Dividing Line Segment in Given Ratio
In coordinate geometry, we use the section formula to find the point that divides a line segment in a given ratio. In construction geometry, the same division is performed using only a ruler and compass.
The construction is based on the Basic Proportionality Theorem (BPT). By drawing parallel lines through equally spaced points, we create proportional divisions on any given line segment.
This construction is a prerequisite for constructing similar triangles and tangents to circles, both of which are NCERT Class 10 topics.
What is Dividing Line Segment in Given Ratio?
Definition: Dividing a line segment in a given ratio m : n means locating a point P on segment AB such that AP : PB = m : n.
Key facts:
- The point P lies between A and B (internal division).
- AP and PB together equal the full length AB.
- The construction uses BPT: a line drawn parallel to one side of a triangle divides the other two sides proportionally.
- No measurement of length is needed — only equal arcs on a ray.
Principle: If we mark (m + n) equal divisions on an auxiliary ray from A, and join the last point to B, then a line through the m-th point drawn parallel to this joining line will meet AB at the required point P.
Dividing Line Segment in Given Ratio Formula
Underlying Section Formula (Coordinate Geometry):
P = ((mx₂ + nx₁)/(m + n), (my₂ + ny₁)/(m + n))
Where:
- A = (x₁, y₁) and B = (x₂, y₂) are the endpoints
- m : n is the given ratio
- P is the dividing point
In construction, we achieve this division geometrically without coordinates, using only compass and straightedge.
Derivation and Proof
Justification of the Construction (Using BPT):
- Let the line segment be AB and the required ratio be m : n.
- Draw ray AX making an acute angle with AB.
- Mark (m + n) equal points A₁, A₂, ..., A_{m+n} on AX using a compass with a fixed radius.
- Join A_{m+n} to B.
- Through Aₘ (the m-th point), draw a line parallel to A_{m+n}B, meeting AB at point P.
- In triangle AA_{m+n}B, the line through Aₘ is parallel to A_{m+n}B.
- By BPT: AA_m / A_mA_{m+n} = AP / PB.
- Since all divisions on AX are equal: AA_m = m units and A_mA_{m+n} = n units.
- Therefore, AP / PB = m / n. This is the required ratio.
Types and Properties
Types of Division:
- Internal Division: Point P lies between A and B. The construction described above performs internal division. AP : PB = m : n.
- External Division: Point P lies on the extension of AB beyond B (or beyond A). For external division in ratio m : n, the construction marks |m − n| points and uses a modified approach.
Common Ratios in Class 10 Problems:
| Ratio m : n | Total Points on Ray | Parallel Through |
|---|---|---|
| 1 : 1 (midpoint) | 2 | 1st point |
| 2 : 3 | 5 | 2nd point |
| 3 : 2 | 5 | 3rd point |
| 3 : 4 | 7 | 3rd point |
| 1 : 3 | 4 | 1st point |
Alternative Construction (Two Rays):
- Draw rays AX and BY on opposite sides of AB, both making acute angles.
- Mark m equal parts on AX and n equal parts on BY.
- Join the m-th point on AX to the n-th point on BY.
- The intersection with AB gives point P such that AP : PB = m : n.
Methods
Construction Steps — Divide AB in Ratio m : n (Single Ray Method):
- Draw a line segment AB of given length.
- Draw a ray AX making an acute angle with AB (angle can be any convenient acute angle, typically 30°–60°).
- Using a compass with any convenient radius, mark (m + n) equal arcs on ray AX. Label the points as A₁, A₂, ..., A_{m+n}.
- Join A_{m+n} to B with a straight line.
- Through point Aₘ, draw a line parallel to A_{m+n}B. (Use corresponding angle construction or alternate interior angle construction.)
- This parallel line intersects AB at point P.
- P divides AB in the ratio m : n.
How to draw a parallel line (Step 5 detail):
- With A_{m+n} as centre, draw an arc cutting A_{m+n}B and A_{m+n}A_m.
- With the same radius and Aₘ as centre, draw an arc cutting the ray through Aₘ.
- Set compass to the chord of the first arc.
- Mark the same chord on the second arc.
- Draw the line through Aₘ and this new point — it is parallel to A_{m+n}B.
Accuracy Tips for Construction:
- Use a sharp pencil (0.5 mm mechanical pencil recommended) for marking points.
- Keep the compass width constant throughout the arc-marking step — do not adjust the compass between arcs.
- The acute angle should be between 30° and 60° for best accuracy. Very small or very large angles compress the construction.
- When drawing the parallel line, use the corresponding angle method rather than "eyeballing" — geometric accuracy depends on this step.
- Mark points clearly and label them A₁, A₂, ... to avoid counting errors.
Common Mistakes to Avoid:
- Unequal arcs: If the compass slips between marking successive arcs, the divisions will be unequal and the ratio will be wrong.
- Wrong point for parallel: For ratio m : n, the parallel goes through the m-th point (not the n-th). Confusing m and n reverses the ratio.
- Missing the parallel: The parallel line must accurately replicate the angle — any error here shifts the dividing point.
- Not extending far enough: When using the two-ray method, ensure the rays are long enough for the arcs to be clearly marked.
Checking Your Construction:
- After construction, measure AP and PB with a ruler.
- Compute AP/PB. It should equal m/n (within ±0.1 cm tolerance).
- If the ratio is significantly off, identify which step introduced the error (usually the parallel line).
Solved Examples
Example 1: Divide a Segment in Ratio 2 : 3
Problem: Divide a line segment AB = 7 cm in the ratio 2 : 3.
Solution:
Given:
- AB = 7 cm, ratio = 2 : 3
- m = 2, n = 3, so m + n = 5
Steps:
- Draw AB = 7 cm.
- Draw ray AX at an acute angle to AB.
- Mark 5 equal arcs on AX: A₁, A₂, A₃, A₄, A₅.
- Join A₅ to B.
- Through A₂, draw a line parallel to A₅B, meeting AB at P.
Result: AP : PB = 2 : 3.
Verification: AP = 7 × 2/5 = 2.8 cm, PB = 7 × 3/5 = 4.2 cm. Ratio = 2.8 : 4.2 = 2 : 3. Confirmed.
Example 2: Divide a Segment in Ratio 3 : 1
Problem: Divide a line segment PQ = 8 cm in the ratio 3 : 1.
Solution:
Given:
- PQ = 8 cm, ratio = 3 : 1
- m = 3, n = 1, so m + n = 4
Steps:
- Draw PQ = 8 cm.
- Draw ray PX at an acute angle to PQ.
- Mark 4 equal arcs on PX: P₁, P₂, P₃, P₄.
- Join P₄ to Q.
- Through P₃, draw a line parallel to P₄Q, meeting PQ at R.
Result: PR : RQ = 3 : 1.
Verification: PR = 8 × 3/4 = 6 cm, RQ = 8 × 1/4 = 2 cm. Ratio = 6 : 2 = 3 : 1. Confirmed.
Example 3: Divide a Segment in Ratio 1 : 1 (Midpoint)
Problem: Find the midpoint of line segment MN = 10 cm by construction.
Solution:
Given:
- MN = 10 cm, ratio = 1 : 1 (midpoint)
- m = 1, n = 1, so m + n = 2
Steps:
- Draw MN = 10 cm.
- Draw ray MX at an acute angle to MN.
- Mark 2 equal arcs on MX: M₁, M₂.
- Join M₂ to N.
- Through M₁, draw a line parallel to M₂N, meeting MN at O.
Result: MO : ON = 1 : 1. So O is the midpoint.
Verification: MO = ON = 10/2 = 5 cm. Confirmed.
Example 4: Divide a Segment in Ratio 3 : 4
Problem: Divide a line segment AB = 10.5 cm in the ratio 3 : 4.
Solution:
Given:
- AB = 10.5 cm, ratio = 3 : 4
- m = 3, n = 4, so m + n = 7
Steps:
- Draw AB = 10.5 cm.
- Draw ray AX at an acute angle to AB.
- Mark 7 equal arcs on AX: A₁, A₂, A₃, A₄, A₅, A₆, A₇.
- Join A₇ to B.
- Through A₃, draw a line parallel to A₇B, meeting AB at P.
Result: AP : PB = 3 : 4.
Verification: AP = 10.5 × 3/7 = 4.5 cm, PB = 10.5 × 4/7 = 6 cm. Ratio = 4.5 : 6 = 3 : 4. Confirmed.
Example 5: Alternative Construction Using Two Rays
Problem: Divide XY = 6 cm in the ratio 2 : 3 using the two-ray method.
Solution:
Given:
- XY = 6 cm, ratio = 2 : 3
Steps:
- Draw XY = 6 cm.
- Draw ray XA making an acute angle on one side of XY.
- Draw ray YB making an acute angle on the opposite side of XY (such that XA and YB are on opposite sides).
- Mark 2 equal arcs on XA: X₁, X₂.
- Mark 3 equal arcs on YB: Y₁, Y₂, Y₃.
- Join X₂ to Y₃. This line meets XY at point P.
Result: XP : PY = 2 : 3.
Verification: XP = 6 × 2/5 = 2.4 cm, PY = 6 × 3/5 = 3.6 cm. Ratio = 2.4 : 3.6 = 2 : 3. Confirmed.
Example 6: Constructing a Point that Divides in Ratio 4 : 1
Problem: Divide AB = 12.5 cm in the ratio 4 : 1.
Solution:
Given:
- AB = 12.5 cm, ratio = 4 : 1
- m = 4, n = 1, so m + n = 5
Steps:
- Draw AB = 12.5 cm.
- Draw ray AX at an acute angle to AB.
- Mark 5 equal arcs on AX: A₁, A₂, A₃, A₄, A₅.
- Join A₅ to B.
- Through A₄, draw a line parallel to A₅B, meeting AB at P.
Result: AP : PB = 4 : 1.
Verification: AP = 12.5 × 4/5 = 10 cm, PB = 12.5 × 1/5 = 2.5 cm. Ratio = 10 : 2.5 = 4 : 1. Confirmed.
Example 7: Coordinate Geometry Verification
Problem: A line segment has endpoints A(1, 2) and B(6, 7). Construct (conceptually) and verify the point dividing AB in ratio 2 : 3.
Solution:
Given:
- A = (1, 2), B = (6, 7), ratio = 2 : 3
Using Section Formula:
- x = (2 × 6 + 3 × 1)/(2 + 3) = (12 + 3)/5 = 15/5 = 3
- y = (2 × 7 + 3 × 2)/(2 + 3) = (14 + 6)/5 = 20/5 = 4
Result: P = (3, 4).
Verification:
- AP = √((3−1)² + (4−2)²) = √(4 + 4) = √8 = 2√2
- PB = √((6−3)² + (7−4)²) = √(9 + 9) = √18 = 3√2
- AP : PB = 2√2 : 3√2 = 2 : 3. Confirmed.
Example 8: Why Any Convenient Compass Width Works
Problem: Explain why the arc width on the ray AX can be any convenient width.
Solution:
Key Insight: The construction depends on equal spacing, not on exact distances.
- BPT uses ratios, not absolute lengths.
- If all (m + n) arcs have the same radius r, then AA_m = mr and A_mA_{m+n} = nr.
- The ratio AA_m : A_mA_{m+n} = mr : nr = m : n, regardless of r.
- A larger r makes the construction easier to draw accurately, but the ratio is the same.
Answer: The compass width cancels out in the ratio. Only equal spacing matters, not the size of each step.
Example 9: Divide in Ratio 5 : 2
Problem: Divide a line segment CD = 14 cm in the ratio 5 : 2.
Solution:
Given:
- CD = 14 cm, ratio = 5 : 2
- m = 5, n = 2, so m + n = 7
Steps:
- Draw CD = 14 cm.
- Draw ray CX at an acute angle to CD.
- Mark 7 equal arcs on CX: C₁, C₂, C₃, C₄, C₅, C₆, C₇.
- Join C₇ to D.
- Through C₅, draw a line parallel to C₇D, meeting CD at P.
Result: CP : PD = 5 : 2.
Verification: CP = 14 × 5/7 = 10 cm, PD = 14 × 2/7 = 4 cm. Ratio = 10 : 4 = 5 : 2. Confirmed.
Example 10: NCERT-Style Exam Problem
Problem: Draw a line segment of length 7.6 cm and divide it in the ratio 5 : 8. Measure the two parts. (NCERT Exercise 11.1, Q1)
Solution:
Given:
- AB = 7.6 cm, ratio = 5 : 8
- m = 5, n = 8, so m + n = 13
Steps:
- Draw AB = 7.6 cm.
- Draw ray AX at an acute angle to AB.
- Mark 13 equal arcs on AX (use a small compass width since 13 arcs are needed).
- Join A₁₃ to B.
- Through A₅, draw a line parallel to A₁₃B, meeting AB at P.
Result: AP : PB = 5 : 8.
Expected Measurements:
- AP = 7.6 × 5/13 ≈ 2.92 cm (approximately 2.9 cm on measurement)
- PB = 7.6 × 8/13 ≈ 4.68 cm (approximately 4.7 cm on measurement)
Note: Small measurement errors (±0.1 cm) are acceptable in constructions.
Real-World Applications
Foundation for Other Constructions:
- Constructing a triangle similar to a given triangle requires dividing a side in a given ratio first.
- Constructing tangents from an external point uses midpoint construction (ratio 1 : 1).
Engineering and Design:
- Dividing beams, rods, or planks into proportional parts for structural design.
- Scaling architectural drawings — enlarging or reducing proportions of blueprints.
Map Making (Cartography):
- Locating a point at a fractional distance between two landmarks.
Computer Graphics:
- Linear interpolation between two points uses the same principle digitally.
- Bezier curves use repeated division of segments in given ratios.
Division of Inheritance:
- Dividing a plot of land in a given ratio among heirs uses the same principle geometrically.
Music:
- Fret positions on a guitar divide the string in specific ratios to produce different notes.
Art and Design:
- The golden ratio (approximately 1 : 1.618) divides a line segment aesthetically. While irrational ratios cannot be constructed exactly, close integer approximations (like 5 : 8) can be constructed using this method.
Manufacturing:
- Cutting rods, pipes, or fabric into proportional pieces requires dividing a length in a given ratio. The geometric method can be used when precision tools are unavailable.
Key Points to Remember
- The construction divides a line segment AB in a given ratio m : n using only ruler and compass.
- It is based on the Basic Proportionality Theorem (BPT).
- Draw a ray at an acute angle and mark (m + n) equal arcs on it.
- Join the last marked point to B, then draw a parallel through the m-th point.
- The compass width for arcs can be any convenient length — only equality matters.
- The alternative method uses two rays on opposite sides of AB with m arcs on one and n on the other.
- This construction is a prerequisite for constructing similar triangles.
- In coordinate geometry, the same division is given by the section formula.
- The point of division always lies between A and B for internal division.
- Construction accuracy depends on careful drawing of the parallel line.
Practice Problems
- Draw a line segment of length 8 cm and divide it in the ratio 3 : 2. Measure and verify the two parts.
- Divide a line segment of length 9.4 cm in the ratio 2 : 5. What are the expected lengths of each part?
- Divide a line segment AB = 11 cm in the ratio 4 : 7 using the construction method.
- Using the two-ray method, divide a segment PQ = 6.6 cm in the ratio 3 : 4.
- A line segment of length 10 cm is divided in the ratio 1 : 4. What is the distance of the dividing point from each endpoint?
- Draw a line segment of length 7 cm and find its midpoint using the division construction (ratio 1 : 1).
- Divide AB = 12 cm in ratio 5 : 3. Verify using the section formula that the dividing point lies at distance 7.5 cm from A.
- If you need to divide a segment in the ratio 7 : 5, how many equal arcs must you mark on the ray? At which point do you draw the parallel?
Frequently Asked Questions
Q1. Why do we draw a ray at an acute angle and not at a right angle?
An acute angle ensures the marked points on the ray are spread out, making the construction more accurate. A very large angle (close to 90°) would compress the parallel line construction and reduce precision. Any acute angle works — 30° to 60° is most convenient.
Q2. Does the compass width used for marking arcs affect the result?
No. The result depends only on the number of equal divisions, not on the compass width. A larger width makes the construction easier to draw but the ratio stays the same because BPT depends on ratios of equal parts.
Q3. How is this construction related to BPT?
The construction creates a triangle where a line through the m-th point is drawn parallel to the base. By BPT, this parallel line divides the other two sides (including AB) in the same ratio as the segments on the ray, which is m : n.
Q4. Can we divide a segment in any ratio using this method?
Yes, any ratio m : n where m and n are positive integers. For irrational ratios (like 1 : √2), exact construction is not possible with ruler and compass alone.
Q5. What is the difference between dividing a segment and finding a point using the section formula?
The section formula is an algebraic method that gives the coordinates of the dividing point. The construction is a geometric method using ruler and compass that physically locates the point on the segment. Both achieve the same result.
Q6. How do we draw a line parallel to another in this construction?
Use the corresponding angles method: with the last point as centre, draw an arc cutting both lines. Transfer the same arc and chord to the m-th point. The new line through that point is parallel to the original.
Q7. What are common errors in this construction?
Common errors include: (1) unequal arcs on the ray (compass width changed accidentally), (2) inaccurate parallel line (angle not copied correctly), (3) counting error in the number of arcs, (4) drawing the parallel through the wrong point.
Q8. Is this construction asked in CBSE board exams?
Yes. Questions typically ask to divide a given segment in a specified ratio (e.g., 3 : 5) with proper construction steps and justification using BPT. It carries 3–4 marks.
Q9. Can we divide a segment into three equal parts using this construction?
Yes. Use ratio 1 : 2 to get the first division point, and ratio 2 : 1 to get the second. Alternatively, mark 3 equal arcs, draw the parallel through the 1st point (ratio 1 : 2) and through the 2nd point (ratio 2 : 1).
Q10. What is the two-ray method?
Instead of one ray, draw two rays — AX from A and BY from B — on opposite sides of AB. Mark m equal parts on AX and n equal parts on BY. Joining the m-th point to the n-th point gives the dividing point where this line crosses AB.










