# Diagonal of Rectangle Calculator

Diagonal of Rectangle Calculator, a valuable tool for anyone exploring the dimensions of rectangles. Discover how to find the diagonal of a rectangle effortlessly with our user-friendly calculator, designed to simplify your mathematical tasks.

### What is the Diagonal of a Rectangle ?

The diagonal of a rectangle is the line segment connecting opposite corners or vertices. It is longer than the sides and can be calculated using the Pythagorean theorem

### Why Calculate Rectangle Diagonal Calculator?

Calculating the diagonal of a rectangle helps determine the distance between opposite corners, providing a key measurement in geometry and design.

### When to Use Rectangle Diagonal Calculator ?

Use the diagonal length when designing structures, determining diagonal bracing, or ensuring accurate measurements for square footage in construction and architecture.

### How to Calculate Diagonal of a Rectangle?

To calculate the diagonal of a rectangle, use the formula (d = sqrt(l2 + w2) ) or utilize an online calculator for quick and accurate results.

Formula:

The Diagonal of a Rectangle (d) can be calculated using the Pythagorean Theorem:

`d =$\sqrt{\left({l}^{2}\text{+}{w}^{2}\right)}$`

Where

l is the length of rectangle

w is the width of rectangle

### Examples

Example 1:

For a rectangle with length (l = 6) units and width (w = 8) units,

Solution:

Using the formula `d = $\sqrt{\left({l}^{2}\text{+}{w}^{2}\right)}$`

`d = $\sqrt{\left({6}^{2}\text{+}{8}^{2}\right)}$`

`d = $\sqrt{\left({\mathrm{36}}^{}\text{+}{\mathrm{64}}^{}\right)}$`

d = 10 units

Example 2:

For a rectangle with length (l = 10) units and the diagonal is (d = 13) units.

Solution:

Using the formula `w = $\sqrt{\left({d}^{2}\text{-}{l}^{2}\right)}$`

`w = $\sqrt{\left({\mathrm{13}}^{2}\text{-}{\mathrm{10}}^{2}\right)}$`

`w = $\sqrt{\left({\mathrm{169}}^{}\text{-}{\mathrm{100}}^{}\right)}$`

w = 8.30 units

Example 3:

For a rectangle with diagonal is (d = 15) units, and the width is (w = 9) units

Solution:

Using the formula `l = $\sqrt{\left({d}^{2}\text{-}{w}^{2}\right)}$`

`l = $\sqrt{\left({\mathrm{15}}^{2}\text{-}{9}^{2}\right)}$`

`l = $\sqrt{\left({\mathrm{225}}^{}\text{-}{\mathrm{81}}^{}\right)}$`

`l` = 12 units