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Math-Magic Solutions for Class-5, Chapter-8: Mapping Your Way

The chapter Mapping Your Way focuses on dealing with the visualisation and creation of maps. It helps the students understand the plain and elevation in order to be able to make maps.

It covers the topics:

Making maps |
Plain |

Elevation |
Visualization of a given space |

Making maps |

Plain |

Elevation |

Visualization of a given space |

NCERT Math-Magic questions are answered in a simple and engaging manner. We have also related 'Learning Concepts and interactive worksheets with the solutions. Our 'Learning Beyond' segment caters to all the probable questions that a child might think out of curiosity.

Download Chapter 8 Mapping Your Way in PDF format for free here.

**Chapter 8: Mapping Your Way **

**Question 1 : **
Look at the shape of the yellow area. Have you seen this shape
before? How many sides does it have? This place is called the Central
Hexagon. Find out from the map:

1) If you are walking on Rajpath then after India Gate on which side
would the Children’s Park be?

2) Which of these roads make the biggest angle between them?

a) Man Singh Road and Shahjahan Road

b) Ashoka Road and Man Singh Road (the angle away from India
Gate)

c) Janpath and Rajpath

3) Which of the above pairs of roads cut at right angles?

**Answer : **The shape in the yellow shade is a polygon with six sides, it is
called
a hexagon.

1) When crossing the India Gate on Rajpath, the Children's Park will
be on the right side.

2) Observe the angles formed by the Man Singh Road and Shahjahan
Road and Ashoka Road and Man Singh Road. The angle formed by
Ashoka Road and Man Singh Road is the greatest.

3) Janpath and Rajpath are at right angles.

**Question 2 : **The children look at this map to see the parade route.

1) Trace the route of the parade in Map 3 and mark India Gate
and Rajpath.

2) Look at the map carefully and find out:

a) Which of these is the longest road?

• B.S. Zafar Marg • Subhash Marg • Tilak Marg

b) If Rubia is coming from Jama Masjid to join the parade, guess
about how far she will have to walk.

c) The total route of the parade is about how long?

• 3 km • 16 km • 25 km • 8 km

**Answer : **

1) The route is traced below:

2)

a) Measure the routes in the given map. 2 cm = 1 km.

Subhash Marg is the longest of the three roads.

b) Jama Masjid is 1 cm away on the map from Subhash Marg.

On the given map 2 cm = 1 km.

So, 1 cm = 500 metres

Therefore, she will have to walk about 500 metres to join the
parade.

c) The parade's total distance on the map is 16 cm.

Since 2 cm = 1 km on the map, the parade’s total route is about
8 km.

**Question 3 : **Find out from Map 4

a) Which of these is nearer to River Yamuna?
the Diwan-e-Aam or the Diwan-e-Khaas?

b) Between which two buildings is Aaram Gah?
c) Which buildings do you pass while going from Rang Mahal to the
Hammam?

d) Which building on this map is farthest from Meena Bazar?

e) About how far is Lahori Gate from Diwan-e-Khaas?

**Answer : **a) Observe the given map. The Diwan-e-Khas is closer to the
Yamuna River than the Diwan-e-Aam.

b) Observe the given map. The Aaram Gah is between Diwan-e-
Khas and Rang Mahal.

c) On the way from Rang Mahal to Hammam, there are Aram Gah
and Diwan-e-Khas.

d) Meena Bazar is the farthest from Hammam.

e) Measure the distance between Lahori Gate and Diwan-e-Khas,
Lahori Gate is about 6 cm away from Diwan-e-Khas on the map.
Since 1cm = 100 m on the map, the distance between Lahori Gate
and Diwan-e-Khas is 6 × 100 = 600 metres.

**Question 4 : **The side of the square was made two times bigger. Does its area
also become two times bigger?

**Answer : **The original length of the square's side is 1 cm. The area of a square
of side 1 cm is:

1 × 1 = 1 square cm.

When the side of the square is doubled, the new length of the side will
be 2 cm.

Area of the new square = 2 × 2 = 4 square cm.

Therefore, if the size of the grid is doubled, the areas of the pictures
will be four times bigger.

**Question 5 : **This is a part of the parade-route Map 3.

1) Can you see which part of the route-map it is?
2) Now try to make it bigger in this 2 cm grid. Remember that the
‘shape’ of the map should not change.

3) If the parade route map is smaller, and the distance between India
Gate and Vijay Chowk becomes 2 cm, what would be its scale?

• 1 cm on map = 1 km on ground

• 12cm on map = 1 km on ground

• 2 cm on map = 1 km on ground

**Answer : **

1) Observe the parade-route Map 3 and compare it to the given part of
the map. The part is marked in Map 3 as shown below.

2) The correct answer is:

3) On map 3, the distance between Vijay Chowk and India gate was
originally 4 cm, and the scale was 2 cm = 1 km.

If the distance reduces to 2 cm on the map, that is half of the original
distance, the scale will also be half of the original scale. That is

1 cm on the map = 1 km on the ground.

**Question 6 : **1) Nonu lives in Gujarat. Nonu’s friend
Javed lives in West Bengal.

Nonu wants to visit his friend. In which direction will he travel?

a) Towards west b) Towards east

c) Towards south d) Towards north

2) If 1 cm on the map shows 200 km on the ground, use this scale to
find out:

A) About how far is Delhi from Jaipur?

a) 50 km b) 500 km c) 250 km

B) Estimate, how far is Jaipur from Bhopal?

On the map = _______ cm. On the ground = _______ km.

3) Look at the map and tell:

a) Which state is surrounded by four other states?

b) Which state has the largest area? If its name is not in the map, find
it from your teacher or parents. Explain how you got your answer.

c) Which state is about 8 times bigger in area than Sikkim?

• Uttar Pradesh • Tripura • Maharashtra

• Himachal Pradesh

d) About how many times of Punjab is the area of Rajasthan?

**Answer : **1) Observe the given map. West Bengal is towards the east of Gujarat.
Therefore, the correct answer is option b).

2)

A) Using a ruler, measure the distance between Delhi and Jaipur in
cm. Since the scale of the map is 1 cm = 200 km, multiply the
measured distance by 200 to find the actual distance on the ground in
km.

The distance between Delhi and Jaipur is about 250 kilometres on the
ground. Therefore, the correct answer is the option c).

B) Using a ruler, measure the distance between Bhopal and Jaipur in
cm. Since the scale of the map is 1 cm = 200 km, multiply the
measured distance by 200 to find the actual distance on the ground in
km. The correct answer is:

The distance between Jaipur and Bhopal on the map is 2.4 cm.

The distance between Jaipur and Bhopal on the ground is 480 km.

3)

a) Himachal Pradesh shares its borders with four states.

b) Do it by yourself with the help of your teacher or parents.

Rajasthan is the state with the largest area.

c) Himachal Pradesh is eight times the size of Sikkim in terms of land
area.

d) Rajasthan is ten times the size of Punjab in terms of land area.

**Question 7 : **Bala is standing on the sea-coast and looking at the vast sea. The
sea looks endless.

Have you seen the sea? In the picture where is the sea? Now look
for the sea in the map of India. What colour is used to show the
sea?

• Mark those states which have the sea on one side.

• Name one state which does not have the sea on any side.

**Answer : **Do it by yourself. The sea is in front of Bala. On the map, the sea is
shown in blue.

Gujarat, Maharashtra, Goa, Kerala, Tamil Nadu, Andhra Pradesh,
Karnataka, West Bengal, and Orissa are the states that share their
borders with a sea.

There are many states that do not have a sea on any side. One of them
is Haryana.

**Question 8 : **These are five towns. Find out:
1) How many cm away is Idlipur from Barfinagar on the map?
2) How many kilometres will you have to travel if you go from
Idlipur to Barfinagar?
3) There is a place called Thukpagram midway between Idlipur and
Barfinagar. Mark it with a ‘T’.
4) A town called Jalebipur is 35 kms away from both Chholaghat and
Dhoklabad. Where do you think it can be? Mark ‘J’ for it.
5) Measure the length of the route between Bhelpur and Chholaghat.
(You can use a thread)

**Answer : **1) Measure the distance between Idlipur and Barfinagar using a ruler.
On the map, the distance between Idlipur and Barfinagar is 5 cm.

2) Since 1 cm on the map is 10 km on the ground, to find the distance
between Idlipur and Barfinagar on the ground, multiply 5 by 10.

5 × 10 = 50

Therefore, the distance between Idlipur and Barfinagar is 10 km.
3) In the following map, Thukpagram is marked with T.

4) Since the scale is 1 cm = 10 km, 35 km on the ground means 3.5
cm on the map. In the following map, Jalebipur is marked with J,
which is 3.5 cm away from both Chholaghat and Dhoklabad.

5) Do it by yourself. Using a thread measure the distance between
Bhelpur and Chholaghat. It is about 6 cm.

The scale is 1 cm = 10 km. Therefore,

6 cm = 60 km.

Hence, the distance between Bhelpur and Chholaghat is about 60
kilometres.

**Question 9 : **Ashi’s school looks like this from the top. Use the squares to
find out:

1) How many times bigger is the area of the assembly ground than
that of the office?

2) How much is the length and width of each classroom?

a) length 5 m, width 4 m b) length 2 m, width 1 m

c) length 12 m, width 10 m d) length 5 m, width 5 m

**Answer : **1) Observe the given image. The assembly ground covers 15 squares.
The office covers 3 squares. Since 15 is 5 times 3, the area of the
assembly ground is 5 times bigger than the area of the office.

2) Measure the length of each classroom in the given image. Each
classroom is 2 cm long and 1.6 cm wide.

Since the scale is 2 cm = 5 m,

Length of the classroom = 5m

Breadth of the classroom = 2.5 × 1.6 = 4 m

**Question 10 : ** All the classrooms in Ashi’s school look like this.

Look carefully and answer.

a) Which of these is exactly opposite to the blackboard?

• Almirah, windows, notice board, display board

b) Now look at the school-map again. Guess and mark where
would these be:

Blackboard in III A and VII, almirah in IV and X, notice board in
V and VI B, last seat of middle-row in II, and display board in I

c) Can a child sitting in III A see the playground?

**Answer : **a) Display board is exactly opposite to the blackboard.

b) Blackboard in III A and VII, almirah in IV and X, notice board
in V and VI B, last seat of middle-row in II, and display board in
I are marked in the picture shown below.

c) A child seated in III A will not be able to see the playground.