NCERT solutions for class 8 maths chapter 10 Visualizing Solid Shapes
In this article, we offer valuable assistance to Class 8 students studying Visualising Solid Shapes with our comprehensive NCERT Solutions for Chapter 10 of Maths. Tailored to the latest CBSE syllabus, these solutions provide detailed explanations for all questions found in the NCERT textbooks. Recognizing the significance of NCERT Solutions as a vital educational resource, our materials aim to aid students in their exam preparations, ensuring a thorough understanding of the subject matter.
Exercise 10.1
For each of the given solids, two views are given. Match for each solid the corresponding top and front views. The first one is done for you.
(a) (iii) (iv)
(b) (i) (v)
(c) (iv) (ii)
(d) (v) (iii)
(e) (ii) (i)
For each of the given solids, the three views are given. Identify for each solid the corresponding top, front and side views.
(a) (i) Front (ii) Side (iii) Top view
(b) (i) Side (ii) Front (iii) Top view
(c) (i) Front (ii) Side (iii) Top view
(d) (i) Front (ii) Side (iii) Top view
For each given solid, identify the top view, front view and side view.
(a) (i) Top view (ii) Front view (iii) Side view
(b) (i) Side view (ii) Front view (iii) Top view
(c) (i) Top view (ii) Side view (iii) Front view
(d) (i) Side view (ii) Front View (iii) Top view
(e) (i) Front view (ii) Top view (iii) Side view
Draw the front view, side view and top view of the given objects:
Exercise 10.2
Look at the given map of a city.
Answer the following:
Colour the map as follows: Blue – water, red – fire station, orange – library, yellow – schools, green – park, pink – college, purple – hospital, brown – cemetery.
(a) Mark a green ‘X’ at the intersection of Road C and Nehru Road, Green ‘Y’ at the intersection of Gandhi Road and Road A.
(b) In red, draw a short street route from the library to the bus depot.
(c) Which is the further east, the city park or the market?
(d) Which is further south, the Primary School or the Sr. Secondary School?
(a)
(b)
(c) City Park
(d) Sr. Secondary School
Draw a map of your school compound using proper scale and symbols for various features like a playground, main building, garden etc.
Do it yourself
Draw a map giving instructions to your friend so that she reaches your house without any difficulty.
Do it yourself
Draw a map of your classroom using proper scales and symbols for different objects.
It can be anything. For your reference, we have shared one classroom picture:
Exercise 10.3
Can a polyhedron have for its faces:
(i) 3 Triangles?
(ii) 4 triangles?
(iii) A square and four triangles?
(i) No, such polyhedrons are not possible. A polyhedron should have a minimum of 4 faces.
(ii) Yes, a triangular pyramid has 4 triangular faces.
(iii) Yes, as a square pyramid has a square face and 4 triangular faces.
Is it possible to have a polyhedron with any given number of faces? (Hint: Think of a pyramid)
It is possible only if the number of faces is greater than or equal to 4.
Which are prisms among the following:
(i) A nail: It is not a prism.
(ii) Unsharpened pencil: It is a prism.
(iii) A table weight: It is not a prism.
(iv) A box: It is a prism.
(i) How are prisms and cylinders alike?
(ii) How are pyramids and cones alike?
(i) A cylinder can look like a circular prism, a prism with a circular base.
(ii) A cone can be a circular pyramid, a pyramid with a circular base.
Is a square prism the same as a cube? Explain.
Yes, a square prism can also be a cube. A square prism has a square as its base. However, its height is not necessarily the same as the side of the square. Thus, a square prism can also be a cuboid.
Verify Euler’s formula for the given solids.
(i) Number of faces, F = 7
Number of edges, E = 15
Number of vertices, V = 10
As per formula, F + V – E = 2
Substitute the values, we have
F + V – E = 7 + 10 – 15
= 2
Hence, verified.
(ii) Here, F = 9, V = 9 and E = 16
Using formula, F+ V – E = 2
F + V – E = 9 + 9 – 16 = 2
Hence, Euler’s formula is verified.
Using Euler’s formula, find the unknown:
|
Faces |
? |
5 |
20 |
|
Vertices |
6 |
? |
12 |
|
Edges |
12 |
9 |
? |
Euler’s formula: F + V – E = 2
Where, F = Faces, V = Vertices and E = Edges
(i) F + 6 – 12 = 2
F = 2 + 6
⇒ F = 8
(ii) 5 + V – 9 = 2
V – 4 = 2
⇒ V = 4 + 2
⇒ V = 6
(iii) 20 + 12 – E = 2
32 – E = 2
⇒ E = 32 – 2
⇒ E = 30
Can a polyhedron have 10 faces, 20 edges and 15 vertices?
From the given data, we have
F = 10
E = 20
V = 15
Every polyhedron satisfies Euler’s formula, which is stated as, F + V – E = 2
For the given polygon,
F + V – E = 10 + 15 – 20 = 25 – 20 = 5, which is not equal to 2.
Therefore, a polyhedron cannot have 10 faces, 20 edges and 15 vertices, as Euler’s formula is not satisfied.
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