Buoyancy is one of the key principles of physics that explains the upward force that fluid, liquid or gas, exerts on an object that is partially or wholly immersed in it. It opposes the weight of the object and causes it to float, sometimes making it sink and then pop up above water.
This is the upward force exerted by the liquid.
The symbol of Buoyancy is B or FB. It is a vector quantity and has both magnitude as well as direction. The unit of buoyancy is Newton [N].
Buoyancy is caused due to the change in pressure. The pressure is higher at the bottom of the object and decreases as we move up. The bottom pressure pushes the object upward and top pressure pushes it downward. So, the net force of the object is upward.
Buoyant force Fb, in terms of pressure, is represented as
Where,
F2 = force acting upwards
F1 = force acting downwards
Force, F=PA
Where,
P = Pressure and
A = Area
Where,
ρ is the density of the fluid is ρ
g is the gravity
V is the volume of the immersed part of the body in the fluid
h is the height of the submerged portion
A is the area
Problem: A cube with side length of 0.2 m is submerged in water. What is the buoyant force acting on it?
Solution:
Volume of the Cube:
V=side3
=(0.2 m)3
=0.008 m3
Density of Water: ρ=1000 kg/m3
Acceleration due to Gravity: g=9.81 m/s2
Find the Buoyant Force:
F b=ρ⋅V⋅g
ρ=1000 kg/m3⋅0.008 m3⋅9.81 m/s2
F\ nb =1000 kg/m30.008 m39.81 m/s2
= 78.48 N
The buoyant force acting on the cube would be approximately 78.48 N.
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Buoyancy is one of the key principles of physics that explains the upward force that fluid, liquid or gas, exerts on an object that is partially or wholly immersed in it. It opposes the weight of the object and causes it to float, sometimes making it sink and then pop up above water.
This is the upward force exerted by the liquid.
The symbol of Buoyancy is B or FB. It is a vector quantity and has both magnitude as well as direction. The unit of buoyancy is Newton [N].
Buoyancy is caused due to the change in pressure. The pressure is higher at the bottom of the object and decreases as we move up. The bottom pressure pushes the object upward and top pressure pushes it downward. So, the net force of the object is upward.
Buoyant force Fb, in terms of pressure, is represented as
Where,
F2 = force acting upwards
F1 = force acting downwards
Force, F=PA
Where,
P = Pressure and
A = Area
Where,
ρ is the density of the fluid is ρ
g is the gravity
V is the volume of the immersed part of the body in the fluid
h is the height of the submerged portion
A is the area
Problem: A cube with side length of 0.2 m is submerged in water. What is the buoyant force acting on it?
Solution:
Volume of the Cube:
V=side3
=(0.2 m)3
=0.008 m3
Density of Water: ρ=1000 kg/m3
Acceleration due to Gravity: g=9.81 m/s2
Find the Buoyant Force:
F b=ρ⋅V⋅g
ρ=1000 kg/m3⋅0.008 m3⋅9.81 m/s2
F\ nb =1000 kg/m30.008 m39.81 m/s2
= 78.48 N
The buoyant force acting on the cube would be approximately 78.48 N.
Other Related Sections
NCERT Solutions | Sample Papers | CBSE SYLLABUS| Calculators | Converters | Stories For Kids | Poems for kids| Learning Concepts I Practice Worksheets I Formulas | Blogs | Parent Resource
List of Physics Formulas |
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