Time and Work is a concept that deals with how long it takes for one person or a group of people to complete a task, and how efficient they are in doing it. These problems study the relationship between three things the number of people working, the time they take, and the total work completed.
What is Time and Work?
Time and Work is a basic concept in mathematics that explains how long a person or a group takes to complete a task. Time and Work shows the connection between work, time, and speed of working.
Time and Work Definition
Time and Work is defined as: The relationship between the total work, the time taken to complete it, and the rate at which the work is done.
Time and Work Formula
M1×D1×T1W1=M2×D2×T2W2
Time and Work Solved Problems
Problem 1: A can complete a work in 12 days. How much work does he complete in 1 day?
Solution:
Step 1: Total work = 1
Step 2: Time = 12 days
Step 3: Work done in 1 day = 1 ÷ 12
Answer: A completes 1/12 of the work in one day.
Problem 2: A can finish a work in 10 days and B can finish the same work in 5 days. How long will they take if they work together?
Solution:
Step 1: A’s one day work = 1/10
B’s one day work = 1/5
Step 2: Total work in one day = 1/10 + 1/5
Convert to same denominator: 1/10 + 2/10 = 3/10
Step 3: Time = 1 ÷ (3/10) = 10/3 days
Answer: They will complete the work in 10/3 days (3⅓ days).
Problem 3: A can complete a work in 15 days. B can complete it in 20 days. How much work do they complete together in 1 day?
Solution:
Step 1: A’s one day work = 1/15
B’s one day work = 1/20
Step 2: Total work in one day = 1/15 + 1/20
LCM = 60
= 4/60 + 3/60 = 7/60
Answer: Together they complete 7/60 of the work in one day
Problem 4: A can complete a work in 8 days. He works for 2 days and then leaves. How much work is left?
Solution:
Step 1: A’s one day work = 1/8
Step 2: Work done in 2 days = 2 × (1/8) = 2/8 = 1/4
Step 3: Remaining work = 1 − 1/4 = 3/4
Answer: 3/4 of the work is left
Problem 5: A and B together can complete a work in 6 days. If A alone can complete it in 10 days, how long will B take alone?
Solution:
Step 1: (A + B)’s one day work = 1/6
A’s one day work = 1/10
Step 2: B’s one day work = 1/6 − 1/10
LCM = 30
= 5/30 − 3/30
= 2/30
= 1/15
Step 3: Time taken by B = 15 days
Answer: B alone will complete the work in 15 days
The basic formula is: Work = Time × Efficiency
Efficiency = Work / Time
Time = Work ÷ Efficiency
If efficiency increases, time decreases.
Efficiency refers to how much work a person can complete in a unit time. Higher efficiency means less time required.
Use the LCM method: Assume total work = LCM of given days to simplify calculations.
Efficiency ∝ 1 / Time
If efficiency doubles, time is halved.
Work = total task completed
Efficiency = speed of completing the work
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