Areas related to circles is an important topic in geometry that helps students understand how to calculate the area of the space occupied by different parts of a circle, such as sectors, segments, and semicircles. It is built on the basic concept of the area of a circle and extends it to other real-world shapes formed within or from a circle. This topic is widely used in solving practical problems involving arcs, chords, and circular regions.
A circle is a simple closed two-dimensional figure in which all points on its boundary are at a fixed distance from a fixed point called the centre. The area of a circle is the region enclosed within its boundary.
Area of a circle = πr2 Where, r = radius of circle
A semicircle is formed when a circle is cut in half along its diameter. The area of a semicircle is half the area of the circle.
Area of semicircle = 12πr2 Where, r = radius of circle
A sector of a circle is a region of a circle enclosed by two radii and the arc between them. The two radii form the angle at the centre of the circle known as the central angle. This central angle determines the size of the sector.
Let r be the radius of a circle. We know that the area of a circle is πr2 , i.e., when the degree measure of the angle at the centre is 360, the area of the sector = πr2 .
Then, when the degree measure of the angle at the centre is 1, the area of the sector = πr2360
∴ when the degree measure of the angle at the centre is θ, = πr2360×θ = θ360×πr2
Area of sector = θ360×πr2
Where, r = radius of circle
θ = angle of the sector in degrees
NOTE: Length of an arc of a sector of a circle with radius r and angle with degree measure is \frac{θ}{360}×2πr
A segment of a circle is the region formed when a circle is divided by a chord. It is the part of the circle enclosed between a chord and the corresponding arc.
APB = Area of the sector OAPB – Area of ∆ OAB
Area of ∆OAB = 12r2sinθ
= r2[πθ360−sinθ2]
Area of the segment = r2[πθ360−sinθ2]
Where, r = radius of circle
θ = angle of the sector in degrees
Example 1: Find the area of a circle with radius 7 cm. (Use π = 22/7) Solution: Given, r = 7 cm Area of a circle = πr2
Area=(22/7)×7×7=154 cm2
Example 2: Find the area of a semicircle with radius 14 cm. (Use π = 22/7) Solution: Given, r = 14 cm Area of a semicircle = 12πr2
Example 3: Find the area of a sector with radius 7 cm and angle 60°.
Solution: Given, r = 7 cm and θ = 60°
Area of sector = 25.67 cm2
Solution: Given r = 14 cm and θ = 60°
Area of the segment = r2[πθ360−sinθ2]=(14)2[π×60360−sin602]
= (14)2[π×60360−322]
= 17.8 cm2
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