Mensuration word problems help students understand how geometry is used in real life. These problems involve calculating the area, surface area, and volume of different shapes such as cubes, cuboids, cylinders, and trapeziums.You may come across situations like painting walls, filling water tanks, covering boxes, or measuring land. To solve these, you must identify the shape correctly and apply the right formula. This chapter brings together all the important concepts of mensuration in one place and helps you solve mixed word problems step by step.
Mensuration word problems are practical questions where you use geometry formulas to find the following:
These problems are based on everyday situations, like:
Key Idea: First identify the shape, then apply the correct formula.
Read more: Important Questions on Mensuration - Class 8
Know more about related topics:
Here are the key formulas used in Class 8:
Example 1: A room has a length of 10 m, a width of 5 m, and a height of 3 m. It has one door of 2 m × 1 m and one window of 1.5 m × 1 m. Find the cost of painting at Rs 20 per m².
Solution:
Lateral surface area = 2h(l + b)
= 2 × 3 × (10 + 5)
= 6 × 15 = 90 m²
Area of door = 2 × 1 = 2 m²
Area of window = 1.5 × 1 = 1.5 m²
Painted area = 90 − 2 − 1.5 = 86.5 m²
Cost = 86.5 × 20 = Rs 1,730
Answer: Rs 1,730
Example 2: A cylindrical tank has a radius of 1 m and a height of 3 m. Find its capacity in litres.
Solution:
Volume = πr²h
= 22/7 × 1 × 1 × 3
= 66/7 = 9.43 m³
Convert to litres:
9.43 × 1000 = 9,430 litres
Answer: 9,430 litres
Example 3: A box measures 25 cm × 15 cm × 10 cm. Find the wrapping paper required.
Solution:
Surface area = 2(lb + bh + lh)
= 2(25×15 + 15×10 + 25×10)
= 2(375 + 150 + 250)
= 2 × 775 = 1550 cm²
Answer: 1550 cm²
Example 4: Parallel sides are 30 m and 20 m; height is 8 m.
Solution:
Area = ½ × (a + b) × h
= ½ × (30 + 20) × 8
= ½ × 50 × 8 = 200 m²
Answer: 200 m²
Example 5: Find the sheet needed to make 10 cubes of side 1 m.
Solution:
Surface area of one cube = 6a²
= 6 × 1² = 6 m²
For 10 cubes = 10 × 6 = 60 m²
Answer: 60 m²
Example 6: Diagonals = 10 cm and 6 cm. Find the area of 20 tiles.
Solution:
Area of one tile = ½ × d₁ × d₂
= ½ × 10 × 6 = 30 cm²
Total = 20 × 30 = 600 cm²
Answer: 600 cm²
Example 7: Tank size = 3 m × 2 m × 1 m. Water fills at 2 litres/sec.
Solution:
Volume = 3 × 2 × 1 = 6 m³ = 6000 litres
Time = 6000 ÷ 2 = 3000 sec
= 50 minutes
Answer: 50 minutes
Example 8: Painting a Cylinder. Radius = 0.5 m, height = 4 m, rate = Rs 15/m²
Solution:
Curved surface area = 2πrh
= 2 × 22/7 × 0.5 × 4 = 88/7 ≈ 12.57 m²
Cost = 12.57 × 15 ≈ Rs 189
Answer: Rs 189
Mensuration is used in many areas:
Multiply cubic metres by 1000.
When only the sides are involved, like painting walls.
First identify the shape (cube, cylinder, etc.), then apply its formula.
They are real-life problems where we calculate area, surface area, or volume using formulas.
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