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Mean of Ungrouped Data

Class 9Statistics

The mean (or arithmetic mean) is the most commonly used measure of central tendency in statistics. It gives a single value that represents the entire data set, serving as the "centre" or "balance point" of the data.


For ungrouped data (raw data that has not been arranged into class intervals or frequency groups), the mean is calculated by dividing the sum of all observations by the total number of observations. This is the simplest and most intuitive definition of "average" that we use in everyday life.


In NCERT Class 9 Mathematics (Chapter 14: Statistics), the mean of ungrouped data is introduced alongside two other measures of central tendency: the median (middle value) and the mode (most frequent value). Among these three, the mean is the most useful for numerical calculations because it takes every observation into account.


The mean is widely used in science (averaging experimental readings to reduce error), economics (per capita income, average prices), sports (batting averages, points per game), education (average marks, GPA), and daily life (average temperature, average speed on a journey).


The concept of "average" dates back thousands of years. Ancient merchants used averages to estimate the value of goods, and navigators averaged measurements to chart courses. Today, the arithmetic mean is the foundation for more advanced statistical measures like variance, standard deviation, and regression analysis.

What is Mean of Ungrouped Data?

Definition: The arithmetic mean (or simply mean) of a set of observations is the sum of all observations divided by the number of observations.


Mean (&x0304;) = Σxᵢ / n


In expanded form:

Mean = (x&sub1; + x&sub2; + x&sub3; + ... + x_n) / n


Where:

  • x&sub1;, x&sub2;, ..., x_n = the individual observations
  • n = total number of observations
  • Σ (sigma) = summation symbol
  • &x0304; (x-bar) = mean of x

Important:

  • The mean is affected by extreme values (very large or very small observations).
  • The mean may not be a value that actually appears in the data set.
  • The sum of deviations from the mean is always zero: Σ(xᵢ − &x0304;) = 0.

Mean of Ungrouped Data Formula

Key Formulas:


1. Direct method (raw data):

Mean = (x&sub1; + x&sub2; + ... + x_n) / n


2. With frequency table (ungrouped):

If values x&sub1;, x&sub2;, ..., x_k occur with frequencies f&sub1;, f&sub2;, ..., f_k:

Mean = Σ(fᵢ × xᵢ) / Σfᵢ


3. Combined mean:

  • If two groups have means &x0304;&sub1; and &x0304;&sub2; with sizes n&sub1; and n&sub2;:
  • Combined mean = (n&sub1;&x0304;&sub1; + n&sub2;&x0304;&sub2;) / (n&sub1; + n&sub2;)

4. Finding missing value:

  • If the mean is known: Missing value = (Mean × n) − Sum of known values

5. Sum of deviations from the mean:

Σ(xᵢ − &x0304;) = 0

Derivation and Proof

Properties of the Arithmetic Mean:


Property 1: Sum of deviations from the mean is zero.

  1. Let the mean of x&sub1;, x&sub2;, ..., x_n be &x0304;.
  2. Σ(xᵢ − &x0304;) = Σxᵢ − n&x0304; = Σxᵢ − n × (Σxᵢ/n) = Σxᵢ − Σxᵢ = 0

Property 2: Effect of changing each observation.

  • If each observation is increased (or decreased) by a constant k:
  • New mean = Old mean + k (or Old mean − k)

Property 3: Effect of multiplying each observation.

  • If each observation is multiplied by a constant k:
  • New mean = k × Old mean

Property 4: Mean lies between the smallest and largest values.

  • min(xᵢ) ≤ &x0304; ≤ max(xᵢ)

Why the mean is important:

  • It uses all observations in the calculation.
  • It is the best measure when data has no extreme outliers.
  • It is used as the basis for higher statistics (variance, standard deviation).

Types and Properties

Methods of calculating mean for ungrouped data:


1. Direct method (raw data)

  • Simply add all values and divide by the count.
  • Used when the number of observations is small.
  • Mean = Sum / n

2. Frequency distribution method

  • Used when the same values repeat multiple times.
  • Multiply each value by its frequency, sum the products, divide by total frequency.
  • Mean = Σ(fᵢxᵢ) / Σfᵢ

3. Short-cut (assumed mean) method

  • Choose an assumed mean a.
  • Calculate deviations: dᵢ = xᵢ − a
  • Mean = a + (Σfᵢdᵢ / Σfᵢ)
  • Useful when values are large numbers.

Comparison with other averages:

  • Mean: Uses all values. Affected by extremes.
  • Median: The middle value when data is arranged in order. Not affected by extremes.
  • Mode: The most frequently occurring value. Easiest to find.

Solved Examples

Example 1: Example 1: Mean of raw data

Problem: Find the mean of: 12, 15, 18, 20, 25.


Solution:

Given:

  • Observations: 12, 15, 18, 20, 25
  • n = 5

Mean = Sum / n:

  • Sum = 12 + 15 + 18 + 20 + 25 = 90
  • Mean = 90/5 = 18

Answer: Mean = 18.

Example 2: Example 2: Mean of test scores

Problem: The marks scored by 8 students in a test are: 72, 85, 90, 68, 76, 82, 95, 88. Find the mean score.


Solution:

Given:

  • n = 8

Sum:

  • 72 + 85 + 90 + 68 + 76 + 82 + 95 + 88 = 656

Mean:

  • Mean = 656/8 = 82

Answer: Mean score = 82.

Example 3: Example 3: Mean using frequency table

Problem: The following table shows the number of goals scored by a football team in 20 matches:

  • Goals (x): 0, 1, 2, 3, 4
  • Frequency (f): 3, 5, 6, 4, 2

Find the mean number of goals per match.


Solution:

Calculate Σfx:

  • (0 × 3) + (1 × 5) + (2 × 6) + (3 × 4) + (4 × 2)
  • = 0 + 5 + 12 + 12 + 8 = 37

Σf = 3 + 5 + 6 + 4 + 2 = 20

Mean = Σfx / Σf = 37/20 = 1.85

Answer: Mean = 1.85 goals per match.

Example 4: Example 4: Finding a missing value

Problem: The mean of 5 numbers is 24. Four of the numbers are 18, 22, 30, and 26. Find the fifth number.


Solution:

Given:

  • Mean = 24, n = 5

Sum of all 5 numbers:

  • Sum = Mean × n = 24 × 5 = 120

Sum of known numbers:

  • 18 + 22 + 30 + 26 = 96

Fifth number:

  • 120 − 96 = 24

Answer: The fifth number is 24.

Example 5: Example 5: Effect of adding a constant

Problem: The mean of 10 observations is 35. If 5 is added to each observation, find the new mean.


Solution:

Given:

  • Old mean = 35, constant added = 5

By the property of mean:

  • New mean = Old mean + constant = 35 + 5 = 40

Answer: New mean = 40.

Example 6: Example 6: Combined mean of two groups

Problem: Group A has 30 students with a mean score of 72. Group B has 20 students with a mean score of 82. Find the combined mean.


Solution:

Given:

  • n&sub1; = 30, &x0304;&sub1; = 72
  • n&sub2; = 20, &x0304;&sub2; = 82

Combined mean:

  • = (n&sub1;&x0304;&sub1; + n&sub2;&x0304;&sub2;) / (n&sub1; + n&sub2;)
  • = (30 × 72 + 20 × 82) / (30 + 20)
  • = (2160 + 1640) / 50
  • = 3800 / 50 = 76

Answer: Combined mean = 76.

Example 7: Example 7: Mean with repeated values

Problem: The ages of 12 students are: 14, 14, 15, 15, 15, 16, 16, 16, 16, 17, 17, 17. Find the mean age.


Solution:

Using frequency method:

  • Age 14: f = 2, fx = 28
  • Age 15: f = 3, fx = 45
  • Age 16: f = 4, fx = 64
  • Age 17: f = 3, fx = 51

Σf = 12, Σfx = 28 + 45 + 64 + 51 = 188

Mean = 188/12 = 15.67 (approx.)

Answer: Mean age ≈ 15.67 years.

Example 8: Example 8: Verifying the zero-deviation property

Problem: The data is: 4, 7, 10, 13, 16. Verify that the sum of deviations from the mean is zero.


Solution:

Step 1: Find the mean

  • Mean = (4 + 7 + 10 + 13 + 16)/5 = 50/5 = 10

Step 2: Calculate deviations

  • 4 − 10 = −6
  • 7 − 10 = −3
  • 10 − 10 = 0
  • 13 − 10 = 3
  • 16 − 10 = 6

Step 3: Sum of deviations

  • −6 + (−3) + 0 + 3 + 6 = 0

Answer: Sum of deviations from the mean = 0. Verified.

Example 9: Example 9: Mean of first n natural numbers

Problem: Find the mean of the first 10 natural numbers.


Solution:

First 10 natural numbers: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10

Sum = n(n + 1)/2:

  • Sum = 10 × 11/2 = 55

Mean = Sum/n:

  • Mean = 55/10 = 5.5

General formula: Mean of first n natural numbers = (n + 1)/2.

Answer: Mean = 5.5.

Example 10: Example 10: Effect of removing a value

Problem: The mean of 6 numbers is 20. When one number is removed, the mean of the remaining 5 numbers becomes 18. Find the removed number.


Solution:

Given:

  • Mean of 6 numbers = 20 ⇒ Sum = 6 × 20 = 120
  • Mean of 5 numbers = 18 ⇒ Sum of remaining = 5 × 18 = 90

Removed number:

  • 120 − 90 = 30

Answer: The removed number is 30.

Real-World Applications

Applications of the Arithmetic Mean:


  • Academic Performance: Schools calculate average marks, aggregate percentages, and cumulative GPAs using the arithmetic mean. When a student scores 85, 90, 78, 92, and 95 in five subjects, the average (88) determines rank, eligibility for scholarships, and placement in advanced courses. Report cards universally use the mean to summarise performance.
  • Economics and Finance: Per capita income (total national income divided by population) is one of the most important economic indicators. Average stock prices, average inflation rates, and average GDP growth rates all use the arithmetic mean. Investors calculate the average return on investment to compare different financial instruments.
  • Science and Experimentation: Scientists take multiple measurements of the same quantity and average them to reduce random errors. If a physics student measures the period of a pendulum as 2.01 s, 1.99 s, 2.02 s, 1.98 s, and 2.00 s, the mean (2.00 s) is more reliable than any single measurement. This averaging process is fundamental to the scientific method.
  • Sports Statistics: Batting averages in cricket (total runs ÷ total innings), bowling averages (runs conceded ÷ wickets taken), points per game in basketball, and goals per match in football are all mean values. Coaches and analysts use these averages for player selection, strategy, and performance evaluation.
  • Business Planning: Average daily sales, average customer spending, and average production cost per unit are crucial for business planning. If a shop sells an average of 150 items per day at an average price of Rs 200, the estimated daily revenue is Rs 30,000. These averages drive inventory decisions, staffing, and financial projections.
  • Weather and Climate: Average temperature, average rainfall, and average wind speed for a city are calculated from daily observations over months and years. The average January temperature in Delhi (14°C) and Mumbai (25°C) helps residents, tourists, and planners make informed decisions.
  • Medical and Health: Doctors use mean values for clinical parameters — average blood pressure (120/80 mmHg), average heart rate (72 bpm), average BMI. These population averages establish normal ranges against which individual patients are compared.
  • Quality Control: Factories monitor the average weight, length, or diameter of products to ensure consistency. If the average diameter of 100 sampled bolts is within the tolerance range, the production batch passes quality inspection.

Key Points to Remember

  • Mean = Sum of all observations / Number of observations = Σxᵢ / n.
  • For a frequency distribution: Mean = Σ(fᵢ × xᵢ) / Σfᵢ, where fᵢ is the frequency of value xᵢ.
  • The mean uses every observation in the data set, making it the most comprehensive measure of central tendency.
  • The mean is affected by extreme values (outliers). A single very large or very small value can pull the mean away from the centre of the data. When outliers are present, the median is a better measure.
  • The sum of deviations from the mean is always zero: Σ(xᵢ − x̄) = 0. This means the mean is the "balance point" of the data — positive and negative deviations cancel out exactly.
  • Adding a constant k to each value increases the mean by k. Multiplying each value by k multiplies the mean by k. These properties simplify calculations.
  • The mean of first n natural numbers = (n + 1)/2. For example, mean of 1 to 100 = 101/2 = 50.5.
  • The combined mean of two groups: Combined mean = (n₁x̄₁ + n₂x̄₂) / (n₁ + n₂). This accounts for different group sizes.
  • The mean may not be an actual value in the data set. For example, the mean of 3 and 8 is 5.5, which is not in the data.
  • The assumed mean method (short-cut method) simplifies calculation when values are large: Mean = A + Σ(fᵢdᵢ)/Σfᵢ, where A is the assumed mean and dᵢ = xᵢ − A.
  • Mean is the most suitable average for numerical data without outliers. For skewed data or data with outliers, median is preferred.
  • Mean of ungrouped data is covered in Chapter 14 (Statistics) of CBSE Class 9 NCERT Mathematics.

Practice Problems

  1. Find the mean of: 8, 12, 15, 20, 25, 30.
  2. The marks of 7 students are 55, 60, 72, 48, 65, 80, 76. Find the mean marks.
  3. The following frequency table shows the number of books read by students in a month: Books (x): 1, 2, 3, 4, 5; Frequency (f): 4, 8, 10, 6, 2. Find the mean.
  4. The mean of 8 numbers is 15. Seven of the numbers are 10, 12, 14, 16, 18, 20, and 13. Find the eighth number.
  5. The mean of 20 observations is 40. If each observation is multiplied by 3, what is the new mean?
  6. Group A (25 students) has a mean score of 68. Group B (15 students) has a mean score of 78. Find the combined mean.
  7. The data is: 5, 10, 15, 20, 25. Verify that the sum of deviations from the mean is zero.
  8. Find the mean of the first 20 natural numbers using the formula.

Frequently Asked Questions

Q1. What is the mean of ungrouped data?

The mean of ungrouped data is the sum of all observations divided by the total number of observations. It is the arithmetic average of the raw data values.

Q2. What is the formula for mean?

Mean = (x1 + x2 + ... + xn) / n. For frequency data: Mean = Σ(fx) / Σf.

Q3. What is the difference between mean, median, and mode?

Mean is the arithmetic average. Median is the middle value when data is arranged in order. Mode is the most frequently occurring value. All three are measures of central tendency.

Q4. Is the mean always a value in the data set?

No. The mean can be a value that does not appear in the data. For example, the mean of 3 and 8 is 5.5, which is not in the data set.

Q5. Why is the mean affected by extreme values?

Because the mean uses the sum of all values, a very large or very small value disproportionately affects the sum and hence the average. Median is a better choice when outliers are present.

Q6. What does it mean that the sum of deviations from the mean is zero?

The positive and negative deviations from the mean exactly cancel out. This means the mean is the 'balance point' of the data — values above and below it are equally distributed in terms of total deviation.

Q7. How do you find a missing value if the mean is known?

Multiply the mean by the number of observations to get the total sum. Subtract the sum of the known values. The result is the missing value.

Q8. What is the combined mean?

When two groups have different means and sizes, the combined mean = (n1 × mean1 + n2 × mean2) / (n1 + n2). It accounts for the different sizes of the groups.

Q9. Is mean of ungrouped data in the CBSE Class 9 syllabus?

Yes. The mean of ungrouped data is part of Chapter 14 (Statistics) in the CBSE Class 9 Mathematics syllabus.

Q10. What is the mean of the first n natural numbers?

The mean of the first n natural numbers = (n + 1)/2. For example, the mean of 1 to 10 is (10 + 1)/2 = 5.5.

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