Math-Magic Solutions for Class-5, Chapter-8: Mapping Your Way

Question 1 : Look at the shape of the yellow area. Have you seen this shape before? How many sides does it have? This place is called the Central Hexagon. Find out from the map:
1) If you are walking on Rajpath then after India Gate on which side would the Children’s Park be?
2) Which of these roads make the biggest angle between them?
a) Man Singh Road and Shahjahan Road
b) Ashoka Road and Man Singh Road (the angle away from India Gate)
c) Janpath and Rajpath
3) Which of the above pairs of roads cut at right angles?

Answer : The shape in the yellow shade is a polygon with six sides, it is called a hexagon.
1) When crossing the India Gate on Rajpath, the Children's Park will be on the right side.
2) Observe the angles formed by the Man Singh Road and Shahjahan Road and Ashoka Road and Man Singh Road. The angle formed by Ashoka Road and Man Singh Road is the greatest.
3) Janpath and Rajpath are at right angles.

Question 2 : The children look at this map to see the parade route.
1) Trace the route of the parade in Map 3 and mark India Gate and Rajpath.
2) Look at the map carefully and find out:
a) Which of these is the longest road?
• B.S. Zafar Marg • Subhash Marg • Tilak Marg
b) If Rubia is coming from Jama Masjid to join the parade, guess about how far she will have to walk.
c) The total route of the parade is about how long?
• 3 km • 16 km • 25 km • 8 km

Answer :
1) The route is traced below:

2)
a) Measure the routes in the given map. 2 cm = 1 km.
Subhash Marg is the longest of the three roads.
b) Jama Masjid is 1 cm away on the map from Subhash Marg.
On the given map 2 cm = 1 km.
So, 1 cm = 500 metres
Therefore, she will have to walk about 500 metres to join the parade.
c) The parade's total distance on the map is 16 cm.
Since 2 cm = 1 km on the map, the parade’s total route is about 8 km.

Question 3 : Find out from Map 4
a) Which of these is nearer to River Yamuna? the Diwan-e-Aam or the Diwan-e-Khaas?
b) Between which two buildings is Aaram Gah? c) Which buildings do you pass while going from Rang Mahal to the Hammam?
d) Which building on this map is farthest from Meena Bazar?
e) About how far is Lahori Gate from Diwan-e-Khaas?

Answer : a) Observe the given map. The Diwan-e-Khas is closer to the Yamuna River than the Diwan-e-Aam.
b) Observe the given map. The Aaram Gah is between Diwan-e- Khas and Rang Mahal.
c) On the way from Rang Mahal to Hammam, there are Aram Gah and Diwan-e-Khas.
d) Meena Bazar is the farthest from Hammam.
e) Measure the distance between Lahori Gate and Diwan-e-Khas, Lahori Gate is about 6 cm away from Diwan-e-Khas on the map. Since 1cm = 100 m on the map, the distance between Lahori Gate and Diwan-e-Khas is 6 × 100 = 600 metres.

Question 4 : The side of the square was made two times bigger. Does its area also become two times bigger?

Answer : The original length of the square's side is 1 cm. The area of a square of side 1 cm is:
1 × 1 = 1 square cm.
When the side of the square is doubled, the new length of the side will be 2 cm.
Area of the new square = 2 × 2 = 4 square cm.
Therefore, if the size of the grid is doubled, the areas of the pictures will be four times bigger.

Question 5 : This is a part of the parade-route Map 3.

1) Can you see which part of the route-map it is? 2) Now try to make it bigger in this 2 cm grid. Remember that the ‘shape’ of the map should not change.

3) If the parade route map is smaller, and the distance between India Gate and Vijay Chowk becomes 2 cm, what would be its scale?
• 1 cm on map = 1 km on ground
• 12cm on map = 1 km on ground
• 2 cm on map = 1 km on ground

Answer :
1) Observe the parade-route Map 3 and compare it to the given part of the map. The part is marked in Map 3 as shown below.
2) The correct answer is:

3) On map 3, the distance between Vijay Chowk and India gate was originally 4 cm, and the scale was 2 cm = 1 km.
If the distance reduces to 2 cm on the map, that is half of the original distance, the scale will also be half of the original scale. That is
1 cm on the map = 1 km on the ground.

Question 6 : 1) Nonu lives in Gujarat. Nonu’s friend Javed lives in West Bengal.
Nonu wants to visit his friend. In which direction will he travel?
a) Towards west b) Towards east
c) Towards south d) Towards north
2) If 1 cm on the map shows 200 km on the ground, use this scale to find out:
A) About how far is Delhi from Jaipur?
a) 50 km b) 500 km c) 250 km
B) Estimate, how far is Jaipur from Bhopal?
On the map = _______ cm. On the ground = _______ km.

3) Look at the map and tell:
a) Which state is surrounded by four other states?
b) Which state has the largest area? If its name is not in the map, find it from your teacher or parents. Explain how you got your answer.
c) Which state is about 8 times bigger in area than Sikkim?
• Uttar Pradesh • Tripura • Maharashtra
• Himachal Pradesh
d) About how many times of Punjab is the area of Rajasthan?

Answer : 1) Observe the given map. West Bengal is towards the east of Gujarat. Therefore, the correct answer is option b).
2)
A) Using a ruler, measure the distance between Delhi and Jaipur in cm. Since the scale of the map is 1 cm = 200 km, multiply the measured distance by 200 to find the actual distance on the ground in km.
The distance between Delhi and Jaipur is about 250 kilometres on the ground. Therefore, the correct answer is the option c).
B) Using a ruler, measure the distance between Bhopal and Jaipur in cm. Since the scale of the map is 1 cm = 200 km, multiply the measured distance by 200 to find the actual distance on the ground in km. The correct answer is:
The distance between Jaipur and Bhopal on the map is 2.4 cm.
The distance between Jaipur and Bhopal on the ground is 480 km.
3)
a) Himachal Pradesh shares its borders with four states.
b) Do it by yourself with the help of your teacher or parents.
Rajasthan is the state with the largest area.
c) Himachal Pradesh is eight times the size of Sikkim in terms of land area.
d) Rajasthan is ten times the size of Punjab in terms of land area.

Question 7 : Bala is standing on the sea-coast and looking at the vast sea. The sea looks endless.
Have you seen the sea? In the picture where is the sea? Now look for the sea in the map of India. What colour is used to show the sea?
• Mark those states which have the sea on one side.
• Name one state which does not have the sea on any side.

Answer : Do it by yourself. The sea is in front of Bala. On the map, the sea is shown in blue.
Gujarat, Maharashtra, Goa, Kerala, Tamil Nadu, Andhra Pradesh, Karnataka, West Bengal, and Orissa are the states that share their borders with a sea.
There are many states that do not have a sea on any side. One of them is Haryana.

Question 8 : These are five towns. Find out: 1) How many cm away is Idlipur from Barfinagar on the map? 2) How many kilometres will you have to travel if you go from Idlipur to Barfinagar? 3) There is a place called Thukpagram midway between Idlipur and Barfinagar. Mark it with a ‘T’. 4) A town called Jalebipur is 35 kms away from both Chholaghat and Dhoklabad. Where do you think it can be? Mark ‘J’ for it. 5) Measure the length of the route between Bhelpur and Chholaghat. (You can use a thread)

Answer : 1) Measure the distance between Idlipur and Barfinagar using a ruler. On the map, the distance between Idlipur and Barfinagar is 5 cm.
2) Since 1 cm on the map is 10 km on the ground, to find the distance between Idlipur and Barfinagar on the ground, multiply 5 by 10.
5 × 10 = 50
Therefore, the distance between Idlipur and Barfinagar is 10 km. 3) In the following map, Thukpagram is marked with T.

4) Since the scale is 1 cm = 10 km, 35 km on the ground means 3.5 cm on the map. In the following map, Jalebipur is marked with J, which is 3.5 cm away from both Chholaghat and Dhoklabad.

5) Do it by yourself. Using a thread measure the distance between Bhelpur and Chholaghat. It is about 6 cm.
The scale is 1 cm = 10 km. Therefore,
6 cm = 60 km.
Hence, the distance between Bhelpur and Chholaghat is about 60 kilometres.

Question 9 : Ashi’s school looks like this from the top. Use the squares to find out:
1) How many times bigger is the area of the assembly ground than that of the office?
2) How much is the length and width of each classroom?
a) length 5 m, width 4 m b) length 2 m, width 1 m
c) length 12 m, width 10 m d) length 5 m, width 5 m

Answer : 1) Observe the given image. The assembly ground covers 15 squares. The office covers 3 squares. Since 15 is 5 times 3, the area of the assembly ground is 5 times bigger than the area of the office.
2) Measure the length of each classroom in the given image. Each classroom is 2 cm long and 1.6 cm wide.
Since the scale is 2 cm = 5 m,
Length of the classroom = 5m
Breadth of the classroom = 2.5 × 1.6 = 4 m

Question 10 : All the classrooms in Ashi’s school look like this.

Look carefully and answer.
a) Which of these is exactly opposite to the blackboard?
• Almirah, windows, notice board, display board
b) Now look at the school-map again. Guess and mark where would these be:
Blackboard in III A and VII, almirah in IV and X, notice board in V and VI B, last seat of middle-row in II, and display board in I
c) Can a child sitting in III A see the playground?

Answer : a) Display board is exactly opposite to the blackboard.
b) Blackboard in III A and VII, almirah in IV and X, notice board in V and VI B, last seat of middle-row in II, and display board in I are marked in the picture shown below.

c) A child seated in III A will not be able to see the playground.