Algebraic Identities
Algebraic identities are equations that are true for all values of the variables involved. Unlike algebraic equations (which are true only for specific values), identities hold universally. For example, (a + b)^2 = a^2 + 2ab + b^2 is true no matter what values a and b take — whether a = 1 and b = 2, or a = -5 and b = 100, or any other values. In Class 8 mathematics, algebraic identities are introduced as powerful tools for simplifying expressions, expanding products, and performing quick calculations. The four standard identities you will learn in this chapter — the square of a sum, the square of a difference, the difference of squares, and the product of two binomials with a common variable — form the foundation of algebra and are used extensively in Class 9 and 10 as well. Mastering these identities will help you factorise polynomials, solve quadratic equations, simplify complex algebraic expressions, and even perform arithmetic calculations mentally (like finding 99^2 without long multiplication). Whether you are squaring a number, finding a product of two numbers close to a round figure, or breaking down a complicated expression into simpler factors, these identities will save you time and effort. They are also the starting point for understanding more advanced identities involving cubes and higher powers that you will encounter in later classes.
What is Algebraic Identities?
An algebraic identity is an equality involving algebraic expressions that holds true for all values of the variables. It is different from an equation, which is true only for particular values of the variables.
The four standard algebraic identities taught in Class 8 are:
Identity I: (a + b)^2 = a^2 + 2ab + b^2
This is called the "square of a sum" identity.
Identity II: (a - b)^2 = a^2 - 2ab + b^2
This is called the "square of a difference" identity.
Identity III: (a + b)(a - b) = a^2 - b^2
This is called the "difference of squares" identity.
Identity IV: (x + a)(x + b) = x^2 + (a + b)x + ab
This is used for expanding products of two binomials with a common variable.
Each identity has a left-hand side (LHS) and a right-hand side (RHS). The LHS is the compact form, and the RHS is the expanded form. You can use identities in both directions — to expand expressions (LHS to RHS) or to factorise expressions (RHS to LHS).
These are called identities and not equations because they are satisfied by every value of the variables. For instance, (a + b)^2 = a^2 + 2ab + b^2 works for a = 1, b = 2 (9 = 1 + 4 + 4 = 9), for a = -3, b = 5 (4 = 9 - 30 + 25 = 4), and for any other values.
Algebraic Identities Formula
The four standard algebraic identities and their useful variations are:
Identity I: (a + b)^2 = a^2 + 2ab + b^2
Variations:
a^2 + b^2 = (a + b)^2 - 2ab
2ab = (a + b)^2 - a^2 - b^2
(a + b) = square root of (a^2 + 2ab + b^2)
Identity II: (a - b)^2 = a^2 - 2ab + b^2
Variations:
a^2 + b^2 = (a - b)^2 + 2ab
2ab = a^2 + b^2 - (a - b)^2
(a - b) = square root of (a^2 - 2ab + b^2)
Identity III: (a + b)(a - b) = a^2 - b^2
Variations:
a^2 = b^2 + (a + b)(a - b)
b^2 = a^2 - (a + b)(a - b)
Identity IV: (x + a)(x + b) = x^2 + (a + b)x + ab
Special cases:
When a = b: reduces to Identity I.
When b = -a: reduces to Identity III.
Combining Identities I and II:
(a + b)^2 + (a - b)^2 = 2(a^2 + b^2)
(a + b)^2 - (a - b)^2 = 4ab
Derivation and Proof
Let us derive each algebraic identity by expanding the products step by step.
Derivation of Identity I: (a + b)^2 = a^2 + 2ab + b^2
(a + b)^2 means (a + b) x (a + b).
Using the distributive property:
= a x (a + b) + b x (a + b)
= a x a + a x b + b x a + b x b
= a^2 + ab + ab + b^2
= a^2 + 2ab + b^2
Geometric Proof: Consider a square with side (a + b). Its area = (a + b)^2. Divide this square into four parts: a square of side a (area a^2), a square of side b (area b^2), and two rectangles each with sides a and b (area ab each). Total area = a^2 + ab + ab + b^2 = a^2 + 2ab + b^2.
Derivation of Identity II: (a - b)^2 = a^2 - 2ab + b^2
(a - b)^2 = (a - b)(a - b)
= a(a - b) - b(a - b)
= a^2 - ab - ab + b^2
= a^2 - 2ab + b^2
Alternative: Replace b with (-b) in Identity I:
(a + (-b))^2 = a^2 + 2a(-b) + (-b)^2
= a^2 - 2ab + b^2. Same result.
Derivation of Identity III: (a + b)(a - b) = a^2 - b^2
Using the distributive property:
(a + b)(a - b) = a(a - b) + b(a - b)
= a^2 - ab + ab - b^2
= a^2 - b^2
The middle terms (-ab and +ab) cancel each other out, leaving only the difference of squares.
Derivation of Identity IV: (x + a)(x + b) = x^2 + (a + b)x + ab
(x + a)(x + b) = x(x + b) + a(x + b)
= x^2 + xb + ax + ab
= x^2 + (a + b)x + ab
We can verify: when a = b, this gives x^2 + 2ax + a^2 = (x + a)^2, which matches Identity I with 'x' and 'a' in place of 'a' and 'b'.
Types and Properties
Algebraic identity problems can be classified into the following types:
1. Expansion using identities:
Expand expressions like (3x + 4)^2 or (2a - 5b)^2 using the standard identities. This is the most basic application.
2. Evaluation of numerical expressions:
Use identities to quickly compute values like 103^2, 97^2, or 105 x 95 without long multiplication.
3. Factorisation:
Rewrite expressions like x^2 + 6x + 9 as (x + 3)^2 by recognising the identity pattern. This is the reverse of expansion.
4. Finding the value of an expression given a condition:
Problems like: "If a + b = 7 and ab = 10, find a^2 + b^2." Use identity rearrangements to solve.
5. Simplification of algebraic expressions:
Simplify complex expressions by applying identities to reduce them to simpler forms.
6. Geometric applications:
Using the geometric interpretation of identities (area model) to understand and verify them.
7. Verification problems:
Verify an identity by substituting specific values for the variables and checking that LHS = RHS.
8. Finding unknown terms:
Given a partial identity like (x + ?)^2 = x^2 + 10x + 25, find the missing value.
Solved Examples
Example 1: Example 1: Expanding (a + b)^2
Problem: Expand (3x + 5)^2.
Solution:
Using Identity I: (a + b)^2 = a^2 + 2ab + b^2, with a = 3x and b = 5:
(3x + 5)^2 = (3x)^2 + 2(3x)(5) + (5)^2
= 9x^2 + 30x + 25
Answer: (3x + 5)^2 = 9x^2 + 30x + 25.
Example 2: Example 2: Expanding (a - b)^2
Problem: Expand (4y - 3)^2.
Solution:
Using Identity II: (a - b)^2 = a^2 - 2ab + b^2, with a = 4y and b = 3:
(4y - 3)^2 = (4y)^2 - 2(4y)(3) + (3)^2
= 16y^2 - 24y + 9
Answer: (4y - 3)^2 = 16y^2 - 24y + 9.
Example 3: Example 3: Using the difference of squares
Problem: Expand (2a + 7b)(2a - 7b).
Solution:
Using Identity III: (a + b)(a - b) = a^2 - b^2, with a = 2a and b = 7b:
(2a + 7b)(2a - 7b) = (2a)^2 - (7b)^2
= 4a^2 - 49b^2
Answer: (2a + 7b)(2a - 7b) = 4a^2 - 49b^2.
Example 4: Example 4: Using Identity IV
Problem: Expand (x + 3)(x + 7).
Solution:
Using Identity IV: (x + a)(x + b) = x^2 + (a + b)x + ab, with a = 3 and b = 7:
(x + 3)(x + 7) = x^2 + (3 + 7)x + (3)(7)
= x^2 + 10x + 21
Answer: (x + 3)(x + 7) = x^2 + 10x + 21.
Example 5: Example 5: Numerical calculation using Identity I
Problem: Find 104^2 using an algebraic identity.
Solution:
Write 104 = 100 + 4.
Using Identity I: (100 + 4)^2 = 100^2 + 2(100)(4) + 4^2
= 10,000 + 800 + 16
= 10,816
Answer: 104^2 = 10,816.
Example 6: Example 6: Numerical calculation using Identity II
Problem: Find 98^2 using an algebraic identity.
Solution:
Write 98 = 100 - 2.
Using Identity II: (100 - 2)^2 = 100^2 - 2(100)(2) + 2^2
= 10,000 - 400 + 4
= 9,604
Answer: 98^2 = 9,604.
Example 7: Example 7: Numerical calculation using Identity III
Problem: Find the value of 203 x 197 using an algebraic identity.
Solution:
Write 203 = 200 + 3 and 197 = 200 - 3.
Using Identity III: (200 + 3)(200 - 3) = 200^2 - 3^2
= 40,000 - 9
= 39,991
Answer: 203 x 197 = 39,991.
Example 8: Example 8: Factorisation using identities
Problem: Factorise: 4x^2 + 12x + 9.
Solution:
Check if this matches the pattern a^2 + 2ab + b^2:
4x^2 = (2x)^2, so a = 2x.
9 = 3^2, so b = 3.
Check: 2ab = 2(2x)(3) = 12x. This matches the middle term!
Therefore: 4x^2 + 12x + 9 = (2x + 3)^2.
Answer: 4x^2 + 12x + 9 = (2x + 3)^2.
Example 9: Example 9: Finding a^2 + b^2 from given conditions
Problem: If a + b = 9 and ab = 20, find a^2 + b^2.
Solution:
Using Identity I: (a + b)^2 = a^2 + 2ab + b^2
9^2 = a^2 + 2(20) + b^2 [this is incorrect notation, let me rewrite]
Rearranging: a^2 + b^2 = (a + b)^2 - 2ab
= 9^2 - 2(20)
= 81 - 40
= 41
Answer: a^2 + b^2 = 41.
Example 10: Example 10: Identity IV with negative values
Problem: Expand (y - 4)(y + 6).
Solution:
Using Identity IV: (x + a)(x + b) = x^2 + (a + b)x + ab, with x = y, a = -4, b = 6:
(y - 4)(y + 6) = y^2 + (-4 + 6)y + (-4)(6)
= y^2 + 2y - 24
Verification by direct multiplication:
(y - 4)(y + 6) = y(y + 6) - 4(y + 6) = y^2 + 6y - 4y - 24 = y^2 + 2y - 24. Matches.
Answer: (y - 4)(y + 6) = y^2 + 2y - 24.
Real-World Applications
Algebraic identities have numerous applications in mathematics and beyond. They are among the most frequently used tools in all of algebra.
Mental Arithmetic: You can compute squares and products mentally using identities. For example, 52^2 = (50 + 2)^2 = 2,500 + 200 + 4 = 2,704. And 48 x 52 = (50 - 2)(50 + 2) = 2,500 - 4 = 2,496. Similarly, 997^2 = (1000 - 3)^2 = 1,000,000 - 6,000 + 9 = 994,009. These shortcuts are faster and more reliable than long multiplication.
Factorisation: Identities help factorise algebraic expressions, which is essential in solving equations, simplifying algebraic fractions, and finding roots. For example, x^2 - 16 = (x + 4)(x - 4) using Identity III. Similarly, 4x^2 + 20x + 25 = (2x + 5)^2 using Identity I. Factorisation using identities is a core skill tested in Class 9 and 10 examinations.
Solving Equations: Quadratic equations often require identity-based manipulation. Once you factorise x^2 - 5x + 6 as (x - 2)(x - 3) using Identity IV (with appropriate values), you can find x = 2 or x = 3. Many competition-level problems also rely on clever use of identities.
Simplifying Complex Expressions: Expressions like (2x + 3y)^2 - (2x - 3y)^2 look complicated but simplify beautifully using identities. Using the result (a + b)^2 - (a - b)^2 = 4ab, this becomes 4(2x)(3y) = 24xy.
Geometry: The geometric proof of identities using area models connects algebra to geometry. The identity (a + b)^2 = a^2 + 2ab + b^2 can be visualised as the area of a square divided into four regions — two smaller squares and two rectangles. This visual understanding helps students remember the identities and see the connection between algebraic formulas and geometric shapes.
Physics and Engineering: Many physics formulas involve squared terms. The kinetic energy formula (1/2)mv^2, the lens formula, and electrical resistance calculations all benefit from identity-based simplification. Engineers use identities when working with signal processing and control systems.
Higher Mathematics: In Class 9 and 10, these identities extend to cubic identities like (a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3 and polynomial factorisation. They are also used in calculus for derivative and integral simplification. Mastering the Class 8 identities is therefore essential preparation for advanced mathematics.
Key Points to Remember
- An algebraic identity is true for ALL values of the variables, unlike an equation which is true for specific values.
- Identity I: (a + b)^2 = a^2 + 2ab + b^2.
- Identity II: (a - b)^2 = a^2 - 2ab + b^2.
- Identity III: (a + b)(a - b) = a^2 - b^2.
- Identity IV: (x + a)(x + b) = x^2 + (a + b)x + ab.
- Identities can be used in both directions: to expand (LHS to RHS) or to factorise (RHS to LHS).
- a^2 + b^2 = (a + b)^2 - 2ab = (a - b)^2 + 2ab — a useful derived result.
- (a + b)^2 + (a - b)^2 = 2(a^2 + b^2) and (a + b)^2 - (a - b)^2 = 4ab.
- Identities are proved by expanding the LHS using the distributive property.
- These identities can be verified geometrically using the area model of a square.
Practice Problems
- Expand (5x + 2y)^2 using Identity I.
- Expand (3a - 4b)^2 using Identity II.
- Find the product (7m + 3n)(7m - 3n) using Identity III.
- Expand (p + 5)(p - 8) using Identity IV.
- Evaluate 997^2 using an algebraic identity.
- Factorise: 25x^2 - 30x + 9.
- If a - b = 5 and ab = 14, find a^2 + b^2.
- Evaluate 52 x 48 without direct multiplication, using an identity.
Frequently Asked Questions
Q1. What is an algebraic identity?
An algebraic identity is a mathematical equation that is true for all values of the variables involved. For example, (a + b)^2 = a^2 + 2ab + b^2 is true for every possible value of a and b.
Q2. How is an identity different from an equation?
An equation is true for specific values of the variable (e.g., 2x + 3 = 7 is true only when x = 2). An identity is true for ALL values of the variables (e.g., (a + b)^2 = a^2 + 2ab + b^2 is true for every a and b).
Q3. What are the four standard algebraic identities in Class 8?
The four identities are: (1) (a + b)^2 = a^2 + 2ab + b^2, (2) (a - b)^2 = a^2 - 2ab + b^2, (3) (a + b)(a - b) = a^2 - b^2, and (4) (x + a)(x + b) = x^2 + (a + b)x + ab.
Q4. How do you use identities for quick calculations?
Express numbers in a form that matches an identity. For example, 102^2 = (100 + 2)^2 = 10,000 + 400 + 4 = 10,404. Or 53 x 47 = (50 + 3)(50 - 3) = 2,500 - 9 = 2,491.
Q5. What is factorisation using identities?
Factorisation is the reverse of expansion. You recognise the pattern in an expression and write it in the compact identity form. For example, x^2 - 25 = x^2 - 5^2 = (x + 5)(x - 5) using Identity III.
Q6. How do you find a^2 + b^2 when a + b and ab are given?
Use the rearrangement: a^2 + b^2 = (a + b)^2 - 2ab. If a + b = 10 and ab = 21, then a^2 + b^2 = 100 - 42 = 58.
Q7. Can Identity IV have negative values for a and b?
Yes. Identity IV works for any values of a and b, including negative ones. For example, (x - 3)(x + 5) uses a = -3 and b = 5: x^2 + (-3 + 5)x + (-3)(5) = x^2 + 2x - 15.
Q8. How can you verify an algebraic identity?
Substitute specific values for the variables and check that LHS = RHS. For example, for (a + b)^2 = a^2 + 2ab + b^2, let a = 2, b = 3: LHS = 5^2 = 25, RHS = 4 + 12 + 9 = 25. LHS = RHS.
Q9. What is the geometric proof of (a + b)^2?
Draw a square with side (a + b). Divide it into four parts: a square of side a (area a^2), a square of side b (area b^2), and two rectangles of sides a and b (area ab each). Total area = a^2 + ab + ab + b^2 = a^2 + 2ab + b^2.
Q10. Why is (a + b)^2 not equal to a^2 + b^2?
(a + b)^2 = a^2 + 2ab + b^2, NOT a^2 + b^2. The extra term 2ab comes from the cross-multiplication of a and b. Forgetting the 2ab term is a very common mistake.










