Work is defined as a transfer of energy by a force that moves an object. In the analysis of objects in motion, work done upon an object depends on the size of the force, the displacement through which the object travels, and the angle between the force and the displacement.
<h2 dir="ltr">Work Formula</h2>
The work formula mathematically describes work as:
W= F.d
W= F.d.cos &theta;
Where,
<ul>
<li dir="ltr" aria-level="1">
W = Work done in joules, J
</li>
<li dir="ltr" aria-level="1">
F = Magnitude of the force applied in newtons, N
</li>
<li dir="ltr" aria-level="1">
d = displacement of the object in meters
</li>
<li dir="ltr" aria-level="1">
&theta; = Angle between the direction of the force and the direction of displacement
</li>
</ul>
The formula of work is used to find the work done, force, or displacement in any problem. Its unit is expressed in Nm.
<h1 dir="ltr">Work Solved Problems</h1>
Underneath is numerical work which helps out to comprehend the concept better.
Problem 1: Find the work done if 10 N of force acts on the body showing the displacement of 2 m.
Solution:
Given:
F (Force) = 10 N,
d (Displacement) = 2 m,
W (Work done) = F &times; d
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;= 10 N &times; 2 m
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;= 20 Nm.
Problem 2: Find the work done for 2-newton force and 3m displacement. 45&deg; Is the angle given between the force &amp; displacement?
Answer:
Given: Force F = 2 N,
Displacement d = 3 m,
&theta; = 45&deg;
Work done,
W = Fd cos &theta;
= 2N &times; 3m cos 45&deg;
W = 3.51 Nm
&nbsp;
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Work Formula

Understand what is the Work, Learn about the Work Formula in physics, and get the solved examples at Orchids International School.