NCERT Solutions for Maths Class 5 Chapter 3 - How Many Squares?

The chapter How Many Squares? focuses on the areas of geometric shapes by measuring them with square grids and estimating how many squares a shape would cover. It helps the students to understand the the concept of area through the idea of a square as a unit.

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The NCERT Solutions for Maths Class 5 Chapter 3 - How Many Squares? are tailored to help the students master the concepts that are key to success in their classrooms. The solutions given in the PDF are developed by experts and correlate with the CBSE syllabus of 2023-2024. These solutions provide thorough explanations with a step-by-step approach to solving problems. Students can easily get a hold of the subject and learn the basics with a deeper understanding. Additionally, they can practice better, be confident, and perform well in their examinations with the support of this PDF.

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Access Answers to NCERT Solutions for Maths Class 5 Chapter 3 - How Many Squares?

Students can access the NCERT Solutions for Maths Class 5 Chapter 3 - How Many Squares?. Curated by experts according to the CBSE syllabus for 2023–2024, these step-by-step solutions make Maths much easier to understand and learn for the students. These solutions can be used in practice by students to attain skills in solving problems, reinforce important learning objectives, and be well-prepared for tests.

How Many Squares?

Question 1 :

a) Measure the side of the red square on the dotted sheet.
b) Draw here as many rectangles as possible using 12 such squares.
c) How many rectangles could you make?
d) Which of these rectangles has the longest perimeter?
e) Which of these rectangles has the smallest perimeter?

Answer :

a) Measure the side of the shaded square using a ruler. The side of the red square is 1 cm.
b) All possible rectangles using 12 squares are shown below.

c) Count the number of rectangles drawn in the part b), there are 7 rectangles in all.
d) Observe the rectangles drawn in part b). Find the perimeter of each rectangle by counting the number of sides of the small squares along their boundary.
The perimeter of rectangle 1 = 26 cm
The perimeter of rectangle 2 = 26 cm
The perimeter of rectangle 3 = 14 cm
The perimeter of rectangle 4 = 14 cm
The perimeter of rectangle 5 = 14 cm
The perimeter of rectangle 6 = 14 cm
The perimeter of rectangle 7 = 16 cm
Thus, rectangles 1 and 2 have the longest perimeters.
e) Observe the perimeters of the rectangles in part d). Rectangles 3, 4, 5, and 6 have the smallest perimeters.


Question 2 :

a) How many squares of one centimetre side does stamp A cover?.............
And stamp B cover?.....................
b) Which stamp has the biggest area?
How many squares of side 1 cm does this stamp cover?
How much is the area of the biggest stamp?
c) Which two stamps have the same area?
How much is the area of each of these stamps?
d) The area of the smallest stamp is .............square cm.
The difference between the area of the smallest and the biggest stamp is.............square cm.

Answer :

a) Observe the given picture and count the number of small squares covered by the stamp A, and the stamp B.
Stamp A covers 18 squares.
Stamp B covers 8 squares.
b) Observe the given picture, the area of a stamp is the number of small squares covered by that stamp. Therefore,
area of stamp A =18 square cm
area of stamp B = 8 square cm
area of stamp C = 6 square cm
area of stamp D = 12 square cm
area of stamp E = 4 square cm
area of stamp F = 12 square cm
Hence, stamp A has the biggest area. It covers 18 squares of side 1 cm. The area of stamp A is 18 square cm.
c) Observe the areas of stamps in part b). Stamps 'D' and 'F' have the same area, 12 square cm each.
d) From the part b), the area of the smallest stamp is 4 square cm.
This stamp covers 4 squares of side 1 cm.
Since the area of the biggest stamp is 18 square cm, and the area of the smallest stamp is 4 square cm, subtract 4 from 18 to get the difference.
18 – 4 = 14
Therefore, the difference between the area of the smallest and the biggest stamp is 14 squares cm.


Question 3 :

a) Which has the bigger area — one of your footprints or the page of this book?
b) Which has the smaller area—two five-rupee notes together or a hundred rupee note?
c) Look at a 10 rupee-note. Is its area more than hundred square cm?
d) Is the area of the blue shape more than the area of the yellow shape? Why?

e) Is the perimeter of the yellow shape more than the perimeter of the blue shape? Why?

Answer :

a) Do it by yourself.
b) Do it by yourself.
c) Do it by yourself. Put a hundred rupee note on a square grid paper and count the number of squares covered by the note.
d) Observe the given images, the yellow square is divided into two triangles, these triangles are rearranged and made bigger blue triangle. Therefore, the area of the blue shape and the area of the yellow shape are equal.
e) Observe the given images. The triangle’s base is double in length than the length of a side of the square. The other two sides of the triangle are larger than the side of the square. So, the perimeter of the triangle will be more than the sum of the four sides of the square. Therefore, the blue shape has larger perimeter.


Question 4 :

Write the area (in square cm) of the shapes below.

Answer :

To find the area of the given shapes, count the squares covered by them in the following manner.
• If a square is fully covered, count is as 1.
• If a square is more than half covered, count it as 1.
• If a square is exactly half covered, count it as 1/2.
• If a square is less than half covered, count it as 0.

Shape A:
3 full squares ⇒ 3
3 more than half squares ⇒ 3
3 less than half squares ⇒ 0
Area of shape A = 3 + 3 + 0 = 6 square cm.
Shape B:
4 full squares ⇒ 4
8 half squares ⇒ 4
4 less than half squares ⇒ 0
Area of shape B = 4 + 4 = 8 square cm.
Shape C:
2 full squares ⇒ 2
2 more than half squares ⇒ 2
2 less than half squares ⇒ 0
Area of shape C = 2 + 2 + 0 = 4 squares cm.
Shape D:
5 full squares ⇒ 5
2 half squares ⇒1
Area of shape D = 5 + 1 = 6 squares cm.
Shape E:
18 full squares ⇒ 18
6 half squares ⇒ 3
Area of shape E = 18 + 3 = 21 square cm.
Shape F:
4 full squares ⇒ 4
4 more than half squares ⇒ 4
4 less than half squares ⇒ 0
Area of shape F = 4 + 4 + 0 = 8 square cm.


Question 5 :

The blue triangle is half of the big rectangle. Area of the big rectangle is 20 square cm. So the area of the blue triangle is...........square cm.

Answer :

Area of big rectangle = 20 square cm
Since the blue triangle is half of the big rectangle,
area of the blue triangle = (20 ÷ 2) = 10 square cm.


Question 6 :

Ah, in it there are two halves of two different rectangles!
Now you find the area of the two rectangles Sadiq is talking about. What is the area of the red triangle? Explain.

Answer :

Observe the given picture, the orange rectangle has covered 12 squares. Therefore,
area of the orange rectangle = 12 square cm.
The green rectangle has covered 8 squares. Therefore,
Area of the green rectangle = 8 square cm.
Since the triangle has covered half of the orange rectangle and half of the green rectangle, the area of the triangle is
1 /2 (area of the orange rectangle area of thegreen rectangle)
= 1/2 (12+8)=20/2 = 10
So, the area of the triangle is 10 square cm.


Question 7 :

Suruchi drew two sides of a shape. She asked Asif to complete the shape with two more sides, so that its area is 10 square cm.

He completed the shape like this.

Is he correct? Discuss
Explain how the green area is 4 square cm and the yellow area is 6 square cm.

Answer :

Following are the rules to find area by counting the squares.
• If a square is fully covered, count is as 1.
• If a square is more than half covered, count it as 1.
• If a square is exactly half covered, count it as 1/2.
• If a square is less than half covered, count it as 0.
The green area has:
2 full squares ⇒ 2
4 half squares ⇒ 2
Therefore, the green area is 2 + 2 = 4 square cm.
The yellow area has:
3 full squares ⇒ 3
3 more than half squares ⇒ 3
3 less than half squares ⇒ 0
Therefore, the yellow area is 3 + 3 + 0 = 6 square cm.
The total area is 4 + 6 = 10 square cm. Hence, Asif is correct.


Practice Time

Question 1 :

 Here is a rectangle of area 20 square cm.
a) Draw one straight line in this rectangle to divide it into two equal triangles. What is the area of each of the triangles?
b) Draw one straight line in this rectangle to divide it into two equal rectangles. What is the area of each of the smaller rectangles?
c) Draw two straight lines in this rectangle to divide it into one rectangle and two equal triangles.
• What is the area of the rectangle?
• What is the area of each of the triangles?

Answer :

a) Join opposite corners of the rectangle by drawing a straight line.

Since the area of the rectangle is 20 square cm, the area of the tringle is
20/2 = 10 ㎠
b) You can draw a straight line along the length of the rectangle or along its breadth.

Since the area of the big rectangle is 20 square cm, the area of the smaller rectangle is
20/2 = 10 ㎠
d) Draw the two straight lines as shown below.

Since the smaller rectangle is half of the big rectangle, the area of the smaller rectangle is
20/2 = 10 ㎠ Since the triangle is half of the smaller rectangle, the area of the triangle is 10/2 = 5 ㎠.


Question 2 :

This is one of the sides of a shape. Complete the shape so that its area is 4 square cm.

Answer :

Following is the triangle, covered 2 full squares and 4 half squares. So, its area is 2 + 2 = 4 square cm.


Question 3 :

Two sides of a shape are drawn here. Complete the shape by drawing two more sides so that its area is less than 2 square cm.

Answer :

The correct answer is:


Question 4 :

Puzzle with five squares.
a) How many different shapes can you draw?
b) Which shape has the longest perimeter? How much?
c) Which shape has the shortest perimeter? How much?
d) What is the area of the shapes? _______ square cm. That’s simple!

Answer :

a) Do it by yourself. You can draw so many shapes using five squares. A sample answer is given below.