Similar Triangles
Similar triangles are one of the most important concepts in Euclidean geometry and a central topic in the CBSE Class 10 Mathematics curriculum under the chapter on Triangles. Two triangles are similar when they have the same shape but not necessarily the same size. This means their corresponding angles are equal and their corresponding sides are in proportion. The concept of similarity extends the idea of congruence (same shape AND same size) to a more general framework where scaling is allowed. Understanding similar triangles is essential because it provides powerful tools for indirect measurement, shadow problems, height-and-distance calculations, and map-making. The chapter builds on the Basic Proportionality Theorem (Thales' Theorem) and introduces several criteria for establishing similarity between triangles: AAA, AA, SSS, and SAS. These criteria allow students to prove that triangles are similar without checking all six conditions (three angle pairs and three side ratios).
What is Similar Triangles - Definition, Theorems, Criteria, Examples & FAQs?
Similar Triangles: Two triangles are said to be similar if:
(i) Their corresponding angles are equal, AND
(ii) Their corresponding sides are in the same ratio (proportional).
If triangle ABC is similar to triangle DEF, we write: triangle ABC ~ triangle DEF (the symbol ~ denotes similarity).
This means:
Angle A = Angle D, Angle B = Angle E, Angle C = Angle F
AND
AB/DE = BC/EF = CA/FD = k (where k is the scale factor)
Order of Vertices Matters: When writing triangle ABC ~ triangle DEF, the order indicates the correspondence: A corresponds to D, B corresponds to E, and C corresponds to F. Writing the similarity with incorrect vertex correspondence is wrong, even if the triangles are similar. For example, if Angle A = Angle E, Angle B = Angle D, Angle C = Angle F, then the correct notation is triangle ABC ~ triangle EDF, NOT triangle ABC ~ triangle DEF.
Scale Factor: The common ratio k = AB/DE = BC/EF = CA/FD is called the scale factor of the similarity. If k = 1, the triangles are congruent (same size). If k > 1, triangle ABC is larger. If k < 1, triangle ABC is smaller.
Distinction Between Similar and Congruent:
All congruent triangles are similar (with scale factor 1), but similar triangles are not necessarily congruent. Similarity preserves shape; congruence preserves both shape and size.
Basic Proportionality Theorem (BPT) / Thales' Theorem:
If a line is drawn parallel to one side of a triangle, it divides the other two sides proportionally. That is, if DE is parallel to BC in triangle ABC (with D on AB and E on AC), then AD/DB = AE/EC. The converse is also true: if a line divides two sides of a triangle in the same ratio, then the line is parallel to the third side.
Properties of Similar Triangles:
(i) Corresponding angles of similar triangles are equal.
(ii) Corresponding sides are proportional.
(iii) The ratio of areas of two similar triangles equals the square of the ratio of their corresponding sides: Area(ABC)/Area(DEF) = (AB/DE)^2 = (BC/EF)^2 = (CA/FD)^2.
(iv) The ratio of perimeters equals the ratio of corresponding sides.
(v) The ratio of corresponding altitudes, medians, and angle bisectors equals the ratio of corresponding sides.
Similar Triangles Formula
Criteria for Similarity of Triangles:
1. AA (Angle-Angle) Criterion:
If two angles of one triangle are equal to two angles of another triangle, the triangles are similar.
If Angle A = Angle D and Angle B = Angle E, then triangle ABC ~ triangle DEF.
(The third pair of angles is automatically equal since angles of a triangle sum to 180 degrees.)
2. SSS (Side-Side-Side) Similarity Criterion:
If the corresponding sides of two triangles are in the same ratio, the triangles are similar.
If AB/DE = BC/EF = CA/FD, then triangle ABC ~ triangle DEF.
3. SAS (Side-Angle-Side) Similarity Criterion:
If one pair of corresponding sides are in the same ratio and the included angles are equal, the triangles are similar.
If AB/DE = AC/DF and Angle A = Angle D, then triangle ABC ~ triangle DEF.
Area Ratio Formula:
If triangle ABC ~ triangle DEF with scale factor k, then:
Area(ABC) / Area(DEF) = k^2 = (AB/DE)^2 = (BC/EF)^2 = (CA/FD)^2
Basic Proportionality Theorem (BPT):
If DE is parallel to BC in triangle ABC (D on AB, E on AC), then:
AD/DB = AE/EC
Equivalently: AD/AB = AE/AC and DB/AB = EC/AC
Pythagoras Theorem as a Special Case:
In a right triangle with the altitude drawn from the right angle to the hypotenuse, three similar triangles are formed. This leads to the Pythagoras theorem: In a right-angled triangle, the square of the hypotenuse equals the sum of squares of the other two sides.
If angle B = 90 degrees in triangle ABC, then AC^2 = AB^2 + BC^2.
Derivation and Proof
Let us derive the AA (Angle-Angle) Similarity Criterion, which is the most fundamental similarity criterion.
Theorem (AA Criterion): If in two triangles, two pairs of corresponding angles are equal, then the two triangles are similar.
Given: In triangle ABC and triangle DEF, Angle A = Angle D and Angle B = Angle E.
To Prove: Triangle ABC ~ Triangle DEF, i.e., AB/DE = BC/EF = CA/FD.
Construction: On ray DE, mark a point P such that DP = AB. On ray DF, mark a point Q such that DQ = AC. Join PQ.
Proof:
Step 1: In triangle ABC and triangle DPQ:
AB = DP (by construction)
Angle A = Angle D (given)
AC = DQ (by construction)
Therefore, triangle ABC is congruent to triangle DPQ (by SAS congruence criterion).
Step 2: From the congruence in Step 1:
Angle B = Angle DPQ (corresponding parts of congruent triangles)
But Angle B = Angle E (given)
Therefore, Angle DPQ = Angle E ... (i)
Step 3: In triangle DEF, since Angle DPQ = Angle DEF [from (i)], and these are corresponding angles formed by the transversal DE cutting lines PQ and EF, the line PQ is parallel to EF.
Step 4: Since PQ is parallel to EF in triangle DEF (with P on DE and Q on DF), by the Basic Proportionality Theorem:
DP/DE = DQ/DF ... (ii)
Step 5: But DP = AB and DQ = AC (by construction). Substituting in (ii):
AB/DE = AC/DF ... (iii)
Step 6: Similarly, by taking a different construction (marking points on sides DE and EF), we can show:
AB/DE = BC/EF ... (iv)
Step 7: From (iii) and (iv):
AB/DE = BC/EF = CA/FD
This, combined with the equal angles (Angle A = Angle D, Angle B = Angle E, and hence Angle C = Angle F since angle sum = 180 degrees), proves that triangle ABC ~ triangle DEF. QED.
Derivation of the Area Ratio Theorem:
If triangle ABC ~ triangle DEF with AB/DE = BC/EF = CA/FD = k, then:
Draw altitudes AM from A to BC and DN from D to EF.
In triangles ABM and DEN:
Angle ABM = Angle DEN (since Angle B = Angle E)
Angle AMB = Angle DNE = 90 degrees
Therefore triangle ABM ~ triangle DEN (AA criterion)
So AM/DN = AB/DE = k
Area(ABC)/Area(DEF) = (1/2 * BC * AM) / (1/2 * EF * DN)
= (BC/EF) * (AM/DN)
= k * k = k^2
Therefore, the ratio of areas of similar triangles is the square of the ratio of corresponding sides.
Types and Properties
Similar triangles manifest in several geometric configurations and problem types in Class 10.
1. Triangles Made Similar by Parallel Lines:
When a line is drawn parallel to one side of a triangle, it creates a smaller triangle similar to the original. In triangle ABC, if DE is parallel to BC (D on AB, E on AC), then triangle ADE ~ triangle ABC by the AA criterion (Angle ADE = Angle ABC as corresponding angles, and Angle A is common). This is the most fundamental configuration.
2. Triangles in an X-Configuration (Two Secants):
When two lines intersect inside or outside two parallel lines, the resulting triangles are similar. If lines AB and CD intersect at point P, and AB is parallel to CD (or if angle APD = angle BPC as vertically opposite angles), triangles can be proved similar using AA.
3. Right Triangle Altitude Similarity:
In a right triangle ABC with the right angle at B, if an altitude BD is drawn to the hypotenuse AC, three similar triangles are created: triangle ABC ~ triangle ADB ~ triangle BDC. This configuration is crucial for deriving the Pythagoras theorem using similarity.
4. Shadow and Height Problems:
When the sun casts shadows, a person and their shadow form a right triangle similar to a pole and its shadow (since the sun's rays are parallel, creating equal angles). If a person of height h1 casts a shadow of length s1, and a pole of height h2 casts a shadow of length s2 at the same time, then h1/h2 = s1/s2.
5. Map and Scale Model Problems:
Maps and scale models are practical applications of similar triangles. If a map has a scale of 1:50000, every 1 cm on the map represents 50000 cm (500 m) on the ground. The triangles formed by distances on the map are similar to the actual triangles on the ground.
6. Overlapping Similar Triangles:
In many geometric proofs, similar triangles share a common vertex or side. For instance, two triangles sharing a vertex with one side of each lying along the same line create a configuration where AA similarity can be established.
7. Triangles Similar by SSS Criterion:
When all three pairs of corresponding sides are in the same ratio, the triangles are similar. This is often used when the problem provides all six side lengths and asks to check similarity.
8. Triangles Similar by SAS Criterion:
When two sides are proportional and the included angle is equal, the triangles are similar. This criterion is particularly useful when angle information is limited to the included angle.
Solved Examples
Example 1: Example 1: Proving Similarity Using AA Criterion
Problem: In triangle ABC, DE is drawn parallel to BC with D on AB and E on AC. If AD = 3 cm, DB = 5 cm, and AE = 4.5 cm, find EC.
Solution:
Since DE is parallel to BC, by the Basic Proportionality Theorem:
AD/DB = AE/EC
3/5 = 4.5/EC
EC = 4.5 x 5/3 = 22.5/3 = 7.5 cm
Also, triangle ADE ~ triangle ABC (by AA criterion: Angle A is common, Angle ADE = Angle ABC as corresponding angles).
Answer: EC = 7.5 cm.
Example 2: Example 2: Using SSS Similarity
Problem: In triangle ABC, AB = 4.5 cm, BC = 6 cm, CA = 7.5 cm. In triangle PQR, PQ = 3 cm, QR = 4 cm, RP = 5 cm. Are the triangles similar? If yes, write the similarity and find the scale factor.
Solution:
Check the ratios of corresponding sides:
AB/PQ = 4.5/3 = 3/2
BC/QR = 6/4 = 3/2
CA/RP = 7.5/5 = 3/2
Since AB/PQ = BC/QR = CA/RP = 3/2, by the SSS similarity criterion, the triangles are similar.
Triangle ABC ~ Triangle PQR with scale factor k = 3/2.
Answer: Yes, triangle ABC ~ triangle PQR with scale factor 3/2.
Example 3: Example 3: Using SAS Similarity
Problem: In triangles ABC and DEF, AB = 6 cm, AC = 8 cm, Angle A = 50 degrees, DE = 3 cm, DF = 4 cm, and Angle D = 50 degrees. Are the two triangles similar?
Solution:
Check the SAS criterion:
AB/DE = 6/3 = 2
AC/DF = 8/4 = 2
Angle A = Angle D = 50 degrees (included angle between the proportional sides)
Since two pairs of corresponding sides are in the same ratio (2:1) and the included angles are equal, by the SAS similarity criterion:
Triangle ABC ~ Triangle DEF.
Answer: Yes, triangle ABC ~ triangle DEF by SAS similarity.
Example 4: Example 4: Finding Sides Using Similarity
Problem: Triangles ABC and PQR are similar such that AB/PQ = 2/3. If AB = 8 cm and BC = 12 cm, find PQ and QR.
Solution:
Given: Triangle ABC ~ Triangle PQR and AB/PQ = 2/3.
Since the triangles are similar, all corresponding sides are in the same ratio:
AB/PQ = BC/QR = CA/PR = 2/3
Finding PQ:
8/PQ = 2/3
PQ = 8 x 3/2 = 12 cm
Finding QR:
12/QR = 2/3
QR = 12 x 3/2 = 18 cm
Answer: PQ = 12 cm and QR = 18 cm.
Example 5: Example 5: Area Ratio of Similar Triangles
Problem: The sides of two similar triangles are in the ratio 4:9. Find the ratio of their areas.
Solution:
If two triangles are similar and the ratio of their corresponding sides is k, then the ratio of their areas is k^2.
Given ratio of sides = 4:9 = 4/9.
Ratio of areas = (4/9)^2 = 16/81
Answer: The ratio of their areas is 16:81.
Example 6: Example 6: Shadow Problem
Problem: At a certain time of day, a 1.5 m tall person casts a shadow of 3 m. At the same time, a tower casts a shadow of 40 m. Find the height of the tower.
Solution:
Since the sun's rays are parallel, the angle of elevation of the sun is the same for both the person and the tower. This creates two similar right triangles.
Let the height of the tower be h metres.
By similarity:
Height of person / Height of tower = Shadow of person / Shadow of tower
1.5 / h = 3 / 40
h = 1.5 x 40 / 3 = 60 / 3 = 20 m
Answer: The height of the tower is 20 m.
Example 7: Example 7: Right Triangle Altitude Problem
Problem: In a right triangle ABC, angle B = 90 degrees. BD is the altitude from B to hypotenuse AC. If AD = 4 cm and DC = 9 cm, find BD.
Solution:
When an altitude is drawn from the right angle vertex to the hypotenuse, three similar triangles are formed:
Triangle ADB ~ Triangle BDC (both are similar to triangle ABC).
From triangle ADB ~ triangle BDC:
AD/BD = BD/DC (corresponding sides of similar triangles)
Therefore: BD^2 = AD x DC
BD^2 = 4 x 9 = 36
BD = sqrt(36) = 6 cm
Answer: BD = 6 cm.
Note: This result, BD^2 = AD x DC, is called the geometric mean relationship and is a direct consequence of the similarity of the triangles formed by the altitude to the hypotenuse.
Example 8: Example 8: Proving Triangles Similar in a Geometric Figure
Problem: In the given figure, ABCD is a trapezium with AB parallel to DC. Diagonals AC and BD intersect at point O. Prove that triangle AOB ~ triangle COD.
Solution:
In triangles AOB and COD:
Angle AOB = Angle COD (vertically opposite angles) ... (i)
Since AB is parallel to DC, and AC is a transversal:
Angle OAB = Angle OCD (alternate interior angles) ... (ii)
Since AB is parallel to DC, and BD is a transversal:
Angle OBA = Angle ODC (alternate interior angles) ... (iii)
From (i), (ii), and (iii), all three pairs of corresponding angles are equal.
By the AA criterion (we actually only need two pairs):
Triangle AOB ~ Triangle COD. Proved.
Consequently, AO/CO = BO/DO = AB/CD.
Example 9: Example 9: Finding Area When Sides Are Given
Problem: Triangle ABC ~ Triangle DEF. The area of triangle ABC is 64 sq cm and the area of triangle DEF is 121 sq cm. If EF = 15.4 cm, find BC.
Solution:
For similar triangles:
Area(ABC)/Area(DEF) = (BC/EF)^2
64/121 = (BC/15.4)^2
Taking square root of both sides:
8/11 = BC/15.4
BC = 15.4 x 8/11 = 123.2/11 = 11.2 cm
Answer: BC = 11.2 cm.
Example 10: Example 10: Using BPT (Thales' Theorem)
Problem: In triangle PQR, a line parallel to QR intersects PQ at X and PR at Y. If PX = 4 cm, XQ = 6 cm, and PY = 6 cm, find YR. Also find PX/PQ and XY/QR.
Solution:
Since XY is parallel to QR, by the Basic Proportionality Theorem:
PX/XQ = PY/YR
4/6 = 6/YR
YR = 6 x 6/4 = 36/4 = 9 cm
PQ = PX + XQ = 4 + 6 = 10 cm
PX/PQ = 4/10 = 2/5
Since triangle PXY ~ triangle PQR (AA criterion: Angle P common, Angle PXY = Angle PQR):
XY/QR = PX/PQ = 2/5
Answer: YR = 9 cm, PX/PQ = 2/5, and XY/QR = 2/5.
Real-World Applications
Similar triangles have extensive applications in real-world measurement, engineering, and science.
Indirect Height Measurement: Before modern instruments, the height of tall structures like pyramids, towers, and cliffs was measured using similar triangles. By measuring the shadow of a stick of known height and the shadow of the structure at the same time, the height could be calculated proportionally. This technique was famously used by the Greek mathematician Thales to measure the height of the Great Pyramid of Giza around 600 BCE.
Surveying and Mapmaking: Cartographers use the principles of similar triangles to create accurate maps. Distances between locations on a map are proportional to actual distances, and the triangulation method (using similar triangles formed by known baseline distances and measured angles) allows surveyors to calculate distances to inaccessible points.
Architecture and Construction: Scale models of buildings are similar figures to the actual structures. Architects use these models to test designs. The ratio of areas (proportional to the square of the scale factor) is used to estimate material costs, and the ratio of volumes (cube of the scale factor) helps estimate concrete and space requirements.
Optics and Photography: The lens equation in optics relies on similar triangles formed by light rays passing through a lens. The magnification of an image (ratio of image height to object height) equals the ratio of image distance to object distance, which is derived from similar triangle relationships.
Navigation and Astronomy: Sailors historically used similar triangles to estimate their distance from shore by measuring angles. Astronomers use the same principle (parallax) to calculate the distance to nearby stars by measuring the angle they appear to shift when viewed from different positions in Earth's orbit.
Computer Graphics: Rendering 3D scenes on a 2D screen uses perspective projection, which is fundamentally based on similar triangles. Objects farther from the viewer appear smaller in proportion to their distance, following the rules of similar triangles.
Key Points to Remember
- Two triangles are similar if their corresponding angles are equal and corresponding sides are proportional. Notation: triangle ABC ~ triangle DEF (order of vertices indicates correspondence).
- The AA (Angle-Angle) criterion is the most commonly used: if two angles of one triangle equal two angles of another, the triangles are similar.
- SSS Similarity: If all three pairs of corresponding sides are proportional, the triangles are similar.
- SAS Similarity: If two pairs of corresponding sides are proportional and the included angles are equal, the triangles are similar.
- The Basic Proportionality Theorem (Thales' Theorem): A line parallel to one side of a triangle divides the other two sides proportionally.
- The ratio of areas of two similar triangles equals the square of the ratio of their corresponding sides: Area1/Area2 = (side1/side2)^2.
- All congruent triangles are similar, but similar triangles are not necessarily congruent.
- In a right triangle, the altitude from the right angle to the hypotenuse creates two smaller triangles, each similar to the original and to each other.
- The Pythagoras theorem can be proved using the concept of similar triangles formed by the altitude to the hypotenuse.
- For CBSE board exams, practice both proving triangles similar (using criteria) and using similarity to find unknown sides, angles, and areas.
Practice Problems
- In triangle ABC, DE is parallel to BC. AD = 2 cm, DB = 4 cm, AE = 3 cm. Find EC and the ratio DE/BC.
- Check whether triangle PQR with PQ = 2.5 cm, QR = 5 cm, RP = 6 cm is similar to triangle XYZ with XY = 5 cm, YZ = 10 cm, ZX = 12 cm.
- The areas of two similar triangles are 81 sq cm and 49 sq cm. If one side of the first triangle is 6.3 cm, find the corresponding side of the second triangle.
- In triangle ABC, angle B = 90 degrees and BD is perpendicular to AC. If AD = 8 cm and CD = 2 cm, find BD and AB.
- A vertical pole 6 m high casts a shadow 4 m long. At the same time, a tower casts a shadow 28 m long. Find the height of the tower.
- In triangle PQR, S and T are points on PQ and PR respectively such that ST is parallel to QR. If PS/SQ = 2/5, find the ratio of areas of triangle PST to triangle PQR.
- Prove that if a line is drawn parallel to one side of a triangle, the other two sides are divided proportionally (Prove BPT).
- Two isosceles triangles have equal vertical angles. Prove that they are similar.
Frequently Asked Questions
Q1. What are similar triangles?
Similar triangles are triangles that have the same shape but may differ in size. Two triangles are similar when their corresponding angles are equal and their corresponding sides are in the same ratio (proportional). The symbol ~ is used to denote similarity, e.g., triangle ABC ~ triangle DEF.
Q2. What is the difference between similar and congruent triangles?
Similar triangles have the same shape but can be different sizes (corresponding angles are equal, sides are proportional). Congruent triangles have both the same shape AND the same size (corresponding angles are equal AND corresponding sides are equal). All congruent triangles are similar (with scale factor 1), but not all similar triangles are congruent.
Q3. What are the criteria for similarity of triangles?
There are three criteria: (1) AA (Angle-Angle): If two angles of one triangle equal two angles of another. (2) SSS (Side-Side-Side): If all three pairs of corresponding sides are proportional. (3) SAS (Side-Angle-Side): If two pairs of sides are proportional and the included angles are equal. Any one criterion is sufficient to establish similarity.
Q4. What is the Basic Proportionality Theorem (BPT)?
The Basic Proportionality Theorem (also called Thales' Theorem) states that if a line is drawn parallel to one side of a triangle, it divides the other two sides in the same ratio. In triangle ABC, if DE is parallel to BC with D on AB and E on AC, then AD/DB = AE/EC.
Q5. How do you find the ratio of areas of two similar triangles?
If two triangles are similar with the ratio of corresponding sides being k, then the ratio of their areas is k^2 (the square of the side ratio). For example, if the sides are in ratio 3:5, the areas are in ratio 9:25.
Q6. Why does the order of vertices matter in similarity notation?
The order of vertices indicates which vertices correspond to each other. In triangle ABC ~ triangle PQR, vertex A corresponds to P, B to Q, and C to R. This means Angle A = Angle P, Angle B = Angle Q, Angle C = Angle R, and AB/PQ = BC/QR = CA/RP. Writing the vertices in wrong order would incorrectly match unequal angles and non-proportional sides.
Q7. How is the Pythagoras theorem related to similar triangles?
The Pythagoras theorem can be proved using similar triangles. In a right triangle ABC with right angle at B, drawing altitude BD to hypotenuse AC creates three similar triangles. From the similarity relations, AB^2 = AD x AC and BC^2 = DC x AC. Adding these: AB^2 + BC^2 = AC(AD + DC) = AC x AC = AC^2, which is the Pythagoras theorem.
Q8. Can two triangles be similar if they share no common angles?
If two triangles have no pair of equal corresponding angles, they cannot be similar. Similarity requires all three pairs of corresponding angles to be equal (and having two pairs equal automatically ensures the third pair is also equal since angle sum = 180 degrees). However, you only need to verify two pairs of equal angles to conclude similarity using the AA criterion.
Q9. What is the scale factor in similar triangles?
The scale factor is the common ratio of corresponding sides in similar triangles. If triangle ABC ~ triangle DEF, the scale factor k = AB/DE = BC/EF = CA/FD. A scale factor of 1 means the triangles are congruent. A scale factor greater than 1 means the first triangle is larger; less than 1 means it is smaller.
Q10. How are similar triangles used in real-life applications?
Similar triangles are used extensively in real life: (1) Measuring heights of tall objects using shadows. (2) Map-making and scale drawings. (3) Architectural models. (4) Surveying land using triangulation. (5) Optics (lens magnification). (6) Computer graphics for perspective rendering. (7) Navigation and astronomy for calculating distances to faraway objects.
Related Topics
- Basic Proportionality Theorem (BPT)
- Criteria for Similarity of Triangles
- AA Similarity Criterion
- Areas of Similar Triangles
- Angle Sum Property of Triangle
- Exterior Angle Property of Triangle
- Properties of Isosceles Triangle
- Properties of Equilateral Triangle
- Triangle Inequality Property
- Medians and Altitudes of Triangle
- Right-Angled Triangle Property
- Congruent Triangles - Proofs
- Inequalities in Triangles
- Converse of Basic Proportionality Theorem










