The numbers 1, 2, 3, 4, and 5 seem deceptively simple, but they hide a surprisingly rich world of mathematical arrangements beneath the surface.
This guide walks you through every possible way to combine and arrange these five digits, from quick two-number pairs to full five-digit sequences with clear examples, real-world context, and exact counts.
A combination is about what you pick, not the sequence you pick it in. We're looking at every possible non-empty subset of the numbers {1, 2, 3, 4, 5}.
The total number of non-empty subsets from a set of 5 elements is 2⁵ − 1 = 31.
Here's every single combination organized by group size:
These are the simplest selections: just one number at a time i.e., singletons
{1}, {2}, {3}, {4}, {5}
Every possible pair from the five numbers:
{1,2}, {1,3}, {1,4}, {1,5}, {2,3}, {2,4}, {2,5}, {3,4}, {3,5}, {4,5}
Note: {1,2} and {2,1} are listed only once, because in combinations, they're the same pair.
Every possible trio:
{1,2,3}, {1,2,4}, {1,2,5}, {1,3,4}, {1,3,5}, {1,4,5}, {2,3,4}, {2,3,5}, {2,4,5}, {3,4,5}
Every group of four :
{1,2,3,4}, {1,2,3,5}, {1,2,4,5}, {1,3,4,5}, {2,3,4,5}
There's only one way to select all five numbers at once:
{1, 2, 3, 4, 5}
To arrange all 5 numbers in a sequence, you use the factorial formula:
5! = 5 × 4 × 3 × 2 × 1 = 120
There are exactly 120 unique arrangements of the digits 1, 2, 3, 4, and 5 when each digit is used exactly once.
Here's a quick intuition for why:
You have 5 choices for the first position
Then 4 remaining choices for the second
Then 3 for the third, 2 for the fourth, and only 1 left for the fifth
Multiply them together: 5 × 4 × 3 × 2 × 1 = 120
Below are all 120 full arrangements of 1, 2, 3, 4, 5 (grouped in rows of 10 for readability):
12345 12354 12435 12453 12534 12543 13245 13254 13425 13452
13524 13542 14235 14253 14325 14352 14523 14532 15234 15243
15324 15342 15423 15432 21345 21354 21435 21453 21534 21543
23145 23154 23415 23451 23514 23541 24135 24153 24315 24351
24513 24531 25134 25143 25314 25341 25413 25431 31245 31254
31425 31452 31524 31542 32145 32154 32415 32451 32514 32541
34125 34152 34215 34251 34512 34521 35124 35142 35214 35241
35412 35421 41235 41253 41325 41352 41523 41532 42135 42153
42315 42351 42513 42531 43125 43152 43215 43251 43512 43521
45123 45132 45213 45231 45312 45321 51234 51243 51324 51342
51423 51432 52134 52143 52314 52341 52413 52431 53124 53142
53214 53241 53412 53421 54123 54132 54213 54231 54312 54321
The five numbers 1, 2, 3, 4, and 5 can produce 31 unique combinations (when order doesn't matter) or 120 full permutations (when order does matter). Shorter arrangements using fewer than all five digits add up to 325 ordered sequences in total. Whether you're studying for a math exam, building a probability model, or just solving a puzzle, these numbers and the patterns they create are a perfect starting point for understanding combinatorics in a concrete, hands-on way.
There are 31 non-empty combinations (subsets) if order doesn't matter. If you mean full 5-digit arrangements, the answer is 120.
5! = 5 × 4 × 3 × 2 × 1 = 120. This is the total number of ways to arrange all five digits in a sequence.
From 1, 2, 3, 4, 5 without repeating 60 3-digit numbers can be made. Calculated as P(5,3) = 5 × 4 × 3 = 60.
C(5,2) = 10 (pairs where order doesn't matter), P(5,2) = 20 (ordered pairs where 12 ≠ 21)
No. Combinations ignore order ({1,2,3} = {3,2,1}), while permutations treat different orders as different outcomes (123 ≠ 321).
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