Table of 490

Table of 490 explains how multiplication works using a clear sequence. Learning the table of 490 helps students solve related math problems confidently. A free PDF of the Table of 490 is helpful for practice and revision.

Table of 490 Chart

The Table of 490 chart shows multiplication results clearly, supporting easy practice and revision.

Multiplication Table of 490

The multiplication table of 490 grows steadily by 490. Practicing this table helps students learn multiplication with bigger numbers and strengthens their ability to solve related problems quickly.

Multiplicand	Operation	Multiplier	Result
490	x	1	=	490
490	x	2	=	980
490	x	3	=	1470
490	x	4	=	1960
490	x	5	=	2450
490	x	6	=	2940
490	x	7	=	3430
490	x	8	=	3920
490	x	9	=	4410
490	x	10	=	4900
490	x	11	=	5390
490	x	12	=	5880
490	x	13

Students can download the Table of 490 as a free PDF to practice the table clearly and revise it whenever required.

Download PDF - Table of 490

 

How to read the multiplication table of 490?

Reading the Table of 490 is simple when you go through each multiplication from 490 × 1 to 490 × 20. This method helps learners clearly follow the full table.

490 times 1 is 490
490 times 2 is 980
490 times 3 is 1470
490 times 4 is 1960
490 times 5 is 2450
490 times 6 is 2940
490 times 7 is 3430
490 times 8 is 3920
490 times 9 is 4410
490 times 10 is 4900
490 times 11 is 5390
490 times 12 is 5880
490 times 13 is 6370
490 times 14 is 6860
490 times 15 is 7350
490 times 16 is 7840
490 times 17 is 8330
490 times 18 is 8820
490 times 19 is 9310
490 times 20 is 9800

Table of 490 in Words

The Table of 490 in words describes multiplication results in easy sentences for clear learning.

Four hundred ninety times one is four hundred ninety
Four hundred ninety times two is nine hundred eighty
Four hundred ninety times three is one thousand four hundred seventy
Four hundred ninety times four is one thousand nine hundred sixty
Four hundred ninety times five is two thousand four hundred fifty
Four hundred ninety times six is two thousand nine hundred forty
Four hundred ninety times seven is three thousand four hundred thirty
Four hundred ninety times eight is three thousand nine hundred twenty
Four hundred ninety times nine is four thousand four hundred ten
Four hundred ninety times ten is four thousand nine hundred
Four hundred ninety times eleven is five thousand three hundred ninety
Four hundred ninety times twelve is five thousand eight hundred eighty
Four hundred ninety times thirteen is six thousand three hundred seventy
Four hundred ninety times fourteen is six thousand eight hundred sixty
Four hundred ninety times fifteen is seven thousand three hundred fifty
Four hundred ninety times sixteen is seven thousand eight hundred forty
Four hundred ninety times seventeen is eight thousand three hundred thirty
Four hundred ninety times eighteen is eight thousand eight hundred twenty
Four hundred ninety times nineteen is nine thousand three hundred ten
Four hundred ninety times twenty is nine thousand eight hundred

Table of 490 Using The Repeated Addition Method

The Table of 490 using the repeated addition method explains multiplication by adding 490 repeatedly.

Solved Examples on the Table of 490

Example 1: A factory produces 1,960 safety helmets and packs them equally into boxes. Each box can hold 490 helmets. How many boxes are needed?

Solution:

Total helmets = 1,960

Helmets per box = 490

Using the table of 490:

490 × 4 = 1,960

Answer: 4 boxes are required.

Example 2: A warehouse stores cartons in stacks. Each stack contains 490 cartons. If there are 6 such stacks, how many cartons are there in total?

Solution:

Number of stacks = 6

Cartons in each stack = 490

Using multiplication:

490 × 6 = 2,940

Answer: There are 2,940 cartons in total.

Example 3: A company manufactures items in batches of 490. It produces 8 batches in a day. If 120 items are damaged, how many good items remain?

Solution:

Total items produced = 490 × 8 = 3,920

Damaged items = 120

Remaining items = 3,920 − 120 = 3,800

Answer: 3,800 items remain undamaged.

Example 4: A school buys 3 sets of books. Each set contains 5 bundles, and each bundle has 490 books. How many books does the school buy?

Solution:

Books in one set = 5 × 490 = 2,450

Total books = 3 × 2,450 = 7,350

Answer: The school buys 7,350 books.

Example 5: A store receives 490 × 10 items in a shipment. If 350 items are returned due to defects, how many items are left in the store?

Solution:

Total items received = 490 × 10 = 4,900

Returned items = 350

Remaining items = 4,900 − 350 = 4,550

Answer: 4,550 items are left in the store.

Learn More Multiplication Tables

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Table of 488	Table of 489	Table of 491	Table of 492
Table of 493	Table of 494	Table of 495	Table of 496
Table of 497	Table of 498	Table of 499	Table of 500