Baudhayana-Pythagoras Theorem: Important Questions and Answers for Class 8

Baudhayana Pythagoras Theorem: Important Questions and Answers for Class 8 are available in this Maths article. Baudhayana-Pythagoras Theorem: Important Questions and Answers for Class 8 are very useful to solve the problems easily. This article helps the students to know the key questions and answers about the Baudhayana-Pythagoras Theorem. The theorem helps us find the missing side of a right triangle using the relationship between its sides, which we use in everyday calculations. Our subject experts have provided detailed solutions for these problems based on the CBSE syllabus and the NCERT textbook. This material helps students revise the chapter easily and perform well in the final examination.

Table of Contents

• Exercise 1: Baudhayana-Pythagoras Theorem Class 8 Important Questions
• Exercise 2: Pythagoras Theorem Word Problems for Class 8
• Exercise 3: Baudhayana-Pythagoras Theorem MCQ Questions
• Exercise 4: Real-Life Applications of Baudhayana-Pythagoras Theorem
• Exercise 5: Questions on Baudhayana-Pythagoras Theorem
• Most Repeated Board Questions On Baudhayana-Pythagoras Theorem Class 8
• Frequently Asked Questions on Baudhayana-Pythagoras Theorem for Class 8

Exercise 1: Baudhayana-Pythagoras Theorem Class 8 Important Questions

Question 1: Find the hypotenuse of a right triangle whose sides are 3 cm and 4 cm.

Solution

$c^2=3^2+4^2=9+16=25$

$c=\sqrt{25}=5$

Answer: 5 cm

Question 2: Find the missing side of a right triangle if the hypotenuse is 10 cm and one side is 6 cm.

Solution

$10^2=6^2+b^2$

$100=36+b^2$

$b^2=64$

$b=8$

Answer: 8 cm

Question 3: Check whether 5 cm, 12 cm, and 13 cm form a right triangle.

Solution

$5^2+12^2=25+144=169$

$13^2=169$

Answer: Yes, it forms a right triangle.

Question 4: Find the diagonal of a square whose side is 5 cm.

Solution

$d^2=5^2+5^2=25+25=50$

$d=\sqrt{50}=5\sqrt{2}$

Answer:$(5\sqrt{2}) cm$

Question 5: Find the hypotenuse when the other sides are 8 cm and 15 cm.

Solution

$c^2=8^2+15^2=64+225=289$

$c=17$

Answer: 17 cm

Exercise 2: Pythagoras Theorem Word Problems for Class 8

Question 1: A ladder 13 m long is placed against a wall. If the foot of the ladder is 5 m away from the wall, find the height reached.

Solution

$13^2=5^2+h^2$

$169=25+h^2$

$h^2=144$

$h=12$

Answer: 12 m

Question 2: Find the diagonal of a rectangle whose length is 6 cm and breadth is 8 cm.

Solution

$d^2=6^2+8^2=36+64=100$

$d=10$

Answer: 10 cm

Question 3: A kite string is 25 m long and the kite is flying at a height of 24 m. Find the horizontal distance.

Solution

$25^2=24^2+x^2$

$625=576+x^2$

$x^2=49$

$x=7$

Answer: 7 m

Question 4: Find the side of a square whose diagonal is 14 cm.

Solution

$14^2=s^2+s^2$

$196=2s^2$

$s^2=98$

$s=7\sqrt{2}$

Answer:$(7\sqrt{2}) cm$

Question 5: Find the height of a triangle if the hypotenuse is 15 cm and base is 9 cm.

Solution

$15^2=9^2+h^2$

$225=81+h^2$

$h^2=144$

$h=12$

Answer: 12 cm

Exercise 3: Baudhayana-Pythagoras Theorem MCQ Questions

Question 1: Which of the following is a Pythagorean triplet?

A) 3, 4, 5
B) 2, 3, 5
C) 4, 5, 6
D) 5, 6, 7

Answer: A) 3, 4, 5

Question 2: The hypotenuse of a triangle with sides 5 cm and 12 cm is:

A) 10 cm
B) 12 cm
C) 13 cm
D) 14 cm

Solution

$c^2=5^2+12^2=25+144=169$

$c=13$

Answer: C) 13 cm

Question 3: The diagonal of a square of side 10 cm is:

A) 10 cm
B) 15 cm
C)$10\sqrt{2}$ cm
D) 20 cm

Solution

$d^2=10^2+10^2=200$

$d=10\sqrt{2}$

Answer: C)$10\sqrt{2} cm$

Question 4: If one side of a right triangle is 7 cm and hypotenuse is 25 cm, the other side is:

A) 20 cm
B) 22 cm
C) 24 cm
D) 26 cm

Solution

$25^2=7^2+b^2$

$625=49+b^2$

$b^2=576$

$b=24$

Answer: C) 24 cm

Question 5: Which theorem is used to find the diagonal of a rectangle?

A) Angle Sum Property
B) Pythagoras Theorem
C) Midpoint Theorem
D) Congruence Theorem

Answer: B) Pythagoras Theorem

Exercise 4: Real-Life Applications of Baudhayana-Pythagoras Theorem

Question 1: A person walks 9 m east and then 12 m north. Find the shortest distance from the starting point.

Solution

$d^2=9^2+12^2=81+144=225$

$d=15$

Answer: 15 m

Question 2: A TV screen measures 8 cm by 6 cm. Find the diagonal.

Solution

$d^2=8^2+6^2=64+36=100$

$d=10$

Answer: 10 cm

Question 3: A rope 17 m long is tied to the top of a pole. If the other end is fixed 8 m away from the pole, find the pole’s height.

Solution

$17^2=8^2+h^2$

$289=64+h^2$

$h^2=225$

$h=15$

Answer: 15 m

Question 4: Find the diagonal of a rectangle of length 12 cm and breadth 16 cm.

Solution

$d^2=12^2+16^2=144+256=400$

$d=20$

Answer: 20 cm

Question 5: A bird flies 15 m vertically and 20 m horizontally. Find the direct distance travelled.

Solution

$d^2=15^2+20^2=225+400=625$

$d=25$

Answer: 25 m

Exercise 5: Questions on Baudhayana-Pythagoras Theorem

Question 1: Check whether 6 cm, 8 cm, and 10 cm form a right triangle.

Solution

$6^2+8^2=36+64=100$

$10^2=100$

Answer: Yes, it forms a right triangle.

Question 2: Find the smallest Pythagorean triplet whose one side is 12.

Solution

Multiply the basic triplet (3, 4, 5) by 4:

Answer: 12, 16, 20

Question 3: The diagonal of a square is 20 cm. Find its area.

Solution

$20^2=2s^2$

$400=2s^2$

$s^2=200$

Area = 200 cm²

Answer: 200 cm²

Question 4: Find the hypotenuse if the other sides are 9 cm and 40 cm.

Solution

$c^2=9^2+40^2=81+1600=1681$

$c=41$

Answer: 41 cm

Question 5: A rectangular park has dimensions 15 m and 20 m. Find the shortest path between opposite corners.

Solution

$d^2=15^2+20^2=225+400=625$

$d=25$

Answer: 25 m

Most Repeated Board Questions On Baudhayana-Pythagoras Theorem Class 8

Question 1: Find the hypotenuse of a right triangle whose sides are 5 cm and 12 cm.

Solution

$c^2=5^2+12^2=25+144=169$

$c=\sqrt{169}=13$

Answer: 13 cm

Question 2: Find the missing side of a right triangle if the hypotenuse is 17 cm and one side is 8 cm.

Solution

$17^2=8^2+b^2$

$289=64+b^2$

$b^2=225$

$b=15$

Answer: 15 cm

Question 3: Check whether 9 cm, 12 cm, and 15 cm form a right triangle.

Solution

$9^2+12^2=81+144=225$

$15^2=225$

Since both sides are equal, the triangle is right-angled.

Answer: Yes, it is a right triangle.

Question 4: Find the diagonal of a rectangle whose length is 15 cm and breadth is 8 cm.

Solution

$d^2=15^2+8^2=225+64=289$

$d=\sqrt{289}=17$

Answer: 17 cm

Question 5: A ladder 10 m long is placed against a wall. If the foot of the ladder is 6 m away from the wall, find the height reached by the ladder.

Solution

$10^2=6^2+h^2$

$100=36+h^2$

$h^2=64$

$h=8$

Answer: 8 m

Question 6: The diagonal of a square is 14 cm. Find its side.

Solution

$14^2=s^2+s^2$

$196=2s^2$

$s^2=98$

$s=7\sqrt{2}$

Answer:$(7\sqrt{2}) cm$

Question 7: Find the shortest distance between opposite corners of a rectangular park of length 24 m and breadth 7 m.

Solution

$d^2=24^2+7^2=576+49=625$

$d=25$

Answer: 25 m

Question 8: A kite is flying at a height of 40 m. The string length is 41 m. Find the horizontal distance.

Solution

$41^2=40^2+x^2$

$1681=1600+x^2$

$x^2=81$

$x=9$

Answer: 9 m

Question 9: Find the hypotenuse when the other two sides are 7 cm and 24 cm.

Solution

$c^2=7^2+24^2=49+576=625$

$c=25$

Answer: 25 cm

Question 10: A rope 13 m long is tied to the top of a pole. If the other end is fixed 5 m away from the pole, find the height of the pole.

Solution

$13^2=5^2+h^2$

$169=25+h^2$

$h^2=144$

$h=12$

Answer: 12 m