**1) Write the Name of the Element Whose Atomic Number Is Double the Atomic Number of the Element Chromium (Cr).**

Chromium’s atomic number = 24.

Double of Chromium = 24 × 2

= 48

Therefore, Cadmium (Cd) has the double atomic number of Chromium.

**2) Write the Name of the Element Whose Atomic Number Is Half the Atomic Number of the Element Mercury (Hg).**

Mercury’s atomic number = 80.

Half of Mercury = 80 ÷ 2

= 40

Therefore, Zirconium (Zr) has half of Mercury’s atomic number.

**3) Name Two Elements Such That the Sum of Their Atomic Number Is Equal to the Atomic Number of Copernicium.**

Name Two Elements Such That the Sum of Their Atomic Number Is Equal to the Atomic Number of Copernicium.

**BODMAS Rule**

**4) Solve the Expression 2 × 112 ÷ 4 + 19. Name the Element Whose Atomic Number Is Equal to the Answer Obtained.**

From the BODMAS rule of arithmetic, it follows that to solve the given expression; we will follow the order:

- Divide
- Multiply
- Addition

First, divide 112 by 4.

Second, multiply two by 28

Third, add 56 and 19.

2 × 112 ÷ 4 + 19

= 2 × 28 + 19

= 56 + 19

= 75

The table shows that the element whose atomic number equals 75 is Rhenium (Re).

**5) Solve the Expression 2 × 112 ÷ 4 + 19. Name the Element Whose Atomic Number Is Equal to the Answer Obtained.**

First, divide 75 by 5.

Second, subtract 15 from 112.

Third, add 97 and 10.

112 – 75 ÷ 5 + 10

= 112 – 15 + 10

= 97 + 10

= 107

The table shows that the element whose atomic number equals 107 is Bohrium (Bh).

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