Rhombus is a quadrilateral having all sides of equal length. We can use the same triangulation method discussed above to find the area of a rhombus. Consider a rhombus BOAT with diagonals AB and OT. The diagonals of a rhombus are the perpendicular bisectors of each other.
The area of a rhombus is the total flat space enclosed within its four equal sides. In simple terms, if you draw a rhombus on paper and coloured it in, the amount of coloured surface would be its area. It is always measured in square units such as cm², m², or mm².
A rhombus looks like a diamond shape a four-sided figure where all sides are the same length, opposite sides run parallel to each other, and opposite angles are equal. The two diagonals cross each other at right angles inside, and that property is the key to finding its area.
Different formulas to find the area of a rhombus are tabulated below:
| Method | Formula | Description |
|---|---|---|
| Using Diagonals | A = ½ × d₁ × d₂ | Area is half the product of the diagonals |
| Using Base and Height | A = b × h | Area equals base multiplied by height |
| Using Trigonometry | A = b² × sin(a) | Area using side and included angle |
Where,
Consider the following rhombus: ABCD
Let O be the point of intersection of two diagonals AC and BD.
The area of the rhombus will be:
A = 4 × area of ∆ AOB
= 4 × (½) × AO × OB sq. units
= 4 × (½) × (½) d1 × (½) d2 sq. units
= 4 × (1/8) d1 × d2 square units
= ½ × d1 × d2
Therefore, the Area of a Rhombus = A = ½ × d1 × d2
Where d1 and d2 are the diagonals of the rhombus.
There are three methods to calculate the area of a rhombus are explained below with examples.
Both diagonals are given.
Formula: Area = (d1 × d2) ÷ 2
Example: If d1 = 10 cm and d2 = 6 cm
Solution:
Area = (d1 × d2) ÷ 2
= (10 × 6) ÷ 2
= 60 ÷ 2 = 30 cm²
The base (side length) and the perpendicular height are given.
Formula: Area = base × height
Example: If base = 8 cm and height = 5 cm
Solution:
Area = base × height
= 8 × 5 = 40 cm²
The side length and one interior angle are given, but the height is not directly known.
Formula: Area = side² × sin(angle)
Area = base × height = side × (side × sin(angle)) = side² × sin(angle)
Example: If side = 6 cm and angle = 30°
Solution:
Area = side² × sin(angle)
= 6² × sin(30°)
= 36 × 0.5 = 18 cm²
1. Find Area Using Diagonals
The diagonals of a rhombus are 12 cm and 16 cm. Find its area.
Area = (d1 × d2) ÷ 2
= (12 × 16) ÷ 2
= 192 ÷ 2
= 96 cm²
2. Find Area Using Base and Height
A rhombus has a base of 9 cm and a perpendicular height of 7 cm. Find its area.
Area = base × height
= 9 × 7
= 63 cm²
3. Find Area Using Trigonometry
A rhombus has a side length of 10 cm and one interior angle of 60°. Find its area.
Area = side² × sin(angle)
= 10² × sin(60°)
= 100 × (√3/2)
= 100 × 0.866
= 86.6 cm²
4. Find a Diagonal When Area is Given
The area of a rhombus is 60 cm² and one diagonal is 10 cm. Find the other diagonal.
Area = (d1 × d2) ÷ 2
60 = (10 × d2) ÷ 2
60 × 2 = 10 × d2
120 = 10 × d2
d2 = 120 ÷ 10
= 12 cm
5. Find Side When Area and Angle are Given
The area of a rhombus is 50 cm² and one angle is 45°. Find the side length.
Area = side² × sin(angle)
50 = side² × sin(45°)
50 = side² × (1/√2)
50 = side² × 0.707
side² = 50 ÷ 0.707
side² = 70.72
side = √70.72
= 8.41 cm
6. Real-Life Problem
A diamond-shaped tile has diagonals of 8 cm and 6 cm. Find the area of the tile.
Area = (d1 × d2) ÷ 2
= (8 × 6) ÷ 2
= 48 ÷ 2
= 24 cm²
where d1 and d2 are the diagonals.
Multiply the lengths of the diagonals and divide by 2.
Yes, they bisect each other at right angles (90°).
Yes, using base and height:Area=base×height
The unit is always square units such as cm², m², etc.
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