Friction Force Formula

Friction is a repulsive force when one body is sliding through a surface. Friction is due to the contact of two surfaces. If the frictional force is strong, the motion of bodies through the surface is not smooth. Throughout this motion, the kinetic energy is converted to heat energy. The friction force is a derived force and not like gravitation i.e. a fundamental force.

Formula

Formula for friction is given as,


  • Ff = friction

  • μ  = the coefficient of friction force

  • Fn = the normal force

            It is a vector quantity.

Solved Problems

Problem 1: An object of mass 10 kg is moving through a surface. Find the friction force if the coefficient of friction is 0.2?

Solution

Known quantities are,

m = 10 kg and μ = 0.2

The friction force formula is,

can be calculated as,

= mg

    = 10×9.81 = 98.1 N

Thus, Ff = 0.2×98.1 = 19.62 N

Friction force Ff is 19.62 N

Problem 2: Determine the friction force of a 5 kg body which moves over a surface with a friction coefficient 0.3?

Solution :

Known variables are,

m = 5 kg and μ = 0.3

The friction force formula is,

can be calculated as,

= mg

      = 5×9.81 

      = 49.05 N

Thus, Ff = 0.3×49.05 

               = 14.715 N

Friction force Ff is 14.715 N

 

Other Related Sections

NCERT Solutions | Sample Papers | CBSE SYLLABUS| Calculators | Converters | Stories For Kids | Poems for kids| Learning Concepts I Practice Worksheets I Formulas | Blogs | Parent Resource

Admissions Open for

Friction Force Formula

Friction is a repulsive force when one body is sliding through a surface. Friction is due to the contact of two surfaces. If the frictional force is strong, the motion of bodies through the surface is not smooth. Throughout this motion, the kinetic energy is converted to heat energy. The friction force is a derived force and not like gravitation i.e. a fundamental force.

Formula

Formula for friction is given as,


  • Ff = friction

  • μ  = the coefficient of friction force

  • Fn = the normal force

            It is a vector quantity.

Solved Problems

Problem 1: An object of mass 10 kg is moving through a surface. Find the friction force if the coefficient of friction is 0.2?

Solution

Known quantities are,

m = 10 kg and μ = 0.2

The friction force formula is,

can be calculated as,

= mg

    = 10×9.81 = 98.1 N

Thus, Ff = 0.2×98.1 = 19.62 N

Friction force Ff is 19.62 N

Problem 2: Determine the friction force of a 5 kg body which moves over a surface with a friction coefficient 0.3?

Solution :

Known variables are,

m = 5 kg and μ = 0.3

The friction force formula is,

can be calculated as,

= mg

      = 5×9.81 

      = 49.05 N

Thus, Ff = 0.3×49.05 

               = 14.715 N

Friction force Ff is 14.715 N

 

Other Related Sections

NCERT Solutions | Sample Papers | CBSE SYLLABUS| Calculators | Converters | Stories For Kids | Poems for kids| Learning Concepts I Practice Worksheets I Formulas | Blogs | Parent Resource

List of Physics Formulas

Admissions Open for

Frequently Asked Questions

Formula: Ptolemy’s Theorem relates the sides and diagonals of a cyclic quadrilateral. For a cyclic quadrilateral ABCD with diagonals AC and BD, the theorem states:

We are also listed in