Discount Questions Explained with Formula and Solutions

Discount questions and answers present methods and worked examples for finding the discount on marked prices through simple and effective steps. This guide reviews the standard idea that discount is the reduction given on the marked price of an item and demonstrates its use through solved problems involving marked price, selling price, discount percent, and profit or loss. From straightforward calculations to application-based questions, each solution focuses on clear steps, percentage reasoning, and helpful shortcuts. Worked examples with brief explanations help strengthen understanding and exam preparation.

Table of Contents

• Discount Formula and Important Concepts
• Basic Discount Questions for Class 6 and 7 with Answers
• CBSE-Level Discount Questions for Class 8, 9 and 10
• Advanced Discount Questions for Competitive Exams
• Frequently Asked Questions of Discount Questions

Discount Formula and Important Concepts

• Discount = Marked Price − Selling Price

• Discount % = (Discount ÷ Marked Price) × 100.

The discount is always calculated on the Marked Price

• Selling Price (SP) = Marked Price (MP) × (1 − Discount% ÷ 100)

• Successive discounts of a% and b% combine into a single discount of (a + b − ab/100)%.

• Marked Price vs Cost Price: MP/CP = (100 + Profit%) / (100 − Discount%).

Basic Discount Questions for Class 6 and 7 with Answers

Q1: A book marked at ₹250 is sold at a discount of 12%. What is its selling price?

(A) ₹210

(B) ₹220

(C) ₹225

(D) ₹230

Solution: 

Correct option: B) ₹220

SP = MP × (1 − 12/100) = 250 × 0.88 = ₹220

Q2: Fill-in-the-Blank (FIB)

A shirt has a marked price of ₹800. During a sale, it is sold for ₹680. The discount offered is ______ and the discount percentage is ______.

Solution: 

Given: MP = ₹800, SP = ₹680

Discount = MP − SP = 800 − 680 = ₹120

Discount % = (Discount ÷ MP) × 100 = (120 ÷ 800) × 100 = 15%

Q3: Riya buys a school bag marked at ₹1,200 during a "20% off" sale. How much money does she save, and how much does she finally pay?

Solution: Discount amount = 20% of 1200 = (20/100) × 1200 = ₹240 saved

Amount paid (SP) = 1200 − 240 = ₹960

Q4: A stationery shop sells a geometry box for ₹180 after giving a discount of ₹20 on the marked price. Find the marked price and the discount percentage.

Solution: 

MP = SP + Discount = 180 + 20 = ₹200

Discount % = (20 ÷ 200) × 100 = 10% 

CBSE-Level Discount Questions for Class 8, 9 and 10

Q5: A trader marks his goods 25% above the cost price and allows a discount of 10% on the marked price. His profit percentage is:

(A) 10%

(B) 12.5%

(C) 13.5%

(D) 15%

Solution:

Correct option: B) 12.5%

Let CP = ₹100. MP = 100 + 25% of 100 = ₹125

SP = 125 × (1 − 10/100) = 125 × 0.9 = ₹112.50

Profit = 112.50 − 100 = ₹12.50 

⇒ Profit% = 12.5%

Q6: Assertion (A): Two successive discounts of 20% and 10% on an article are the same as a single discount of 30%.

Reason (R): Successive discounts are calculated one after another on the reduced price each time, not on the original marked price both times.

(A) Both A and R are true, and R correctly explains why A is false as stated.

(B) Both A and R are true, and R explains A.

(C) A is true, R is false.

(D) A is false, R is true and R is the correct explanation for why A is false.

Solution:

Correct option: D

Assertion is false: successive discounts of 20% and 10% give an equivalent single discount of 20 + 10 − (20×10)/100 = 28%, not 30%. Reason is true and correctly explains why the two are not equal.

Q7: A shop in Jaipur is running a Diwali sale on a dinner set marked at ₹4,500. The offer reads: "Flat 20% off, plus an additional 5% off for online payment." Priya pays online.

(a) What single discount percentage does Priya actually get?

(b) How much does she finally pay?

Solution:

(a) Equivalent discount = 20 + 5 − (20×5)/100 = 25 − 1 = 24%

(b) SP = 4500 × (1 − 24/100) = 4500 × 0.76 = ₹3,420

Q8: An almirah is marked at ₹8,000. The shopkeeper allows successive discounts of 10%, 10%, and 5%. Find the final selling price.

Solution: SP = 8000 × 0.90 × 0.90 × 0.95 = ₹6,156 

Advanced Discount Questions for Competitive Exams

Q9: A shopkeeper offers "Buy 7, Get 5 Free" on toys of equal marked price. What is the effective discount percentage of this scheme?

(A) 35.7%

(B) 40%

(C) 41.67%

(D) 45%

Solution:

Correct option: C) 41.67%

Customer pays for 7 toys but takes home 12 (7 + 5 free).

Effective discount % = (Free items ÷ Total items) × 100 

= (5 ÷ 12) × 100 = 41.67%

Q10: A store offers two schemes on a shirt of marked price ₹1,000:

Scheme A: A single discount of 30%

Scheme B: Two successive discounts of 15% and 15%

Which scheme should a smart buyer pick, and why?

Solution:

Scheme A is better for the buyer.

Scheme A: SP = 1000 × 0.70 = ₹700

Scheme B: SP = 1000 × 0.85 × 0.85 = 1000 × 0.7225 = ₹722.50

Scheme A saves an extra ₹22.50. 

Q11: A shopkeeper marks an item 30% above cost price and, to earn 6.5% more profit than his usual 17% profit at 10% discount, what new discount percentage should he offer? (CP unchanged, MP = ₹130 per ₹100 CP)

(A) 4%

(B) 5%

(C) 5.5%

(D) 6%

Solution:

Correct option: B) 5%

Let CP = 100. MP = 130. SP at 10% discount = 130 × 0.9 = 117 (17% profit, matches given condition).

Desired SP for 6.5% more profit = 117 + 6.5 = 123.5

New discount = (130 − 123.5) ÷ 130 × 100 = 6.5 ÷ 130 × 100 = 5% 

Q12: Riya could not decide between a flat discount of 30% or two successive discounts of 25% and 5%, both offered on a shopping bill of ₹3,840. Which option should she pick, and what is the difference between the two discount amounts?

Solution:

Equivalent discount for 25% and 5% successively = 25 + 5 − (25×5)/100 

= 30 − 1.25 = 28.75%

Difference in discount % = 30% − 28.75% = 1.25%

Difference in ₹ = 3840 × 1.25% = ₹48

The flat 30% discount is better for Riya by ₹48.