The nth term of an arithmetic progression (AP) is an important concept in mathematics that helps find any term of a sequence without writing all the previous terms. It is based on a constant pattern where each term increases or decreases by a fixed difference. In this guide, you will learn about the nth term of an arithmetic progression, its formulas with easy steps, and examples.
An arithmetic progression (AP) is a sequence of numbers in which the difference between any two consecutive terms is always the same. That fixed difference is called the common difference, written as d.
In general notation, an AP is written as a, a+d, a+2d, a+3d, … where a is the first term and d is the common difference. Both a and d can be positive, negative, or even zero, but d remains constant throughout.
Read more: Important Questions on Arithmetic Progression - Class 10
The nth term of an AP is the term in the nth position in the sequence. It's also called the general term of an AP, and it's usually written as an
Derivation of the nth term of an Arithmetic Progression
Let a1,a2,a3,...be an AP whose first term a1is a and the common difference is d.
The coefficient of d in each term is always one less than the position number.
∴ the general term of an AP is an= a + (n - 1)d
Where 'a' = first term, 'd' = common difference, and 'n' = position of the term
Here are the four steps to follow to find the nth term of an arithmetic progression:
Identify the first term (a).
Find the common difference (d). Subtract the first term from the second: d = a2−a1
Note the value of n (which term you need). For 'find the 15th term', n = 15.
Substitute into an = a + (n − 1)d and simplify.
Example 1: Find the 12th term of the AP: 5, 8, 11, 14, …
Solution: Given: a = 5, d = 8 − 5 = 3, n = 12
an = a + (n − 1)d
a12 = 5 + (12 − 1) × 3
a12 = 5 + 11 × 3 = 5 + 33 = 38
The 12th term of the AP is 38.
Example 2: How many terms are in the AP: 7, 13, 19, 25, ..., 205?
Solution: Given, a = 7, d = 13 − 7 = 6, and an= 205
205 = 7 + (n − 1) × 6
205 − 7 = (n − 1) × 6
198 = (n − 1) × 6
n − 1 = 33
∴n = 34
There are 34 terms in the AP 7, 13, 19, 25, ..., 205
Example 3: Check whether 301 is a term of the AP: 5, 11, 17, 23, …
Solution: Given a = 5, d = 6
Assume 301 = an = 5 + (n − 1) × 6
301 − 5 = (n − 1) × 6
296 = (n − 1) × 6
n − 1 = 296/6 = 49.33… (not an integer)
Since n is the position of the term, it must always be a positive integer. Hence, 301 is not a part of the arithmetic progression.
Example 4: The 4th term of an AP is 0, and the 10th term is −12. Find the AP.
Solution: a4= a + 3d = 0 … (1)
a10 = a + 9d = −12 … (2)
Subtracting (1) from (2):
6d = −12
d = −2
Substituting d = −2 in (1) a + 3(−2) = 0 ⇒ a = 6
a = 6 and d = -2
∴ AP is 6, 4, 2, 0, −2, −4, −6, −8, −10, −12, …
The nth term of an AP is the term at the nth position in the sequence. It is calculated using the formula an = a + (n−1)d, where a is the first term, d is the common difference, and n is the position term.
Yes, if the common difference is negative (d < 0), the AP is decreasing, and its terms will eventually become negative.
Yes. The terms 'nth term', 'general term', and 'general formula of an AP' all refer to the same expression: an = a + (n−1) d.
Set the number equal to a_{n} and solve for n. If n is a positive integer, the number is a term. If n comes out to be a fraction, a negative number, or zero, the number does not belong to that AP.
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