Decimal Expansion of Rationals (Revisited)
In earlier classes, you learned that rational numbers are numbers that can be written in the form p/q, where p and q are integers and q is not equal to zero. You also learned that every rational number has a decimal expansion that is either terminating or non-terminating repeating. In Class 10, we revisit this concept with a deeper understanding. We now explore the conditions under which a rational number has a terminating decimal expansion versus a non-terminating repeating one. This chapter builds on the Fundamental Theorem of Arithmetic and uses prime factorisation of the denominator to determine the nature of the decimal expansion. Understanding this topic is essential for distinguishing between rational and irrational numbers and for working confidently with real numbers in algebra and coordinate geometry.
What is Decimal Expansion of Rational Numbers?
A rational number is any number that can be expressed in the form p/q, where p and q are integers and q is not equal to zero. Every rational number, when divided, produces a decimal expansion. This decimal expansion takes one of two forms:
1. Terminating Decimal Expansion: The decimal representation ends after a finite number of digits. For example, 7/8 = 0.875. The division process eventually leaves a remainder of zero, so the decimal terminates.
2. Non-Terminating Repeating Decimal Expansion: The decimal representation goes on forever, but a block of digits repeats indefinitely. For example, 1/3 = 0.333... (the digit 3 repeats), and 1/7 = 0.142857142857... (the block 142857 repeats). This repeating block is called the period of the decimal, and it is often written with a bar over the repeating digits.
The key theorem in Class 10 states: Let x = p/q be a rational number, where p and q are co-prime (that is, HCF of p and q is 1). Then:
(i) x has a terminating decimal expansion if and only if the prime factorisation of q is of the form 2^n * 5^m, where n and m are non-negative integers.
(ii) x has a non-terminating repeating decimal expansion if the prime factorisation of q contains a prime factor other than 2 or 5.
This theorem connects the algebraic representation of a fraction to its decimal behaviour. The denominator's prime factorisation is the sole deciding factor. If the denominator (after reducing the fraction to lowest terms) has only 2s and 5s in its prime factorisation, the decimal will terminate. If any other prime (such as 3, 7, 11, 13, etc.) appears, the decimal will be non-terminating repeating.
Decimal Expansion of Rationals (Revisited) Formula
Let x = p/q be a rational number in its lowest terms (HCF(p, q) = 1).
If q = 2^n * 5^m (where n, m are non-negative integers), then x has a terminating decimal expansion.
If q has any prime factor other than 2 or 5, then x has a non-terminating repeating decimal expansion.
To convert a terminating decimal to a fraction: write the decimal as a fraction with a power of 10 in the denominator. For example, 0.375 = 375/1000 = 3/8.
To convert a repeating decimal to a fraction: let x equal the repeating decimal, multiply by a suitable power of 10 to shift the repeating block, and subtract to eliminate the repeating part.
Derivation and Proof
The proof of the theorem on terminating decimal expansions relies on the Fundamental Theorem of Arithmetic and the structure of our base-10 number system.
Why base 10 matters: Our decimal system is based on powers of 10. When we write a terminating decimal like 0.375, we mean 375/1000 = 375/(10^3). Since 10 = 2 * 5, any power of 10 has the form 10^k = 2^k * 5^k. Therefore, a fraction p/q can be expressed as a terminating decimal only if q can divide some power of 10.
Forward direction — If q = 2^n * 5^m, then the decimal terminates:
Suppose q = 2^n * 5^m. We want to express p/q as a fraction with a power of 10 in the denominator. If n is greater than or equal to m, multiply numerator and denominator by 5^(n - m): p/q = p * 5^(n - m) / (2^n * 5^m * 5^(n - m)) = p * 5^(n - m) / (2^n * 5^n) = p * 5^(n - m) / 10^n. This gives a terminating decimal with at most n decimal places. Similarly, if m is greater than n, multiply by 2^(m - n) to get a denominator of 10^m.
Example: Consider 7/8 = 7/2^3. Here q = 2^3, so n = 3 and m = 0. Multiply numerator and denominator by 5^3 = 125: 7 * 125 / (2^3 * 5^3) = 875/1000 = 0.875. The decimal terminates.
Reverse direction — If the decimal terminates, then q = 2^n * 5^m:
Suppose p/q has a terminating decimal expansion. Then p/q = d/10^k for some integers d and k. So p/q = d/(2^k * 5^k). Since p and q are co-prime, q must divide 2^k * 5^k. By the Fundamental Theorem of Arithmetic, the only prime factors of 2^k * 5^k are 2 and 5. Therefore, q can only have 2 and 5 as prime factors, meaning q = 2^n * 5^m for some non-negative integers n and m.
Why non-terminating repeating occurs:
When we perform long division of p by q, at each step we get a remainder. The possible remainders are 0, 1, 2, ..., q - 1. If the remainder is ever 0, the division terminates. If the remainder is never 0, then by the Pigeonhole Principle, within at most q steps, some remainder must repeat. Once a remainder repeats, the sequence of digits in the quotient begins to repeat, producing a non-terminating repeating decimal. This is guaranteed when q has a prime factor other than 2 or 5, because then q cannot divide any power of 10, so the remainder can never become 0.
Length of the repeating block: The length of the repeating block (period) divides the value of Euler's totient function applied to q. For simple cases like 1/7, the period is 6 (since the remainders cycle through 1, 3, 2, 6, 4, 5 before repeating). For 1/3, the period is 1.
Types and Properties
The decimal expansion of rational numbers falls into exactly two categories:
1. Terminating Decimals: These are decimals that have a finite number of digits after the decimal point. They occur when the denominator (in lowest terms) has no prime factors other than 2 and 5.
- 1/2 = 0.5 (denominator = 2 = 2^1)
- 3/4 = 0.75 (denominator = 4 = 2^2)
- 7/8 = 0.875 (denominator = 8 = 2^3)
- 13/20 = 0.65 (denominator = 20 = 2^2 * 5)
- 9/125 = 0.072 (denominator = 125 = 5^3)
2. Non-Terminating Repeating Decimals: These are decimals that go on forever with a repeating block of digits. They occur when the denominator (in lowest terms) has at least one prime factor other than 2 or 5.
- 1/3 = 0.333... (denominator = 3, repeating block: 3)
- 2/7 = 0.285714285714... (denominator = 7, repeating block: 285714)
- 5/6 = 0.8333... (denominator = 6 = 2 * 3, repeating block: 3)
- 1/11 = 0.090909... (denominator = 11, repeating block: 09)
- 7/12 = 0.58333... (denominator = 12 = 2^2 * 3, repeating block: 3)
Important note: Every terminating decimal can also be written as a non-terminating repeating decimal by appending repeating zeroes. For example, 0.5 = 0.5000... But conventionally, we consider it terminating.
Mixed type: Some decimals like 7/12 = 0.58333... have a non-repeating part (58) followed by a repeating part (3). This still counts as non-terminating repeating.
Methods
Method 1: Prime Factorisation of the Denominator
To determine whether a rational number p/q has a terminating or non-terminating repeating decimal expansion:
Step 1: Reduce p/q to its lowest terms by dividing both p and q by their HCF.
Step 2: Find the prime factorisation of q.
Step 3: Check if q = 2^n * 5^m. If yes, the decimal terminates. If q has any other prime factor, the decimal is non-terminating repeating.
Method 2: Long Division
Perform long division of p by q. If the remainder eventually becomes 0, the decimal terminates. If a remainder repeats, the decimal is non-terminating repeating. This method directly produces the decimal expansion and is useful for finding the actual digits.
Method 3: Converting Denominator to a Power of 10
If the denominator is of the form 2^n * 5^m, multiply both numerator and denominator by 2^(m-n) or 5^(n-m) (whichever is needed) to make the denominator a power of 10. This directly gives the terminating decimal.
Method 4: Converting Repeating Decimals to Fractions
To convert a repeating decimal back to a fraction: (a) Let x = the repeating decimal. (b) Multiply x by 10^k, where k is the number of digits in the repeating block. (c) Subtract the original equation from the new one to eliminate the repeating part. (d) Solve for x.
Solved Examples
Example 1: Example 1: Determine if 13/3125 has a terminating decimal expansion
Problem: Without actually performing long division, state whether 13/3125 will have a terminating or non-terminating repeating decimal expansion.
Solution:
Step 1: Check if the fraction is in lowest terms. HCF(13, 3125) = 1 (since 13 is prime and does not divide 3125). So the fraction is already in lowest terms.
Step 2: Find the prime factorisation of the denominator. 3125 = 5 * 625 = 5 * 5 * 125 = 5 * 5 * 5 * 25 = 5 * 5 * 5 * 5 * 5 = 5^5.
Step 3: Since q = 5^5 = 2^0 * 5^5 (which is of the form 2^n * 5^m), the decimal expansion is terminating.
Step 4: To find the actual decimal, multiply numerator and denominator by 2^5 = 32: 13 * 32 / (5^5 * 2^5) = 416 / 100000 = 0.00416.
Answer: 13/3125 = 0.00416, which is a terminating decimal.
Example 2: Example 2: Determine the decimal nature of 17/6
Problem: Does 17/6 have a terminating or non-terminating repeating decimal expansion?
Solution:
Step 1: Check if the fraction is in lowest terms. HCF(17, 6) = 1 (17 is prime, 6 = 2 * 3). So the fraction is already in lowest terms.
Step 2: Find the prime factorisation of the denominator. 6 = 2 * 3.
Step 3: The prime factorisation of q contains the prime factor 3 (which is neither 2 nor 5). Therefore, the decimal expansion is non-terminating repeating.
Step 4: By long division, 17/6 = 2.8333... The digit 3 repeats.
Answer: 17/6 has a non-terminating repeating decimal expansion: 2.8333...
Example 3: Example 3: Find the decimal expansion of 7/80
Problem: Express 7/80 as a decimal and verify it terminates.
Solution:
Step 1: HCF(7, 80) = 1, so the fraction is in lowest terms.
Step 2: Prime factorisation of 80 = 2^4 * 5.
Step 3: Since q = 2^4 * 5^1 (of the form 2^n * 5^m), the decimal terminates.
Step 4: To convert, make the denominator a power of 10. We need 5^(4-1) = 5^3 = 125. Multiply numerator and denominator by 125: 7 * 125 / (80 * 125) = 875 / 10000 = 0.0875.
Answer: 7/80 = 0.0875 (terminating decimal with 4 decimal places).
Example 4: Example 4: Convert 0.363636... to a fraction
Problem: Express the repeating decimal 0.363636... (where 36 repeats) as a fraction in its simplest form.
Solution:
Step 1: Let x = 0.363636...
Step 2: The repeating block has 2 digits, so multiply by 10^2 = 100: 100x = 36.363636...
Step 3: Subtract the original equation: 100x - x = 36.363636... - 0.363636... This gives 99x = 36.
Step 4: Solve for x: x = 36/99.
Step 5: Simplify by dividing by HCF(36, 99) = 9: x = 4/11.
Verification: Prime factorisation of 11 is just 11 (which is neither 2 nor 5), confirming 4/11 has a non-terminating repeating decimal.
Answer: 0.363636... = 4/11.
Example 5: Example 5: Check multiple fractions for terminating decimals
Problem: Which of the following rational numbers have terminating decimal expansions? (a) 23/200 (b) 9/14 (c) 31/250 (d) 11/30
Solution:
(a) 23/200: HCF(23, 200) = 1. Denominator 200 = 2^3 * 5^2 (form 2^n * 5^m). Terminating. 23/200 = 23 * 5 / (200 * 5) = 115/1000 = 0.115.
(b) 9/14: HCF(9, 14) = 1. Denominator 14 = 2 * 7. Contains prime factor 7. Non-terminating repeating.
(c) 31/250: HCF(31, 250) = 1. Denominator 250 = 2 * 5^3 (form 2^n * 5^m). Terminating. 31/250 = 31 * 4 / (250 * 4) = 124/1000 = 0.124.
(d) 11/30: HCF(11, 30) = 1. Denominator 30 = 2 * 3 * 5. Contains prime factor 3. Non-terminating repeating.
Answer: (a) and (c) have terminating decimal expansions.
Example 6: Example 6: Find the number of decimal places
Problem: Without performing the division, find the number of decimal places in the terminating decimal expansion of 21/400.
Solution:
Step 1: HCF(21, 400) = 1, so the fraction is in lowest terms.
Step 2: Prime factorisation of 400 = 2^4 * 5^2.
Step 3: To convert to a power of 10, we need max(4, 2) = 4 as the exponent. So the denominator becomes 10^4 = 10000.
Step 4: Multiply numerator and denominator by 5^(4-2) = 5^2 = 25: 21 * 25 / (400 * 25) = 525 / 10000 = 0.0525.
Step 5: The number of decimal places equals max(n, m) = max(4, 2) = 4.
Answer: 21/400 = 0.0525 has 4 decimal places.
Example 7: Example 7: Convert 2.1454545... to a fraction
Problem: Express 2.1454545... (where 45 repeats after the initial non-repeating part 1) as a fraction.
Solution:
Step 1: Let x = 2.1454545...
Step 2: The non-repeating part after the decimal has 1 digit, and the repeating block has 2 digits.
Step 3: Multiply by 10 to move the non-repeating part: 10x = 21.454545...
Step 4: Multiply by 10^2 * 10 = 1000 to shift by the repeating block as well: 1000x = 2145.4545...
Step 5: Subtract: 1000x - 10x = 2145.4545... - 21.4545... = 2124. So 990x = 2124.
Step 6: x = 2124/990. Simplify by dividing by HCF(2124, 990) = 6: x = 354/165. Divide by 3: x = 118/55.
Verification: 55 = 5 * 11, which has prime factor 11 (other than 2 or 5), confirming the decimal is non-terminating repeating.
Answer: 2.1454545... = 118/55.
Example 8: Example 8: Prove that the decimal expansion of 1/17 is non-terminating repeating
Problem: Show that 1/17 has a non-terminating repeating decimal expansion and find the length of the repeating block.
Solution:
Step 1: HCF(1, 17) = 1, so the fraction is already in lowest terms.
Step 2: Prime factorisation of 17 is simply 17 (it is a prime number).
Step 3: Since 17 is neither 2 nor 5, the decimal expansion is non-terminating repeating.
Step 4: By long division of 1 by 17:
1/17 = 0.058823529411764705882352941176470...
The repeating block is 0588235294117647, which has 16 digits.
Step 5: The length of the repeating block divides (17 - 1) = 16. In this case, the period is exactly 16, which means 1/17 has the maximum possible period length.
Answer: 1/17 has a non-terminating repeating decimal with a repeating block of 16 digits: 0588235294117647.
Example 9: Example 9: After how many places will the decimal expansion of 23/2^3 * 5^4 terminate?
Problem: After how many decimal places will the decimal expansion of 23/(2^3 * 5^4) terminate?
Solution:
Step 1: The denominator is 2^3 * 5^4. This is already in the form 2^n * 5^m with n = 3 and m = 4.
Step 2: The number of decimal places in the terminating expansion equals max(n, m) = max(3, 4) = 4.
Step 3: To verify, convert to a fraction with denominator 10^4: Multiply numerator and denominator by 2^(4-3) = 2: 23 * 2 / (2^3 * 5^4 * 2) = 46 / (2^4 * 5^4) = 46/10000 = 0.0046.
The decimal 0.0046 has 4 decimal places (counting the leading zeroes after the decimal point).
Answer: The decimal expansion terminates after 4 places.
Example 10: Example 10: Show that 0.9999... = 1
Problem: Prove that the repeating decimal 0.9999... (where 9 repeats forever) is exactly equal to 1.
Solution:
Method 1 (Algebraic):
Step 1: Let x = 0.9999...
Step 2: Multiply by 10: 10x = 9.9999...
Step 3: Subtract: 10x - x = 9.9999... - 0.9999... = 9.
Step 4: So 9x = 9, which gives x = 1.
Method 2 (Fraction):
We know that 1/3 = 0.3333...
Multiplying both sides by 3: 3 * (1/3) = 3 * 0.3333... = 0.9999...
But 3 * (1/3) = 1. Therefore, 0.9999... = 1.
Method 3 (Logical):
If 0.9999... is not equal to 1, then there must be a number between 0.9999... and 1. But no such number exists, because for any number of 9s you write, the gap between 0.999...9 and 1 is 1/10^n, and as n approaches infinity, this gap approaches 0.
Answer: 0.9999... = 1. This is not an approximation; they are exactly the same real number.
Real-World Applications
Understanding the decimal expansion of rational numbers has several practical applications across mathematics and everyday life.
In Banking and Finance: Interest rates, currency conversions, and tax calculations often produce decimal results. Knowing whether a division will yield a terminating or repeating decimal helps in rounding correctly and avoiding errors in financial computations.
In Engineering and Measurement: When converting between units (for instance, fractions of an inch to millimetres), the nature of the decimal expansion determines precision. Terminating decimals give exact values, while repeating decimals require rounding, introducing small errors.
In Computer Science: Computers store numbers in binary (base 2). A fraction that terminates in base 10 may not terminate in base 2 (for example, 1/5 = 0.2 in base 10 but 0.001100110011... in base 2). Understanding decimal expansions helps programmers anticipate floating-point representation errors.
In Cryptography: Properties of repeating decimals and modular arithmetic are used in number theory, which forms the basis of encryption algorithms.
In Examinations: CBSE Class 10 board exams frequently test the ability to determine whether a fraction has a terminating decimal expansion, making this a high-scoring and essential topic.
Key Points to Remember
- A rational number p/q (in lowest terms) has a terminating decimal expansion if and only if the prime factorisation of q is of the form 2^n * 5^m.
- If q has any prime factor other than 2 or 5, the decimal expansion is non-terminating repeating.
- The number of decimal places in a terminating decimal equals max(n, m), where q = 2^n * 5^m.
- Every terminating decimal can be expressed as a fraction with a power of 10 in the denominator.
- Every non-terminating repeating decimal represents a rational number and can be converted back to a fraction using algebraic methods.
- The length of the repeating block in the decimal expansion of 1/q divides the Euler totient function of q.
- The Fundamental Theorem of Arithmetic (unique prime factorisation) is the basis for this theorem.
- Always reduce the fraction to lowest terms before checking the denominator's prime factorisation.
- 0.9999... (repeating) is exactly equal to 1, not approximately equal.
- Irrational numbers (like the square root of 2 or pi) have non-terminating, non-repeating decimal expansions, distinguishing them from rationals.
Practice Problems
- Without performing long division, determine whether 77/210 has a terminating or non-terminating repeating decimal expansion. (Hint: reduce to lowest terms first.)
- Find the decimal expansion of 13/3200 and state the number of decimal places.
- Express the repeating decimal 0.474747... as a fraction in its simplest form.
- The decimal expansion of 7/q terminates. If q is a two-digit number greater than 30, list all possible values of q.
- Express 3.127272727... (where 27 repeats) as a fraction in its simplest form.
- Determine the number of decimal places in the terminating decimal expansion of 129/(2^2 * 5^7).
- Prove that the product of a terminating decimal and a non-terminating repeating decimal is always a non-terminating repeating decimal, or provide a counterexample.
- Find the length of the repeating block in the decimal expansion of 1/13.
Frequently Asked Questions
Q1. What is a terminating decimal expansion?
A terminating decimal expansion is a decimal representation that ends after a finite number of digits. For example, 0.75, 0.125, and 3.4 are all terminating decimals. A rational number p/q (in lowest terms) has a terminating decimal if the denominator q has only 2 and 5 as prime factors.
Q2. What is a non-terminating repeating decimal?
A non-terminating repeating decimal is a decimal that goes on forever but has a block of digits that repeats indefinitely. For example, 1/3 = 0.333... and 1/7 = 0.142857142857... The repeating block is called the period. A rational number has this type of decimal when its denominator (in lowest terms) has a prime factor other than 2 or 5.
Q3. How do you determine if a fraction has a terminating decimal without dividing?
First, reduce the fraction to its lowest terms by dividing by the HCF of the numerator and denominator. Then find the prime factorisation of the denominator. If the denominator is of the form 2^n * 5^m (only contains 2s and 5s), the decimal terminates. Otherwise, it is non-terminating repeating.
Q4. Why are only 2 and 5 the special prime factors?
Because our number system is base 10, and 10 = 2 * 5. A terminating decimal is essentially a fraction whose denominator is a power of 10. Since the only prime factors of any power of 10 are 2 and 5, the denominator of the fraction (in lowest terms) must also have only 2 and 5 as prime factors.
Q5. Is 0.9999... really equal to 1?
Yes, 0.9999... (with 9 repeating forever) is exactly equal to 1. This can be proved algebraically: let x = 0.999..., then 10x = 9.999..., so 10x - x = 9, giving 9x = 9 and x = 1. It is not an approximation; they are the same real number.
Q6. Can a fraction with a non-terminating repeating decimal be an irrational number?
No. Every non-terminating repeating decimal represents a rational number. A decimal is irrational only if it is non-terminating AND non-repeating (no block of digits ever repeats). Examples of irrational decimals include the square root of 2 = 1.41421356... and pi = 3.14159265...
Q7. What is the maximum length of the repeating block for 1/q?
The maximum length of the repeating block (period) for 1/q is q - 1. For example, 1/7 has a period of 6 (which equals 7 - 1), and 1/17 has a period of 16 (which equals 17 - 1). However, the actual period can be shorter; for instance, 1/11 has a period of 2 (not 10).
Q8. How do you convert a repeating decimal to a fraction?
Let x equal the repeating decimal. Multiply x by a power of 10 to shift the repeating block. Subtract the original equation from the multiplied one to eliminate the repeating part. Solve the resulting equation for x and simplify. For example, for x = 0.272727..., multiply by 100 to get 100x = 27.2727..., subtract to get 99x = 27, so x = 27/99 = 3/11.
Q9. Does the numerator affect whether the decimal terminates?
The numerator does not affect whether the decimal terminates or repeats, provided the fraction is in its lowest terms. The nature of the decimal expansion depends solely on the prime factorisation of the denominator. However, if the fraction is not in lowest terms, common factors between numerator and denominator might simplify the denominator, potentially changing its prime factorisation.
Q10. What is the importance of this topic in CBSE board exams?
This topic is part of the Real Numbers chapter and typically carries 1-mark or 2-mark questions in CBSE Class 10 board exams. Questions usually ask students to determine whether a given fraction has a terminating decimal expansion, or to find the number of decimal places. It is considered an easy and high-scoring topic.










