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Surface Area of Cone

Class 9Surface Areas and Volumes

A cone is a three-dimensional solid with a circular base that narrows smoothly to a point called the apex or vertex. The study of the surface area of a cone is part of the NCERT Class 9 chapter on Surface Areas and Volumes (Chapter 13).


The surface area of a cone consists of two distinct parts: the curved (lateral) surface area (CSA), which is the slanting surface from the base to the apex, and the area of the flat circular base. Together, they make up the total surface area (TSA).


Cones appear frequently in daily life — ice cream cones, traffic cones, party hats, funnels, teepee tents, and conical roofs on turrets are all cone-shaped objects. Calculating the surface area is essential in manufacturing (how much wafer is needed for an ice cream cone), packaging (material for conical containers), and construction (canvas for a tent).


An important concept in this topic is the slant height (l), which is different from the vertical height (h). The slant height is the distance from the apex to any point on the circumference of the base, and it is always greater than the height. The three quantities — radius (r), height (h), and slant height (l) — are related by the Pythagorean theorem: l² = r² + h².


When the curved surface of a cone is cut along the slant height and unrolled, it forms a sector of a circle. This geometric insight is the basis for deriving the CSA formula.

What is Surface Area of Cone?

Definition: A cone is a solid bounded by a flat circular base and a curved surface that tapers to a single point (apex).


The key measurements of a cone are:

  • r = radius of the circular base
  • h = height (perpendicular distance from the base to the apex)
  • l = slant height (distance from any point on the circumference of the base to the apex)

The relationship between these measurements is:

l² = r² + h²


Therefore:

  • l = √(r² + h²)
  • h = √(l² − r²)
  • r = √(l² − h²)

Important:

  • The slant height is always greater than the height of the cone.
  • A cone is a right circular cone if the apex is directly above the centre of the base.
  • When the curved surface is unrolled, it forms a sector of a circle with radius equal to the slant height.

Surface Area of Cone Formula

Key Formulas:


1. Slant Height:

l = √(r² + h²)


2. Curved Surface Area (CSA):

CSA = πrl


3. Total Surface Area (TSA):

TSA = πrl + πr² = πr(l + r)


Where:

  • r = radius of the base
  • l = slant height
  • h = vertical height
  • π = 22/7 or 3.14159...

Units:

  • If dimensions are in cm, the surface area is in cm².
  • If dimensions are in m, the surface area is in .

Derivation and Proof

Derivation of the Curved Surface Area of a Cone:


Step 1: Unroll the curved surface

  • When the curved surface of a cone is cut along the slant height and unrolled, it forms a sector of a circle.
  • The radius of this sector equals the slant height l of the cone.
  • The arc length of this sector equals the circumference of the base = 2πr.

Step 2: Find the area of the sector

  1. For a full circle of radius l: circumference = 2πl, area = πl².
  2. The sector has arc length = 2πr (the base circumference).
  3. The angle of the sector (in radians) = arc/radius = 2πr/l.
  4. Area of sector = ½ × l² × (2πr/l) = ½ × l × 2πr = πrl.

Alternatively, using proportions:

  • Area of sector / Area of full circle = Arc length / Full circumference
  • Area of sector / πl² = 2πr / 2πl
  • Area of sector = πl² × (r/l) = πrl

Step 3: Add the base area for TSA

  • Base area = πr²
  • TSA = CSA + Base area = πrl + πr² = πr(l + r)

Types and Properties

Types of surface area calculations for a cone:


1. Curved Surface Area (CSA) only

  • CSA = πrl
  • Used when the base is not covered (e.g., an open cone, a funnel, or a conical tent).

2. Total Surface Area (TSA)

  • TSA = πr(l + r)
  • Used when the cone is a solid with both the curved surface and the flat circular base (e.g., a solid traffic cone, a conical cap).

3. Frustum of a cone

  • A frustum is formed when a cone is cut by a plane parallel to the base.
  • CSA of frustum = π(r&sub1; + r&sub2;)l, where r&sub1; and r&sub2; are the two radii.
  • TSA of frustum = π(r&sub1; + r&sub2;)l + πr&sub1;² + πr&sub2;²
  • This is covered in Class 10.

4. When only height and radius are given

  • First compute slant height: l = √(r² + h²)
  • Then apply CSA or TSA formulas.

5. Half-cone (semicone)

  • CSA = ½ × πrl
  • This occurs in some advanced problems where only half the curved surface is considered.

Solved Examples

Example 1: Example 1: Finding CSA given radius and slant height

Problem: Find the curved surface area of a cone with radius 7 cm and slant height 10 cm. (Use π = 22/7)


Solution:

Given:

  • r = 7 cm, l = 10 cm

Using CSA = πrl:

  • CSA = (22/7) × 7 × 10
  • CSA = 22 × 10 = 220 sq cm

Answer: CSA = 220 sq cm.

Example 2: Example 2: Finding TSA given radius and slant height

Problem: Find the total surface area of a cone with radius 3.5 cm and slant height 6 cm. (Use π = 22/7)


Solution:

Given:

  • r = 3.5 cm, l = 6 cm

Using TSA = πr(l + r):

  • TSA = (22/7) × 3.5 × (6 + 3.5)
  • TSA = (22/7) × 3.5 × 9.5
  • TSA = 11 × 9.5 = 104.5 sq cm

Answer: TSA = 104.5 sq cm.

Example 3: Example 3: Finding CSA when height and radius are given

Problem: A cone has radius 6 cm and height 8 cm. Find its curved surface area. (Use π = 3.14)


Solution:

Given:

  • r = 6 cm, h = 8 cm

Step 1: Find slant height

  • l = √(r² + h²) = √(36 + 64) = √100 = 10 cm

Step 2: Find CSA

  • CSA = πrl = 3.14 × 6 × 10 = 188.4 sq cm

Answer: CSA = 188.4 sq cm.

Example 4: Example 4: Cost of canvas for a conical tent

Problem: A conical tent has a base diameter of 14 m and slant height 15 m. Find the cost of the canvas required at Rs 50 per sq m. (Use π = 22/7)


Solution:

Given:

  • Diameter = 14 m ⇒ r = 7 m
  • l = 15 m
  • Cost = Rs 50 per sq m

Step 1: Find CSA (tent has no base)

  • CSA = πrl = (22/7) × 7 × 15 = 22 × 15 = 330 sq m

Step 2: Find cost

  • Cost = 330 × 50 = Rs 16,500

Answer: Cost of canvas = Rs 16,500.

Example 5: Example 5: Finding slant height from CSA

Problem: The curved surface area of a cone is 308 sq cm and its radius is 7 cm. Find the slant height. (Use π = 22/7)


Solution:

Given:

  • CSA = 308 sq cm, r = 7 cm

Using CSA = πrl:

  1. 308 = (22/7) × 7 × l
  2. 308 = 22l
  3. l = 308/22 = 14 cm

Answer: Slant height = 14 cm.

Example 6: Example 6: Finding the height from slant height and radius

Problem: A cone has slant height 25 cm and radius 7 cm. Find its height.


Solution:

Given:

  • l = 25 cm, r = 7 cm

Using l² = r² + h²:

  • h² = l² − r² = 625 − 49 = 576
  • h = √576 = 24 cm

Answer: Height = 24 cm.

Example 7: Example 7: TSA when height and radius are given

Problem: Find the total surface area of a cone with radius 5 cm and height 12 cm. (Use π = 3.14)


Solution:

Given:

  • r = 5 cm, h = 12 cm

Step 1: Find slant height

  • l = √(25 + 144) = √169 = 13 cm

Step 2: Find TSA

  • TSA = πr(l + r) = 3.14 × 5 × (13 + 5)
  • TSA = 3.14 × 5 × 18 = 3.14 × 90 = 282.6 sq cm

Answer: TSA = 282.6 sq cm.

Example 8: Example 8: Comparing CSA of two cones

Problem: Cone A has radius 4 cm and slant height 9 cm. Cone B has radius 6 cm and slant height 6 cm. Which cone has greater CSA?


Solution:

CSA of Cone A:

  • CSA_A = π × 4 × 9 = 36π sq cm

CSA of Cone B:

  • CSA_B = π × 6 × 6 = 36π sq cm

Answer: Both cones have equal CSA = 36π sq cm.

Example 9: Example 9: Finding radius from TSA

Problem: The total surface area of a cone is 616 sq cm and its slant height is 21 cm. Find the radius. (Use π = 22/7)


Solution:

Given:

  • TSA = 616 sq cm, l = 21 cm

Using TSA = πr(l + r):

  1. 616 = (22/7) × r × (21 + r)
  2. 616 × 7 = 22r(21 + r)
  3. 4312 = 22r(21 + r)
  4. 196 = r(21 + r)
  5. r² + 21r − 196 = 0
  6. (r + 28)(r − 7) = 0
  7. r = 7 cm (rejecting r = −28)

Answer: Radius = 7 cm.

Example 10: Example 10: Cone formed by a sector

Problem: A sector of a circle with radius 15 cm and angle 120° is rolled into a cone. Find the radius and height of the cone.


Solution:

Given:

  • Radius of sector = slant height of cone = l = 15 cm
  • Angle of sector = 120°

Step 1: Find the radius of the cone

  • Arc length of sector = (120/360) × 2π × 15 = (1/3) × 30π = 10π cm
  • This equals the circumference of the base: 2πr = 10π
  • r = 5 cm

Step 2: Find the height

  • h = √(l² − r²) = √(225 − 25) = √200 = 10√2 ≈ 14.14 cm

Answer: Radius = 5 cm, Height = 10√2 ≈ 14.14 cm.

Real-World Applications

Applications of Cone Surface Area:


  • Tent and Canopy Design: Conical tents, teepees, and circus tent tops require calculation of the curved surface area to determine the amount of canvas, nylon, or fabric needed. A conical tent with base radius 7 m and slant height 12 m needs π × 7 × 12 = 264 sq m of canvas. Large-scale event planning depends on accurate CSA calculations to estimate costs.
  • Ice Cream Cone Manufacturing: Ice cream cone manufacturers calculate the CSA of each wafer cone to determine the amount of batter needed per cone. For a cone with radius 2 cm and slant height 10 cm, CSA = π × 2 × 10 = 62.83 sq cm of wafer surface. Millions of cones are produced daily, so even small inaccuracies in surface area estimation affect material costs significantly.
  • Traffic Cone Production: Traffic cones need to be painted or coated with reflective material. The TSA determines the amount of paint or reflective tape required. Since traffic cones are hollow (no base needed), only the CSA is relevant for the coating calculation.
  • Roof Construction: Conical roofs on towers, turrets, and traditional buildings (like African rondavels) require area calculations for roofing material — tiles, thatch, or metal sheets. The CSA gives the exact amount of roofing material needed, accounting for the slope.
  • Funnel Design: Laboratory funnels, kitchen funnels, and industrial hoppers are conical. The surface area determines the amount of metal, plastic, or glass needed for manufacturing. Larger funnels for chemical plants require precise CSA calculations for material procurement.
  • Party Hats and Decorations: Conical party hats, Christmas trees, and decorative lampshades require CSA calculations to determine the amount of paper, cardboard, or fabric. A party hat with radius 5 cm and slant height 15 cm needs about 236 sq cm of paper.
  • Paper Cup Manufacturing: Paper cups are conical (or frustum-shaped). The CSA determines the amount of paper needed per cup. With billions of disposable cups produced annually, surface area calculations are critical for material efficiency and cost control.
  • Satellite and Rocket Nose Cones: The nose cones of rockets and satellites are conical. Engineers calculate the surface area to determine the amount of heat-shielding material needed to protect the payload during atmospheric re-entry.

Key Points to Remember

  • A cone has a circular base (radius r), a curved surface, a vertex (apex), a height (h), and a slant height (l).
  • Slant height: l = √(r² + h²). The slant height is always greater than the vertical height because l² = r² + h² > h².
  • Curved Surface Area (CSA) = πrl — area of the slanting surface only, excluding the base.
  • Total Surface Area (TSA) = πr(l + r) = πrl + πr² — curved surface plus the circular base.
  • The curved surface, when cut along the slant height and unrolled flat, forms a sector of a circle with radius equal to l and arc length equal to 2πr.
  • Use CSA when the base is open (tents, funnels, open containers). Use TSA when the base is closed (solid cones, closed containers).
  • When combining a cone with another solid (cylinder, hemisphere), do NOT count the shared circular face. Only include visible surfaces in the total surface area.
  • Always check whether the problem gives radius or diameter. If diameter is given, remember to halve it before applying the formulas.
  • Use π = 22/7 when the radius or other dimensions are multiples of 7 (for cleaner calculations). Use π = 3.14 otherwise, unless the problem specifies.
  • The CSA of a cone can also be written as πr√(r² + h²) when slant height is not directly given but r and h are known.
  • A cone is a special case of a pyramid with a circular base. The volume formula (not surface area) is V = (1/3)πr²h.
  • Surface area of a cone is covered in Chapter 13 (Surface Areas and Volumes) of CBSE Class 9 NCERT Mathematics.

Practice Problems

  1. Find the CSA of a cone with radius 14 cm and slant height 20 cm.
  2. Find the TSA of a cone with radius 5 cm and height 12 cm.
  3. A conical tent has a base radius of 10.5 m and height 14 m. Find the area of the canvas used.
  4. The CSA of a cone is 550 sq cm and its radius is 7 cm. Find the slant height.
  5. A solid cone has TSA 704 sq cm and slant height 25 cm. Find the radius of the base.
  6. A sector of a circle with radius 21 cm and angle 60° is rolled into a cone. Find the radius of the cone.
  7. The height of a cone is 24 cm and the diameter of the base is 14 cm. Find both CSA and TSA.
  8. Find the ratio of the CSA to the TSA of a cone with radius 3 cm and slant height 5 cm.

Frequently Asked Questions

Q1. What is the curved surface area of a cone?

The curved surface area (CSA) of a cone is the area of its lateral (sloping) surface, excluding the base. It is calculated as CSA = πrl, where r is the base radius and l is the slant height.

Q2. What is the total surface area of a cone?

The total surface area (TSA) is the sum of the curved surface area and the base area: TSA = πrl + πr² = πr(l + r).

Q3. How do you find the slant height of a cone?

The slant height is found using the Pythagoras Theorem: l = √(r² + h²), where r is the base radius and h is the vertical height.

Q4. When do you use CSA and when TSA?

Use CSA when the base is open (e.g., tents, funnels, hollow cones). Use TSA when the cone is a solid object with both the curved surface and the flat base covered.

Q5. What shape does the curved surface of a cone form when unrolled?

The curved surface of a cone, when cut along the slant height and laid flat, forms a sector of a circle. The radius of this sector equals the slant height of the cone.

Q6. Is slant height always greater than the height of a cone?

Yes. The slant height l = √(r² + h²) is always greater than h because l² = r² + h² > h².

Q7. What is the difference between a cone and a cylinder?

A cone tapers from a circular base to a single point (apex). A cylinder has two equal circular bases connected by a uniform curved surface. The CSA of a cylinder is 2πrh, while the CSA of a cone is πrl.

Q8. Is surface area of a cone in the CBSE Class 9 syllabus?

Yes. The surface area of a cone (both CSA and TSA) is part of Chapter 13 (Surface Areas and Volumes) in the CBSE Class 9 Mathematics syllabus.

Q9. How is a cone formed from a sector?

When a sector of a circle is rolled so that the two straight edges meet, it forms a cone. The radius of the sector becomes the slant height of the cone, and the arc length becomes the circumference of the base.

Q10. What is a frustum of a cone?

A frustum is the portion of a cone remaining when it is cut by a plane parallel to the base. It has two circular faces of different radii. Frustums are studied in Class 10.

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