Spring force is the force exerted on a spring that is stretched or compressed from its unstretched or uncompressed position. In essence, you compress or stretch a spring which, in turn, will try to regain its original shape and develop a restoring force that opposes the applied force. It is because of this property that springs are ubiquitous in most everyday objects and mechanical systems-from mattresses to toys.
This force, by Hooke's Law, is proportional to the displacement of the spring from its natural length. The expression for spring force is given as:
F = k(x – x0)
Where
xo is the spring force is F
x is equilibrium position displacement of the spring from its position at equilibrium
k is the spring constant
The negative sign indicates that the visualized spring force is a restoring force that acts in the opposite direction.
Problem 1: A spring has length 22 cm/s. If it is loaded with 2 kg, it gets stretched by 38 cm/s. Find its spring constant.
Solution:
(Mass) m = 2 kg
(initial length) xo = 22 cm
(displacement) x = 38 cm
Final displacement = x – xo = 38 cm – 22 cm = 16 cm = 0.16 m
The spring force is articulated as,
F = ma
F = 2 kg × 0.16 m
F = 0.32 N
The spring constant is articulated as,
Hence, the spring constant is -2 N/m.
Problem 2: With force 100 N, if a body is stretched by 2m Calculate its spring constant.
Solution:
Given,
(Displacement) x = 2m
(force) F = 100 N
The spring constant is articulated as,
Hence, the spring constant is -50 N
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Spring force is the force exerted on a spring that is stretched or compressed from its unstretched or uncompressed position. In essence, you compress or stretch a spring which, in turn, will try to regain its original shape and develop a restoring force that opposes the applied force. It is because of this property that springs are ubiquitous in most everyday objects and mechanical systems-from mattresses to toys.
This force, by Hooke's Law, is proportional to the displacement of the spring from its natural length. The expression for spring force is given as:
F = k(x – x0)
Where
xo is the spring force is F
x is equilibrium position displacement of the spring from its position at equilibrium
k is the spring constant
The negative sign indicates that the visualized spring force is a restoring force that acts in the opposite direction.
Problem 1: A spring has length 22 cm/s. If it is loaded with 2 kg, it gets stretched by 38 cm/s. Find its spring constant.
Solution:
(Mass) m = 2 kg
(initial length) xo = 22 cm
(displacement) x = 38 cm
Final displacement = x – xo = 38 cm – 22 cm = 16 cm = 0.16 m
The spring force is articulated as,
F = ma
F = 2 kg × 0.16 m
F = 0.32 N
The spring constant is articulated as,
Hence, the spring constant is -2 N/m.
Problem 2: With force 100 N, if a body is stretched by 2m Calculate its spring constant.
Solution:
Given,
(Displacement) x = 2m
(force) F = 100 N
The spring constant is articulated as,
Hence, the spring constant is -50 N
Other Related Sections
NCERT Solutions | Sample Papers | CBSE SYLLABUS| Calculators | Converters | Stories For Kids | Poems for kids| Learning Concepts I Practice Worksheets I Formulas | Blogs | Parent Resource
List of Physics Formulas |
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Formula: Ptolemy’s Theorem relates the sides and diagonals of a cyclic quadrilateral. For a cyclic quadrilateral ABCD with diagonals AC and BD, the theorem states:
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