Mayan Calendar
The Mayan calendar is a combination of three separate calendars. Here students know about the types of calendars used in the Mayan calendar. Also, the content connects students with the mathematical concept calendar, the addition of two numbers, and subtracting numbers.
Mayan Calendar Definition:
The Mayan calendar applied in pre-Columbian Mesoamerica. We know about different calendar systems. The Mayan calendar is one of them. It is used to track longer periods.
In the Maya calendar, each date is repeated every 18,980 days, which is equal to 52 solar years approximately.
Types of Calendars in Mayan Calendar:
In the Mayan calendar, three calendars, Tzolkin, Haab, and Long count used together to count
dates.
The Haab is used by the Mayan civilization, which is a civil calendar. Also, it has 365 days.
The Tzolkin calendar is used to calculate the date of religious days, wedding dates, ceremonial
events,
etc.
Some units are present in this Calendar which connects with days
Mayan Calendar Days:
| Long Count unit | Long count period | Days |
|---|---|---|
| 1 k'in | 1 | |
| 1 Winal | 20k'in | 20 |
| 1 Tun | 18 Winal | 360 |
| 1 k'atun | 20 Tun | 7200 |
| 1 B'ak'tun | 20 k'atun | 144,000 |
| 1 Piktun | 20 B'ak'tun | 2,880,000 |
| 1 Kalabtun | 20 Piktun | 57,600,000 |
| 1 K'inchiltun | 20 kalabtun | 1,152,000,000 |
Calendar Questions:
Question 1
Choose the Correct Option for the Following:
- What Is the Day’s Difference Between 1Tun and an Ordinary Year?
- What Is the Day’s Difference Between 1Tun and a Leap Year?
i) 7 Days
ii) 6 Days
iii) 5 Days
iv) 8 Days
i) 7 Days
ii) 6 Days
iii) 5 Days
iv) 8 Days
Answer:
a) a)We know 1 Tun = 360 days.
In an ordinary year, we have 365 days.
So, the difference is
= (365 – 360) days
= 5 days.
Then,
What is the day’s difference between 1Tun and an ordinary year?
i) 7 Days
ii) 6 Days
iii) 5 Days
iv) 8 Days
The correct option is option iii) 5 days.
b) We know 1 Tun = 360 days.
In an ordinary year, we have 366 days.
So, the difference between the day
= (366 – 360) days
= 6 days.
Then,
What is the day’s difference between 1Tun and a leap year?
i) 7 Days
ii) 6 Days
iii) 5 Days
iv) 8 Days
Question 2:
Choose the Correct Answer:
Rabi Goes to School on Republic Day to Celebrate the Day.
How Many Days Are There in the Month of Republic Day?
i) 1 Tun
ii) 31 K’in
iii) 35 K’in
iv) 1 Winal
Answer:
Rabi knew Republic Day in January month.
January = 31 days = 31 K’in
Hence, the correct option is option ii) 31 K’in
Addition of Two Numbers:
Question 3:
Fill In the Blank of the Given Question:
- Number of Days in July = _________K’in.
- Number of Days in June = ____________Winal + _________ K’in
- Number of Days in February (Leap Year) = _________ K’in.
- Number of Days in February (Non-Leap Year) = ____________Winal + _________ K’in.
Answer:
- Number of days in July = 31 K’in.
- 1 Winal = 20days.
- Number of days in February (leap year) = 29 K’in.
- d)1 winal = 20days.
So, 29 days = 20 days + 9 days
Number of days in February (non-leap year)
= 1 Winal + 9 K’in.
So, 30 days = 20 days + 10 days
The number of days in June = 1 Winal + 10 K’in
Subtracting Numbers:
Question 4:
Observe the Given Calendar Properly and Answer the Following Question:
- What Day of the Week Will Be It After Subtracting 1 Winal From 12/31/2009?
- What Day of the Week Will Be After Subtracting 9 K’in from 12/30/2009?
- What Day of the Week Will Be After Subtracting 2 K’in from 12/13/2009?
Answer:
- We know 1 Winal = 20 day
Now, if we subtract 20 days from 31, we get 11
31 – 20 = 11
So, the date is 12/11/2009
The required day is Friday. - We know 9 K’in = 9 days
Now, if we subtract 9 days from 30, we get 21
30 – 9 = 21
So, the date is 12/21/2009 - We know that 2 K’in = 2 days
Now, if we subtract 2 days from 13, we get 11
13 – 2 = 11
So, the date is 12/11/2009
The required day is Friday.