MCQs for Class 9: Chapter 6 'Measuring Space - Perimeter and Area'

MCQs on Chapter 6: Measuring Space: Perimeter and Area for Class 9 Maths are available in this article along with a free PDF for offline practice. These MCQs help students revise important concepts such as perimeter, circumference of circles, arcs, area of rectangles, parallelograms, triangles, Heron’s formula, cyclic quadrilaterals, and Brahmagupta’s formula in an exam-oriented format.

Practising these MCQs will help students improve conceptual understanding, strengthen problem-solving skills, and prepare confidently for school exams and competitive assessments.

Chapter 6 Measuring Space: Perimeter and Area - MCQs with Answers

Question 1: The perimeter of a square with side 9 cm is:

(A) 18 cm
(B) 27 cm
(C) 36 cm
(D) 81 cm

Answer: (C)

Explanation: Perimeter of a square = 4 × side = 4 × 9 = 36 cm.

Question 2: The perimeter of a rectangle with length 14 cm and breadth 6 cm is:

(A) 20 cm
(B) 40 cm
(C) 84 cm
(D) 120 cm

Answer: (B)

Explanation: Perimeter of rectangle = 2(length + breadth) = 2(14 + 6) = 40 cm.

Question 3: The circumference of a circle with radius 14 cm is:

(A) 44 cm
(B) 66 cm
(C) 88 cm
(D) 176 cm

Answer: (C)

Explanation: Circumference = 2πr = 2 × 22/7 × 14 = 88 cm.

Question 4: The circumference of a circle is directly proportional to its:

(A) Area
(B) Diameter
(C) Radius squared
(D) Chord

Answer: (B)

Explanation: Circumference = πd, where d is the diameter.

Question 5: The length of a semicircular arc of radius 21 cm is:

(A) 33 cm
(B) 44 cm
(C) 66 cm
(D) 132 cm

Answer: (C)

Explanation: Semicircular arc length = πr = 22/7 × 21 = 66 cm.

Question 6: The length of a quarter-circle arc of radius 14 cm is:

(A) 11 cm
(B) 22 cm
(C) 44 cm
(D) 88 cm

Answer: (B)

Explanation: Quarter-circle arc length = (1/4) × 2πr = πr/2 = 22 cm.

Question 7: The area of a rectangle with length 18 cm and breadth 7 cm is:

(A) 25 cm²
(B) 50 cm²
(C) 126 cm²
(D) 252 cm²

Answer: (C)

Explanation: Area = length × breadth = 18 × 7 = 126 cm².

Question 8: The area of a parallelogram with base 15 cm and height 8 cm is:

(A) 60 cm²
(B) 120 cm²
(C) 240 cm²
(D) 360 cm²

Answer: (B)

Explanation: Area of parallelogram = base × height = 15 × 8 = 120 cm².

Question 9: The area of a triangle with base 20 cm and height 9 cm is:

(A) 90 cm²
(B) 120 cm²
(C) 180 cm²
(D) 360 cm²

Answer: (A)

Explanation: Area of triangle = 1/2 × base × height = 1/2 × 20 × 9 = 90 cm².

Question 10: A median of a triangle divides it into:

(A) Two congruent triangles
(B) Two triangles of equal area
(C) Two right triangles
(D) Two similar triangles

Answer: (B)

Explanation: A median divides a triangle into two triangles having equal areas.

Question 11: The semi-perimeter of a triangle with sides 5 cm, 12 cm, and 13 cm is:

(A) 15 cm
(B) 20 cm
(C) 25 cm
(D) 30 cm

Answer: (A)

Explanation: Semi-perimeter = (5 + 12 + 13) / 2 = 15 cm.

Question 12: Using Heron's formula, the area of a triangle with sides 5 cm, 12 cm, and 13 cm is:

(A) 30 cm²
(B) 60 cm²
(C) 78 cm²
(D) 90 cm²

Answer: (A)

Explanation: Semi-perimeter = 15. Area = √[15(15−5)(15−12)(15−13)] = √(15 × 10 × 3 × 2) = √900 = 30 cm².

Question 13: A quadrilateral whose vertices lie on a circle is called:

(A) Rhombus
(B) Trapezium
(C) Cyclic quadrilateral
(D) Kite

Answer: (C)

Explanation: A quadrilateral with all four vertices on the same circle is called a cyclic quadrilateral.

Question 14: Brahmagupta's formula is used to find the area of a:

(A) Triangle
(B) Circle
(C) Rectangle
(D) Cyclic quadrilateral

Answer: (D)

Explanation: Brahmagupta's formula gives the area of a cyclic quadrilateral using the lengths of its sides.

Question 15: The value of π is approximately equal to:

(A) 2.14
(B) 3.14
(C) 4.13
(D) 22.7

Answer: (B)

Explanation: The approximate value of π is 3.14.

Download Class 9 Measuring Space: Perimeter and Area MCQs PDF

Want to solve these questions later? Download the worksheet PDF below and keep it for revision before tests or exams.

MCQs Worksheet on Chapter 6: Measuring Space - Perimeter and Area for Class 9