Factoring polynomials is the reverse process of polynomial multiplication. It involves breaking down a complex polynomial expression into a product of simpler polynomial factors. This technique is an essential concept in algebra and is frequently used in solving equations, simplifying expressions, and analyzing polynomial functions.
Let’s explore what factoring polynomial means, how to factor polynomials using different methods, and go through several factors of polynomials examples.
Table of Contents
Factoring polynomial means expressing the polynomial as a product of two or more simpler polynomials. For example, the polynomial expression:
x² + 5x + 6
Can be factored into:
(x + 2)(x + 3)
After factoring, we can find the roots or zeroes of the polynomial. These are the values of x for which the polynomial becomes zero.
There are several methods of factoring polynomial expressions depending on the number of terms and their form:
Greatest Common Factor (GCF)
Grouping Method
Difference of Squares
Sum or Difference of Cubes
Trinomial Method
Using Algebraic Identities
Let’s explore the most commonly used methods in detail.
To factor a polynomial, the key steps are:
Identify the GCF across all terms
Try grouping terms in pairs
Apply standard algebraic identities
Use trial and error for quadratic trinomials
Apply the Factor Theorem when suitable
You can also use a factoring polynomial calculator to verify your solutions and visualize factorization steps.
The Greatest Common Factor (GCF) is the highest factor that divides all the terms of the polynomial.
Example:
Factor: 3x² + 6x
GCF = 3x
So,
3x² + 6x = 3x(x + 2)
Used for polynomials with 4 or more terms.
Example:
Factor: x² - 15x + 50
Find two numbers whose sum is -15 and product is 50: -5 and -10
Rewrite:
x² - 5x - 10x + 50
Group:
x(x - 5) -10(x - 5)
Result:
(x - 5)(x - 10)
Use these standard identities:
(a + b)² = a² + 2ab + b²
(a - b)² = a² - 2ab + b²
a² - b² = (a + b)(a - b)
Example:
Factor: x² - 121
Use identity a² - b²:
x² - 11² = (x - 11)(x + 11)
A polynomial p(x) has a factor (x - a) if and only if p(a) = 0.
Example:
Check if x + 3 is a factor of x³ + 3x² + 5x + 15
Let x = -3
p(-3) = (-3)³ + 3(-3)² + 5(-3) + 15 = -27 + 27 - 15 + 15 = 0
Since p(-3) = 0, x + 3 is a factor.
Group terms in pairs and factor them individually.
Example:
Factor: x³ + x² - x - 1
Group: (x³ + x²) + (-x - 1)
Factor: x²(x + 1) -1(x + 1)
Final: (x² - 1)(x + 1) = (x - 1)(x + 1)(x + 1)
Example 1:
Factor: x² + 5x + 6
Find two numbers: 2 and 3
x² + 2x + 3x + 6 = x(x + 2) + 3(x + 2) = (x + 2)(x + 3)
Example 2:
Factor using GCF: 4x² - 12x + 8
GCF = 4
4(x² - 3x + 2) = 4(x - 1)(x - 2)
Example 3:
Factor: 16x² + 40xy + 25y²
This is a perfect square trinomial
(4x + 5y)²
Factorise:
(i) 16x² + 40xy + 25y²
(ii) x² – (y – 3)x – 3y
Factorise by splitting the middle term:
(i) 4x² – 12x + 9
(ii) 4x² – 4ax + (a² – b²)
Factorise using Factor Theorem:
z² – 3z – 28
Use a factoring polynomial calculator to cross-check your answers and visualize steps!
Factoring polynomials is a foundational algebraic skill that simplifies complex expressions and helps solve equations efficiently. By breaking down a polynomial into its factors, students can better understand its structure, find its roots, and apply it in real-world scenarios. Whether it’s solving quadratic equations, simplifying algebraic expressions, or preparing for higher-level math, mastering factoring techniques is essential. With regular practice and a clear grasp of methods like common factoring, grouping, and special identities, anyone can confidently tackle polynomial problems with ease.
Related Links :
Polynomial Functions : Break down complex polynomials into simple terms with guided lessons and visuals.
Polynomial : Practice polynomial problems and prepare for board exams with confidence.
Ans.Factoring polynomial is the process of expressing a polynomial as the product of simpler polynomials.
Ans.You can use methods like finding GCF, grouping terms, applying identities, and using the Factor Theorem.
Ans.The major types include:
GCF method
Grouping method
Difference of squares
Sum/difference of cubes
Ans.Find the GCF and factor it out. Example:
x² – x = x(x – 1)
Ans.x² – 7x – 18 = (x – 9)(x + 2) using middle term splitting.
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