Specific gravity is a dimensionless number; thus, it has no units and is defined as the ratio of the density of a substance to the reference substance. The reference substance is usually water in the case of liquids and solids, and the reference substance is air in the case of gases.
Specific gravity is a unitless quantity.The density of water is 1000 Kg/m3
Problem 1: If the density of iron is 7850 kg/m3, what is its specific gravity?
Answer:
Given,
Density of iron = 7850 Kg/m3,
Density of water = 1000 Kg/m3
Problem 2: Compute the specific gravity if the density of granite is 174.8 lbs/ft3 and density of water is 62.4 lb/ft3?
Answer:
Given,
Density of granite = 174.8 lbs/ft3
Density of water = 62.4 lbs/ft3
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Specific gravity is a dimensionless number; thus, it has no units and is defined as the ratio of the density of a substance to the reference substance. The reference substance is usually water in the case of liquids and solids, and the reference substance is air in the case of gases.
Specific gravity is a unitless quantity.The density of water is 1000 Kg/m3
Problem 1: If the density of iron is 7850 kg/m3, what is its specific gravity?
Answer:
Given,
Density of iron = 7850 Kg/m3,
Density of water = 1000 Kg/m3
Problem 2: Compute the specific gravity if the density of granite is 174.8 lbs/ft3 and density of water is 62.4 lb/ft3?
Answer:
Given,
Density of granite = 174.8 lbs/ft3
Density of water = 62.4 lbs/ft3
Other Related Sections
NCERT Solutions | Sample Papers | CBSE SYLLABUS| Calculators | Converters | Stories For Kids | Poems for kids| Learning Concepts I Practice Worksheets I Formulas | Blogs | Parent Resource
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Formula: Ptolemy’s Theorem relates the sides and diagonals of a cyclic quadrilateral. For a cyclic quadrilateral ABCD with diagonals AC and BD, the theorem states:
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