Important Questions on We Distribute Yet Things Multiply for Class 8 are available in this Maths article. Important Questions on We Distribute Yet Things Multiply for Class 8 are very useful to solve the problems easily. This article helps the students to know the key questions and answers about We Distribute Yet Things Multiply. We Distribute Yet Things Multiply covers division, factors, multiples, and their relationships, which we use in everyday calculations. Our subject experts have provided detailed solutions for these problems based on the CBSE syllabus and the NCERT textbook. This material helps students revise the chapter easily and perform well in the final examination.
Question 1: What is the distributive property of multiplication over addition?
Answer: The distributive property states:
a(b+c)=ab+ac
This means multiplication is distributed to each term inside the bracket.
Question 2: Use distributive property to solve: 24 × (10 + 2)
Answer:
Step 1: Multiply 24 by 10
24 × 10 = 240
Step 2: Multiply 24 by 2
24 × 2 = 48
Step 3: Add the results
240 + 48 = 288
Answer: 288
Question 3: Expand: 3(x + 5)
Answer:
Multiply 3 with each term inside the bracket.
3 × x = 3x
3 × 5 = 15
Answer: 3x + 15
Question 4: Expand: 7(a − 2)
Answer:
7 × a = 7a
7 × (−2) = −14
Answer: 7a − 14
Question 5: Find the value of: 15 × 101
Answer:
Using distributive property:
15 × (100 + 1)
= 15 × 100 + 15 × 1
= 1500 + 15
= 1515
Answer: 1515
Question 1: What are like terms?
Answer:
Terms having the same variables and powers are called like terms.
Example:
3x and 5x
Question 2: Simplify: 4x + 3x
Answer:
Add the coefficients.
4x + 3x = 7x
Answer: 7x
Question 3: Simplify: 8a − 2a + 5
Answer:
8a − 2a = 6a
So the expression becomes:
6a + 5
Answer: 6a + 5
Question 4: Expand: 5(p + q)
Answer:
5 × p = 5p
5 × q = 5q
Answer: 5p + 5q
Question 5: Simplify: 10m + 7m − 4m
Answer:
10m + 7m = 17m
17m − 4m = 13m
Answer: 13m
Question 1: Write the identity for the square of a sum.
Answer:
a(b+c)=ab+ac
Question 2: Expand: (x + 3)²
Answer:
Using identity:
(x + 3)² = x² + 2(x)(3) + 3²
= x² + 6x + 9
Answer: x² + 6x + 9
Question 3: Write the identity for the difference of squares.
Answer: (a+b)(a−b)=a2−b2
Question 4: Expand: (a − 5)²
Answer:
Using identity:
(a − 5)² = a² − 2(a)(5) + 5²
= a² − 10a + 25
Answer: a² − 10a + 25
Question 5: Find: (2x + 1)(2x − 1)
Answer:
Using identity:
(2x)² − (1)²
= 4x² − 1
Answer: 4x² − 1
Question 1: A teacher buys 25 notebooks costing ₹12 each. Find the total cost.
Answer:
Total cost = 25 × 12
= 25 × (10 + 2)
= 250 + 50
= 300
Answer: ₹300
Question 2: A box contains 15 rows of chocolates with 8 chocolates in each row. Find the total chocolates.
Answer:
15 × 8 = 120
Answer: 120 chocolates
Question 3: Find: 99 × 7
Answer:
99 × 7 = (100 − 1) × 7
= 700 − 7
= 693
Answer: 693
Question 4: A shopkeeper sells 18 pens at ₹15 each. Find the total amount.
Answer:
18 × 15
= 18 × (10 + 5)
= 180 + 90
= 270
Answer: ₹270
Question 5: Find: 52 × 11
Answer:
52 × (10 + 1)
= 520 + 52
= 572
Answer: 572
Learn distributive property carefully.
Practice algebraic expressions daily.
Remember algebraic identities using formulas.
Solve step-by-step problems regularly.
Revise identities before exams.
Practice simplifying expressions.
Avoid calculation mistakes in signs.
Write all multiplication steps clearly.
Solve previous year important questions.
Practice mental multiplication tricks.
Question 1: Expand: 2(a + 4)
Answer:
2a + 8
Question 2: Write the identity for: (a − b)²
Answer:
(a−b)2=a2−2ab+b2
Question 3: Simplify: 5x + 2x
Answer: 7x
Question 4: Find: 12 × 101
Answer:
12 × (100 + 1)
= 1200 + 12
= 1212
Answer: 1212
Question 5: What are like terms?
Answer:
Terms having the same variables and powers are called like terms.
Question 1: Expand: 4(x + 6)
Answer:
4 × x = 4x
4 × 6 = 24
Answer: 4x + 24
Question 2: Simplify: 7a + 5a − 3a
Answer:
7a + 5a = 12a
12a − 3a = 9a
Answer: 9a
Question 3: Expand: (y + 2)²
Answer:
(y + 2)² = y² + 2(y)(2) + 2²
= y² + 4y + 4
Answer: y² + 4y + 4
Question 4: Find: 49 × 11
Answer:
49 × (10 + 1)
= 490 + 49
= 539
Answer: 539
Question 5: Expand: (a + b)(a − b)
Answer:
a² − b²
Question 1: Explain distributive property with an example.
Answer:
The distributive property means multiplication can be distributed over addition.
Example:
6(4 + 2)
= 6 × 4 + 6 × 2
= 24 + 12
= 36
This method makes calculations easier.
Question 2: Expand and simplify: (2x + 3)²
Answer:
Using identity:
(2x + 3)²
= (2x)² + 2(2x)(3) + 3²
= 4x² + 12x + 9
Answer: 4x² + 12x + 9
Question 3: A shopkeeper buys 35 boxes with 12 chocolates in each box. Find the total chocolates using distributive property.
Answer:
35 × 12
= 35 × (10 + 2)
= 350 + 70
= 420
Answer: 420 chocolates
Question 4: Expand: (a − 4)(a + 4)
Answer:
Using identity:
a² − 4²
= a² − 16
Answer: a² − 16
Question 5: Explain algebraic identity with an example.
Answer: An algebraic identity is an equation that is true for all values of variables.
(a + b)2 = a2 + 2ab + b2
Let: a = 8, b = 3.5
Substituting the values:
(8 + 3.5)2 = 82 + 2(8)(3.5) + 3.52
11.52 = 64 + 56 + 12.25
132.25 = 132.25
Step-by-Step Expansion
(a + b)2
= a2 + ab + ab + b2
= a2 + 2ab + b2
This chapter explains the distributive property of multiplication over addition and subtraction, along with algebraic identities.
The distributive property means multiplying a number or variable across terms inside brackets.
Example: a(b+c)=ab+ac
It helps simplify algebraic expressions and solve equations easily.
Algebraic expansion means removing brackets using multiplication rules.
Example: (x+2)(x+3)=x2+5x+6
Factorisation is the reverse process of expansion, where expressions are written as products of factors.
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