The trajectory of a projectile can be described by the equations of motion. The basic formula for the trajectory of a projectile which is launched at some angle 𝚹 from the ground level with an initial velocity is,
has parametric equations:
1. Horizontal motion
2. Vertical motion
As,
x(t)= Horizontal position at time t
y(t)= Vertical position at time t
G is the gravitational acceleration
t= time in second
The trajectory can be written as one equation (removing \
t), by solving for t from the horizontal motion equation
Substitute this into the vertical motion equation
This is a parabolic equation, and is the trajectory of the projectile.
The maximum height H can be found from
The range R (horizontal distance travelled when it hits the ground) can be found as
It assumes no air resistance and that the launch and landing heights are equal.
Q1: Maximum Height
Known:
Initial velocity,
Launch angle,
Find:
Maximum height reached by the projectile.
Solution
Compute the vertical component of velocity
Applying maximum height formula
Given:
Initial velocity,
Launch angle,
Solution
Range formula
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