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Proof of Pythagoras Theorem

Class 10Triangles

The Pythagoras Theorem is one of the most fundamental results in geometry. Its proof using similar triangles is covered in Chapter 6 (Triangles) of the NCERT Class 10 Mathematics textbook.


Key facts:

  • The theorem establishes a relationship between the three sides of a right-angled triangle.
  • The proof in Class 10 uses the concept of similarity of triangles, specifically the result that the altitude from the right angle vertex creates two triangles similar to the original.
  • The converse of the Pythagoras Theorem is equally important — it helps determine whether a triangle is right-angled.


The Pythagoras Theorem has been known for over 2,500 years and has more than 400 known proofs. The proof prescribed in the NCERT Class 10 textbook uses the concept of similar triangles formed by dropping a perpendicular from the right-angle vertex to the hypotenuse. This is one of the most elegant proofs because it connects two major topics — triangles (similarity) and the Pythagorean relationship.



The key construction step — drawing the altitude from the right angle to the hypotenuse — creates three similar triangles: the original triangle and two smaller triangles. This single construction yields not only the Pythagoras Theorem but also the important geometric mean relationships that are useful in many advanced problems.

What is Proof of Pythagoras Theorem — Statement, Proof Using Similar Triangles & Examples?

Pythagoras Theorem:

In a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.


If triangle ABC is right-angled at B, then:

AC² = AB² + BC²


where:

  • AC = hypotenuse (the side opposite the right angle — always the longest side)
  • AB and BC = the other two sides (legs)

Converse of Pythagoras Theorem:

If in a triangle, the square of one side equals the sum of squares of the other two sides, then the angle opposite to that side is a right angle.


If AC² = AB² + BC², then angle B = 90°.


Key triangle relationships from the proof:

  • When the altitude BD is drawn from the right angle B to hypotenuse AC, three similar triangles are formed: Triangle ABC ~ Triangle ADB ~ Triangle BDC.
  • Each leg of the original triangle is the geometric mean of the hypotenuse and the adjacent segment: AB^2 = AD x AC and BC^2 = DC x AC.
  • The altitude to the hypotenuse is the geometric mean of the two segments: BD^2 = AD x DC.
  • The altitude to the hypotenuse satisfies: 1/BD^2 = 1/AB^2 + 1/BC^2.

Proof of Pythagoras Theorem Formula

Pythagoras Theorem — Key Formulas:

To FindFormula
Hypotenusec = √(a² + b²)
One lega = √(c² − b²)
Other legb = √(c² − a²)

Common Pythagorean Triplets:

TripletMultiples
3, 4, 56-8-10, 9-12-15, 12-16-20, 15-20-25
5, 12, 1310-24-26, 15-36-39
8, 15, 1716-30-34
7, 24, 2514-48-50

Classifying triangles using side lengths:

  • If c² = a² + b²: right-angled triangle
  • If c² > a² + b²: obtuse-angled triangle
  • If c² < a² + b²: acute-angled triangle

Derivation and Proof

Proof of Pythagoras Theorem (Using Similar Triangles — NCERT Method):


Given: Triangle ABC, right-angled at B (angle B = 90°).

To prove: AC² = AB² + BC².


Construction: Draw BD perpendicular to AC, where D is on AC.


Proof:

  1. In triangle ADB and triangle ABC:
    • Angle ADB = angle ABC = 90°
    • Angle A = angle A (common)
    • By AA similarity: triangle ADB is similar to triangle ABC.
  2. Therefore: AD/AB = AB/AC (corresponding sides of similar triangles).
    Cross-multiply: AB² = AD × AC ... (i)
  3. In triangle BDC and triangle ABC:
    • Angle BDC = angle ABC = 90°
    • Angle C = angle C (common)
    • By AA similarity: triangle BDC is similar to triangle ABC.
  4. Therefore: DC/BC = BC/AC (corresponding sides of similar triangles).
    Cross-multiply: BC² = DC × AC ... (ii)
  5. Add equations (i) and (ii):
    AB² + BC² = AD × AC + DC × AC
    = AC(AD + DC)
    = AC × AC (since AD + DC = AC)
    = AC²

Therefore: AC² = AB² + BC².


QED.


Key insight: The altitude from the right angle vertex to the hypotenuse creates two smaller triangles, each similar to the original triangle and to each other. This triple similarity is the foundation of the proof.

Types and Properties

Types of Pythagoras Theorem problems:


Type 1: Finding the hypotenuse

  • Given two legs, find the hypotenuse.
  • Formula: c = √(a² + b²)
  • Example: Legs = 6, 8 → Hypotenuse = √(36 + 64) = √100 = 10

Type 2: Finding a leg

  • Given the hypotenuse and one leg, find the other leg.
  • Formula: a = √(c² − b²)
  • Example: Hypotenuse = 13, one leg = 5 → Other leg = √(169 − 25) = √144 = 12

Type 3: Checking for right angle (Converse)

  • Given three sides, check if c² = a² + b² (where c is the longest side).
  • If yes → right-angled triangle.
  • If c² > a² + b² → obtuse triangle.
  • If c² < a² + b² → acute triangle.

Type 4: Proof-based problems

  • Prove geometric results using the Pythagoras Theorem.
  • Example: Prove that in an isosceles right triangle with legs a, the hypotenuse = a√2.
  • Example: Prove that the altitude from the right angle vertex to the hypotenuse gives AB² = AD × AC.

Type 5: Word problems

  • Ladder against a wall — the ladder is the hypotenuse, the wall is the vertical leg, the ground distance is the horizontal leg.
  • Distance between two points — bird on a pole, ships at sea, planes in the sky.
  • Diagonal of a rectangle — the diagonal forms the hypotenuse with length and breadth as legs.

Type 6: In other shapes

Methods

Method 1: Direct application

  • Identify the right angle and the hypotenuse.
  • Apply c² = a² + b² directly.

Method 2: Converse application

  • Given three sides, check if the square of the longest side equals the sum of squares of the other two.

Method 3: In compound figures

  • Break the figure into right triangles.
  • Apply the theorem in each triangle.

Tips:

  • Always identify the hypotenuse first — it is the side opposite the right angle and is always the longest.
  • The theorem applies ONLY to right-angled triangles.
  • Pythagorean triplets (3-4-5, 5-12-13, 8-15-17) allow quick recognition of right triangles.
  • When working with surds, leave the answer in surd form unless asked to approximate.


Presentation tips for board exams:

  • Draw a neat figure with angle B clearly marked as 90 degrees and BD perpendicular to AC.
  • Write the Given and To Prove statements before starting the proof.
  • Clearly state the construction: "Draw BD perpendicular to AC."
  • When proving similarity, explicitly mention both angle pairs (common angle + right angle).
  • Write the proportionality statement from each similarity clearly before cross-multiplying.
  • In the final step, clearly show that AD + DC = AC.
  • End with "Hence Proved" or "QED".
  • Total proof should take about 1 page of writing.

Common exam variations:

  • Prove Pythagoras Theorem (full proof) — 5 marks
  • Using the proof, find segments of the hypotenuse — 3-4 marks
  • Prove the geometric mean relation BD^2 = AD x DC — 3 marks
  • Prove 1/BD^2 = 1/AB^2 + 1/BC^2 using the altitude — 4 marks

Solved Examples

Example 1: Finding the Hypotenuse

Problem: Find the hypotenuse of a right triangle with legs 6 cm and 8 cm.


Solution:

Given:

  • a = 6 cm, b = 8 cm

Using: c² = a² + b²

  1. c² = 36 + 64 = 100
  2. c = √100 = 10

Answer: Hypotenuse = 10 cm.

Example 2: Finding a Leg

Problem: A right triangle has hypotenuse 13 cm and one leg 5 cm. Find the other leg.


Solution:

Given:

  • c = 13 cm, a = 5 cm

Using: b = √(c² − a²)

  1. b² = 169 − 25 = 144
  2. b = √144 = 12

Answer: The other leg = 12 cm.

Example 3: Converse — Checking Right Angle

Problem: A triangle has sides 7 cm, 24 cm, and 25 cm. Is it right-angled?


Solution:

Given:

  • Sides: 7, 24, 25 (longest = 25)

Check:

  1. 25² = 625
  2. 7² + 24² = 49 + 576 = 625
  3. 25² = 7² + 24² ✓

By the converse of Pythagoras Theorem, the triangle is right-angled. The right angle is opposite the side of length 25.

Answer: Yes, it is a right-angled triangle.

Example 4: Ladder Against a Wall

Problem: A ladder 10 m long reaches a window 8 m above the ground. How far is the foot of the ladder from the wall?


Solution:

Given:

  • Ladder (hypotenuse) = 10 m
  • Height (vertical leg) = 8 m

Using: base = √(hypotenuse² − height²)

  1. base² = 100 − 64 = 36
  2. base = √36 = 6

Answer: The foot of the ladder is 6 m from the wall.

Example 5: Diagonal of a Rectangle

Problem: Find the diagonal of a rectangle with length 12 cm and breadth 5 cm.


Solution:

Given:

  • Length = 12 cm, breadth = 5 cm

Using: diagonal = √(l² + b²)

  1. d² = 144 + 25 = 169
  2. d = √169 = 13

Answer: Diagonal = 13 cm.

Example 6: Height of Equilateral Triangle

Problem: Find the height of an equilateral triangle with side 10 cm.


Solution:

Given:

  • Side = 10 cm
  • The height bisects the base, creating two right triangles with base 5 cm and hypotenuse 10 cm.

Using: h = √(10² − 5²)

  1. h² = 100 − 25 = 75
  2. h = √75 = 5√3

Answer: Height = 5√3 cm (approximately 8.66 cm).

Example 7: Distance Between Two Points (3D concept preview)

Problem: A bird is sitting on a pole 12 m high. A cat is at a distance of 16 m from the base of the pole. What is the distance between the bird and the cat?


Solution:

Given:

  • Height of pole = 12 m
  • Distance from base = 16 m

Using: distance = √(12² + 16²)

  1. d² = 144 + 256 = 400
  2. d = √400 = 20

Answer: Distance = 20 m.

Example 8: Proof Problem — Triangle with Altitude

Problem: In triangle ABC, angle B = 90° and BD is perpendicular to AC. Prove that AB² = AD × AC.


Solution:

Given:

  • Triangle ABC, angle B = 90°, BD perpendicular to AC

Proof:

  1. In triangles ADB and ABC:
    • Angle ADB = angle ABC = 90°
    • Angle A = angle A (common)
  2. By AA similarity: triangle ADB is similar to triangle ABC.
  3. AD/AB = AB/AC (corresponding sides)
  4. Cross-multiply: AB² = AD × AC

Hence proved.

Example 9: Classifying a Triangle

Problem: A triangle has sides 6 cm, 8 cm, and 11 cm. Classify it as acute, right, or obtuse.


Solution:

Given:

  • Sides: 6, 8, 11 (longest = 11)

Check:

  1. 11² = 121
  2. 6² + 8² = 36 + 64 = 100
  3. 121 > 100, i.e., c² > a² + b²

Answer: The triangle is obtuse-angled (the angle opposite 11 cm is obtuse).

Example 10: Rhombus Diagonal Problem

Problem: The diagonals of a rhombus are 16 cm and 12 cm. Find the side of the rhombus.


Solution:

Given:

  • Diagonals = 16 cm and 12 cm
  • Diagonals of a rhombus bisect each other at right angles.

Steps:

  1. Half-diagonals: 8 cm and 6 cm
  2. Each side forms the hypotenuse of a right triangle with legs 8 and 6.
  3. side² = 8² + 6² = 64 + 36 = 100
  4. side = 10

Answer: Side of rhombus = 10 cm.

Example 11: Proving 1/BD^2 = 1/AB^2 + 1/BC^2

Problem: In right triangle ABC (angle B = 90 degrees), BD is the altitude to hypotenuse AC. Prove that 1/BD^2 = 1/AB^2 + 1/BC^2.


Proof:

  • From the proof of Pythagoras: AB^2 = AD.AC and BC^2 = DC.AC
  • Also BD^2 = AD.DC
  • 1/AB^2 + 1/BC^2 = 1/(AD.AC) + 1/(DC.AC) = (DC + AD)/(AD.DC.AC) = AC/(AD.DC.AC) = 1/(AD.DC) = 1/BD^2

Hence proved: 1/BD^2 = 1/AB^2 + 1/BC^2.

Real-World Applications

Applications of the Pythagoras Theorem:

  • Construction — builders use the 3-4-5 rule to ensure corners are exactly 90°. Lay out 3 m on one side, 4 m on the other; if the diagonal is 5 m, the corner is right-angled.
  • Navigation — calculating straight-line (as-the-crow-flies) distance when north-south and east-west displacements are known. Ships and aircraft use this constantly.
  • Architecture — calculating roof heights (the slope forms the hypotenuse), ramp lengths for wheelchair access, staircase dimensions, and diagonal bracing for structural support.
  • Coordinate geometry — the distance formula d = √[(x₂−x₁)² + (y₂−y₁)²] is a direct application of the Pythagoras Theorem in the Cartesian plane.
  • Physics — resolving vectors into perpendicular components (force, velocity, displacement). The magnitude of the resultant of two perpendicular vectors is found using c = √(a² + b²).
  • Computer graphics — pixel distance calculations, collision detection between objects, and determining whether a point lies inside a circle (compare distance to radius).
  • Surveying — measuring heights of buildings, mountains, and towers indirectly by forming right triangles with known horizontal distances.
  • Everyday life — TV and monitor sizes are measured as diagonals. A "55-inch TV" has a 55-inch diagonal, and the actual width and height are found using the Pythagoras Theorem with the aspect ratio.

Historical significance:

  • The theorem was known to Babylonians around 1800 BCE (clay tablet Plimpton 322 lists Pythagorean triplets).
  • Indian mathematicians (Sulba Sutras, ~800 BCE) used the theorem for constructing fire altars with precise right angles.
  • Pythagoras of Samos (~570–495 BCE) is traditionally credited with the first formal proof.
  • Over 400 distinct proofs of the theorem exist, including proofs by US President James Garfield and Leonardo da Vinci.


Further applications of the altitude-on-hypotenuse construction:

  • Spiral of Theodorus: A geometric construction that uses repeated right triangles to represent square roots of successive natural numbers. Each new triangle shares the hypotenuse of the previous one as a leg, creating a spiral pattern.
  • Golden ratio: The Pythagoras Theorem is used in deriving the golden ratio through the diagonal of a regular pentagon, which involves right triangles with specific proportions.
  • Three-dimensional geometry: The 3D distance formula d = sqrt(dx^2 + dy^2 + dz^2) is derived by applying Pythagoras Theorem twice — once in the horizontal plane and once vertically.

Key Points to Remember

  • Pythagoras Theorem: In a right triangle, hypotenuse² = sum of squares of the other two sides.
  • The theorem applies ONLY to right-angled triangles.
  • The hypotenuse is always the longest side, opposite the right angle.
  • The NCERT proof uses similar triangles created by dropping an altitude from the right angle to the hypotenuse.
  • The altitude creates three similar triangles (two small + the original).
  • Converse: If c² = a² + b², the triangle is right-angled at the vertex opposite c.
  • Classification: c² = a² + b² (right), c² > a² + b² (obtuse), c² < a² + b² (acute).
  • Common Pythagorean triplets: 3-4-5, 5-12-13, 8-15-17, 7-24-25.
  • In CBSE exams, the proof carries 4–5 marks. Memorize the construction and the two pairs of similar triangles.
  • The distance formula in coordinate geometry is a direct application of this theorem.

Practice Problems

  1. A right triangle has legs 9 cm and 40 cm. Find the hypotenuse.
  2. The hypotenuse of a right triangle is 17 cm and one leg is 8 cm. Find the other leg.
  3. Check whether a triangle with sides 11 cm, 60 cm, and 61 cm is right-angled.
  4. A ladder 15 m long leans against a wall. If the foot is 9 m from the wall, how high up the wall does it reach?
  5. Find the length of the diagonal of a square with side 7 cm.
  6. Prove that in an isosceles right triangle with legs a, the hypotenuse is a√2.
  7. The diagonals of a rhombus are 24 cm and 10 cm. Find the perimeter of the rhombus.
  8. In triangle ABC, angle C = 90°, CD is perpendicular to AB. Prove that BC² = BD × BA.

Frequently Asked Questions

Q1. What does the Pythagoras Theorem state?

In a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) equals the sum of the squares of the other two sides: c² = a² + b².

Q2. How is the Pythagoras Theorem proved in Class 10?

By drawing the altitude from the right-angle vertex to the hypotenuse. This creates two smaller triangles, each similar to the original (by AA similarity). Using corresponding sides of similar triangles gives AB² = AD × AC and BC² = DC × AC. Adding these gives AC² = AB² + BC².

Q3. What is the converse of the Pythagoras Theorem?

If in a triangle, the square of one side equals the sum of squares of the other two, then the angle opposite that side is 90°. Use this to check whether a triangle is right-angled.

Q4. What are Pythagorean triplets?

A Pythagorean triplet is a set of three positive integers (a, b, c) such that a² + b² = c². Common triplets: 3-4-5, 5-12-13, 8-15-17, 7-24-25. Any multiple of a triplet is also a triplet.

Q5. Does the Pythagoras Theorem work for all triangles?

No. It works only for RIGHT-ANGLED triangles. For other triangles, you need the cosine rule (studied in Class 11).

Q6. How do I identify the hypotenuse?

The hypotenuse is the side opposite the right angle. It is always the longest side of the right triangle.

Q7. How do I classify a triangle using side lengths?

Let c be the longest side. If c² = a² + b²: right-angled. If c² > a² + b²: obtuse. If c² < a² + b²: acute.

Q8. Is the proof of Pythagoras Theorem important for CBSE exams?

Yes. The proof is a frequently asked question carrying 4–5 marks. Memorize the construction (altitude BD to hypotenuse AC) and the two AA similarity arguments.

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