Baudhayana-Pythagoras Theorem: Important Questions and Answers for Class 8

Baudhayana Pythagoras Theorem: Important Questions and Answers for Class 8 are available in this Maths article. Baudhayana-Pythagoras Theorem: Important Questions and Answers for Class 8 are very useful to solve the problems easily. This article helps the students to know the key questions and answers about the Baudhayana-Pythagoras Theorem. The theorem helps us find the missing side of a right triangle using the relationship between its sides, which we use in everyday calculations. Our subject experts have provided detailed solutions for these problems based on the CBSE syllabus and the NCERT textbook. This material helps students revise the chapter easily and perform well in the final examination.

Table of Contents

Exercise 1: Baudhayana-Pythagoras Theorem Class 8 Important Questions

Question 1: Find the hypotenuse of a right triangle whose sides are 3 cm and 4 cm.

Solution

c2=32+42=9+16=25

c=25=5

Answer: 5 cm

Question 2: Find the missing side of a right triangle if the hypotenuse is 10 cm and one side is 6 cm.

Solution

102=62+b2

100=36+b2

b2=64

b=8

Answer: 8 cm

Question 3: Check whether 5 cm, 12 cm, and 13 cm form a right triangle.

Solution

52+122=25+144=169

132=169

Answer: Yes, it forms a right triangle.

Question 4: Find the diagonal of a square whose side is 5 cm.

Solution

d2=52+52=25+25=50

d=50=52

Answer: (52)cm

Question 5: Find the hypotenuse when the other sides are 8 cm and 15 cm.

Solution

c2=82+152=64+225=289

c=17

Answer: 17 cm

Exercise 2: Pythagoras Theorem Word Problems for Class 8

Question 1: A ladder 13 m long is placed against a wall. If the foot of the ladder is 5 m away from the wall, find the height reached.

Solution

132=52+h2

169=25+h2

h2=144

h=12

Answer: 12 m

Question 2: Find the diagonal of a rectangle whose length is 6 cm and breadth is 8 cm.

Solution

d2=62+82=36+64=100

d=10

Answer: 10 cm

Question 3: A kite string is 25 m long and the kite is flying at a height of 24 m. Find the horizontal distance.

Solution

252=242+x2

625=576+x2

x2=49

x=7

Answer: 7 m

Question 4: Find the side of a square whose diagonal is 14 cm.

Solution

142=s2+s2

196=2s2

s2=98

s=72

Answer: (72)cm

Question 5: Find the height of a triangle if the hypotenuse is 15 cm and base is 9 cm.

Solution

152=92+h2

225=81+h2

h2=144

h=12

Answer: 12 cm

Exercise 3: Baudhayana-Pythagoras Theorem MCQ Questions

Question 1: Which of the following is a Pythagorean triplet?

A) 3, 4, 5
B) 2, 3, 5
C) 4, 5, 6
D) 5, 6, 7

Answer: A) 3, 4, 5

Question 2: The hypotenuse of a triangle with sides 5 cm and 12 cm is:

A) 10 cm
B) 12 cm
C) 13 cm
D) 14 cm

Solution

c2=52+122=25+144=169

c=13

Answer: C) 13 cm

Question 3: The diagonal of a square of side 10 cm is:

A) 10 cm
B) 15 cm
C) 102 cm
D) 20 cm

Solution

d2=102+102=200

d=102

Answer: C) 102cm

Question 4: If one side of a right triangle is 7 cm and hypotenuse is 25 cm, the other side is:

A) 20 cm
B) 22 cm
C) 24 cm
D) 26 cm

Solution

252=72+b2

625=49+b2

b2=576

b=24

Answer: C) 24 cm

Question 5: Which theorem is used to find the diagonal of a rectangle?

A) Angle Sum Property
B) Pythagoras Theorem
C) Midpoint Theorem
D) Congruence Theorem

Answer: B) Pythagoras Theorem

Exercise 4: Real-Life Applications of Baudhayana-Pythagoras Theorem

Question 1: A person walks 9 m east and then 12 m north. Find the shortest distance from the starting point.

Solution

d2=92+122=81+144=225

d=15

Answer: 15 m

Question 2: A TV screen measures 8 cm by 6 cm. Find the diagonal.

Solution

d2=82+62=64+36=100

d=10

Answer: 10 cm

Question 3: A rope 17 m long is tied to the top of a pole. If the other end is fixed 8 m away from the pole, find the pole’s height.

Solution

172=82+h2

289=64+h2

h2=225

h=15

Answer: 15 m

Question 4: Find the diagonal of a rectangle of length 12 cm and breadth 16 cm.

Solution

d2=122+162=144+256=400

d=20

Answer: 20 cm

Question 5: A bird flies 15 m vertically and 20 m horizontally. Find the direct distance travelled.

Solution

d2=152+202=225+400=625

d=25

Answer: 25 m

Exercise 5: Questions on Baudhayana-Pythagoras Theorem

Question 1: Check whether 6 cm, 8 cm, and 10 cm form a right triangle.

Solution

62+82=36+64=100

102=100

Answer: Yes, it forms a right triangle.

Question 2: Find the smallest Pythagorean triplet whose one side is 12.

Solution

Multiply the basic triplet (3, 4, 5) by 4:

Answer: 12, 16, 20

Question 3: The diagonal of a square is 20 cm. Find its area.

Solution

202=2s2

400=2s2

s2=200

Area = 200 cm²

Answer: 200 cm²

Question 4: Find the hypotenuse if the other sides are 9 cm and 40 cm.

Solution

c2=92+402=81+1600=1681

c=41

Answer: 41 cm

Question 5: A rectangular park has dimensions 15 m and 20 m. Find the shortest path between opposite corners.

Solution

d2=152+202=225+400=625

d=25

Answer: 25 m

Most Repeated Board Questions On Baudhayana-Pythagoras Theorem Class 8

Question 1: Find the hypotenuse of a right triangle whose sides are 5 cm and 12 cm.

Solution

c2=52+122=25+144=169

c=169=13

Answer: 13 cm

Question 2: Find the missing side of a right triangle if the hypotenuse is 17 cm and one side is 8 cm.

Solution

172=82+b2

289=64+b2

b2=225

b=15

Answer: 15 cm

Question 3: Check whether 9 cm, 12 cm, and 15 cm form a right triangle.

Solution

92+122=81+144=225

152=225

Since both sides are equal, the triangle is right-angled.

Answer: Yes, it is a right triangle.

Question 4: Find the diagonal of a rectangle whose length is 15 cm and breadth is 8 cm.

Solution

d2=152+82=225+64=289

d=289=17

Answer: 17 cm

Question 5: A ladder 10 m long is placed against a wall. If the foot of the ladder is 6 m away from the wall, find the height reached by the ladder.

Solution

102=62+h2

100=36+h2

h2=64

h=8

Answer: 8 m

Question 6: The diagonal of a square is 14 cm. Find its side.

Solution

142=s2+s2

196=2s2

s2=98

s=72

Answer: (72)cm

Question 7: Find the shortest distance between opposite corners of a rectangular park of length 24 m and breadth 7 m.

Solution

d2=242+72=576+49=625

d=25

Answer: 25 m

Question 8: A kite is flying at a height of 40 m. The string length is 41 m. Find the horizontal distance.

Solution

412=402+x2

1681=1600+x2

x2=81

x=9

Answer: 9 m

Question 9: Find the hypotenuse when the other two sides are 7 cm and 24 cm.

Solution

c2=72+242=49+576=625

c=25

Answer: 25 cm

Question 10: A rope 13 m long is tied to the top of a pole. If the other end is fixed 5 m away from the pole, find the height of the pole.

Solution

132=52+h2

169=25+h2

h2=144

h=12

Answer: 12 m

Frequently Asked Questions on Baudhayana-Pythagoras Theorem for Class 8

1. What is the Baudhayana-Pythagoras Theorem?

The Baudhayana-Pythagoras Theorem states that in a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

c2=a2+b2

 

2. Who discovered the Pythagoras Theorem first?

The theorem was described earlier by the Indian mathematician Baudhayana before Pythagoras.

3. What is a right-angled triangle?

A right-angled triangle is a triangle with one angle equal to: 90∘

4. What is the hypotenuse?

The hypotenuse is the longest side of a right-angled triangle and lies opposite the right angle.

5. Can the theorem be applied to all triangles?

No, it is applicable only to right-angled triangles.

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