Mayan Calender - Orchids
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Mayan Calendar

The Mayan calendar is a combination of three separate calendars. Here students know about the types of calendars used in the Mayan calendar. Also, the content connects students with the mathematical concept calendar, the addition of two numbers, and subtracting numbers.

Mayan Calendar Definition:

The Mayan calendar applied in pre-Columbian Mesoamerica. We know about different calendar systems. The Mayan calendar is one of them. It is used to track longer periods.

In the Maya calendar, each date is repeated every 18,980 days, which is equal to 52 solar years approximately.

Mayan calendar

Types of Calendars in Mayan Calendar:

In the Mayan calendar, three calendars, Tzolkin, Haab, and Long count used together to count dates.
The Haab is used by the Mayan civilization, which is a civil calendar. Also, it has 365 days.
The Tzolkin calendar is used to calculate the date of religious days, wedding dates, ceremonial events, etc.

Some units are present in this Calendar which connects with days

Mayan calendar

Mayan Calendar Days:


Long Count unit Long count period Days
1 k'in 1
1 Winal 20k'in 20
1 Tun 18 Winal 360
1 k'atun 20 Tun 7200
1 B'ak'tun 20 k'atun 144,000
1 Piktun 20 B'ak'tun 2,880,000
1 Kalabtun 20 Piktun 57,600,000
1 K'inchiltun 20 kalabtun 1,152,000,000

Calendar Questions:

Question 1

Choose the Correct Option for the Following:

  1. What Is the Day’s Difference Between 1Tun and an Ordinary Year?

  2. i) 7 Days

    ii) 6 Days


    iii) 5 Days

    iv) 8 Days


  3. What Is the Day’s Difference Between 1Tun and a Leap Year?

  4. i) 7 Days

    ii) 6 Days


    iii) 5 Days

    iv) 8 Days


Answer:

a) a)We know 1 Tun = 360 days.
In an ordinary year, we have 365 days.
So, the difference is
= (365 – 360) days
= 5 days.

Then,
What is the day’s difference between 1Tun and an ordinary year?

i) 7 Days

ii) 6 Days


iii) 5 Days

tick-mark

iv) 8 Days


The correct option is option iii) 5 days.


b) We know 1 Tun = 360 days.

In an ordinary year, we have 366 days.
So, the difference between the day
= (366 – 360) days
= 6 days.

Then,
What is the day’s difference between 1Tun and a leap year?

i) 7 Days

ii) 6 Days

tick-mark


iii) 5 Days

iv) 8 Days

Question 2:

Choose the Correct Answer:
Rabi Goes to School on Republic Day to Celebrate the Day.
How Many Days Are There in the Month of Republic Day?

i) 1 Tun

ii) 31 K’in

iii) 35 K’in

iv) 1 Winal

Answer:

Rabi knew Republic Day in January month.
January = 31 days = 31 K’in
Hence, the correct option is option ii) 31 K’in

Addition of Two Numbers:

Question 3:

Fill In the Blank of the Given Question:

  1. Number of Days in July = _________K’in.
  2. Number of Days in June = ____________Winal + _________ K’in
  3. Number of Days in February (Leap Year) = _________ K’in.
  4. Number of Days in February (Non-Leap Year) = ____________Winal + _________ K’in.

Answer:

  1. Number of days in July =  31   K’in.
  2. 1 Winal = 20days.
  3. So, 30 days = 20 days + 10 days
    The number of days in June =  1  Winal +   10   K’in

  4. Number of days in February (leap year) =  29   K’in.
  5. d)1 winal = 20days.
    So, 29 days = 20 days + 9 days
    Number of days in February (non-leap year)
    =  1  Winal +  9  K’in.

Subtracting Numbers:

Question 4:

Calendar

Observe the Given Calendar Properly and Answer the Following Question:

  1. What Day of the Week Will Be It After Subtracting 1 Winal From 12/31/2009?
  2. What Day of the Week Will Be After Subtracting 9 K’in from 12/30/2009?
  3. What Day of the Week Will Be After Subtracting 2 K’in from 12/13/2009?

Answer:

  1. We know 1 Winal = 20 day
    Now, if we subtract 20 days from 31, we get 11
    31 – 20 = 11
    So, the date is 12/11/2009
    The required day is Friday.

  2. We know 9 K’in = 9 days
    Now, if we subtract 9 days from 30, we get 21
    30 – 9 = 21
    So, the date is 12/21/2009

  3. We know that 2 K’in = 2 days
    Now, if we subtract 2 days from 13, we get 11
    13 – 2 = 11
    So, the date is 12/11/2009
    The required day is Friday.
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