Molar Concentration, or molarity is an amount of substance, or solute in a given volume of solution. It is usually expressed in moles per liter (mol/L). To understand molarity, one of the basic concepts in physics that helps analyze fluids' behavior and chemical reactions.
The formula of molar concentration is,
Where:
C = Molar concentration (mol/L)
n = Number of moles of solute (mol)
V = Volume of solution (L)
Example 1:Determine the molar concentration of NaOH for the reaction between HCl and NaOH.
Solution:
The balanced chemical equation can be written as,
HCl + NaOH → NaCl + H2O
For an acid
n(HCl) = (35.0 / 1000 dm3) × 0.250 mol dm-3
= 8.75 × 10-3mol
The mole ratio NaOH: HCl = 1:1.
The moles of NaOH present is 8.75 × 10-3mol.
Now we have the equation,
Now convert the volume of aqueous NaOH in dm3
25 cm3 = 25 / 1000 dm3
= 25 × 10-3dm3
Thus,
Molar concentration of NaOH = 8.75×10−3 / 25.0×10-3
Molar conc. of NaOH = 0.350 mol dm-3
Example 2: The conc. of Ca(HCO3)2 is 0.85 gmol/L. Express this conc. in geq/L.
Solution:
Given,
[C] = 0.85 gmol/ L
[C]eq = [C][MM] / eq.mass
M = 40.1(2) + 2{1+12+3(16)}
= 202.2
Number of reference species = 2
Therefore, eq.mass = Ca(HCO3)2 / 2
= 202.2 / 2
However,
[C]eq = 0.85[202.2] / 202.2/2
= 1.7 geq/L
Other Related Sections
NCERT Solutions | Sample Papers | CBSE SYLLABUS| Calculators | Converters | Stories For Kids | Poems for kids| Learning Concepts I Practice Worksheets I Formulas | Blogs | Parent Resource
Admissions Open for
Molar Concentration, or molarity is an amount of substance, or solute in a given volume of solution. It is usually expressed in moles per liter (mol/L). To understand molarity, one of the basic concepts in physics that helps analyze fluids' behavior and chemical reactions.
The formula of molar concentration is,
Where:
C = Molar concentration (mol/L)
n = Number of moles of solute (mol)
V = Volume of solution (L)
Example 1:Determine the molar concentration of NaOH for the reaction between HCl and NaOH.
Solution:
The balanced chemical equation can be written as,
HCl + NaOH → NaCl + H2O
For an acid
n(HCl) = (35.0 / 1000 dm3) × 0.250 mol dm-3
= 8.75 × 10-3mol
The mole ratio NaOH: HCl = 1:1.
The moles of NaOH present is 8.75 × 10-3mol.
Now we have the equation,
Now convert the volume of aqueous NaOH in dm3
25 cm3 = 25 / 1000 dm3
= 25 × 10-3dm3
Thus,
Molar concentration of NaOH = 8.75×10−3 / 25.0×10-3
Molar conc. of NaOH = 0.350 mol dm-3
Example 2: The conc. of Ca(HCO3)2 is 0.85 gmol/L. Express this conc. in geq/L.
Solution:
Given,
[C] = 0.85 gmol/ L
[C]eq = [C][MM] / eq.mass
M = 40.1(2) + 2{1+12+3(16)}
= 202.2
Number of reference species = 2
Therefore, eq.mass = Ca(HCO3)2 / 2
= 202.2 / 2
However,
[C]eq = 0.85[202.2] / 202.2/2
= 1.7 geq/L
Other Related Sections
NCERT Solutions | Sample Papers | CBSE SYLLABUS| Calculators | Converters | Stories For Kids | Poems for kids| Learning Concepts I Practice Worksheets I Formulas | Blogs | Parent Resource
List of Physics Formulas |
---|
Admissions Open for
Formula: Ptolemy’s Theorem relates the sides and diagonals of a cyclic quadrilateral. For a cyclic quadrilateral ABCD with diagonals AC and BD, the theorem states:
CBSE Schools In Popular Cities