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Difference of Squares - Applications

Class 8Algebraic Expressions and Identities

The difference of two squares identity is one of the most useful algebraic identities for mental maths and simplification. It states that a² − b² = (a + b)(a − b).



This identity allows us to quickly compute products like 53 × 47, 102 × 98, or 997 × 1003 without long multiplication. It also helps in factorising expressions and simplifying calculations in geometry and physics.



In this topic, we focus on practical applications of the a² − b² identity — mental arithmetic tricks, algebraic simplification, and real-world problem solving.

What is Difference of Squares - Applications?

Definition: The difference of two squares identity states:

a² − b² = (a + b)(a − b)


This means:

  • The difference of two perfect squares can always be written as a product of two factors.
  • The factors are the sum and difference of the two numbers.
  • Conversely, a product of the form (a + b)(a − b) always equals a² − b².

Difference of Squares - Applications Formula

Key Formulas:

a² − b² = (a + b)(a − b)


Applications for mental maths:

  • To find : Write n as (a + b) or (a − b) where a is a round number. Then n² = a² ± 2ab + b², or use the difference of squares.
  • To multiply (a + b)(a − b): The answer is simply a² − b².
  • To compute 97²: Write as (100 − 3)² = 10000 − 600 + 9 = 9409. Alternatively, 97² = 100² − 3² − 2(3)(100 − 97) ... but the direct (a−b)² method is cleaner.

Derivation and Proof

Why does a² − b² = (a + b)(a − b)?

  1. Start with the right side: (a + b)(a − b).
  2. Expand using distribution (FOIL):
    (a + b)(a − b) = a·a − a·b + b·a − b·b
  3. Simplify: = a² − ab + ab − b²
  4. The middle terms cancel: = a² − b²
  5. This proves the identity.

Geometric interpretation:

  • A square of side a has area a².
  • Remove a smaller square of side b from one corner. The remaining area is a² − b².
  • This L-shaped region can be rearranged into a rectangle of dimensions (a + b) × (a − b).

Types and Properties

Types of applications:

  • Type 1 — Quick multiplication: Products like 52 × 48 = (50 + 2)(50 − 2) = 50² − 2² = 2500 − 4 = 2496.
  • Type 2 — Finding squares mentally: 99² = (100 − 1)(100 + 1) + 1 = 10000 − 1 = 9999? No — 99² = (100)² − 2(100)(1) + 1² = 9801. Use (a−b)² for squaring.
  • Type 3 — Factorising expressions: 4x² − 9 = (2x)² − 3² = (2x + 3)(2x − 3).
  • Type 4 — Simplifying fractions: (x² − 25)/(x + 5) = (x+5)(x−5)/(x+5) = x − 5.
  • Type 5 — Number theory: The difference of squares of two consecutive numbers: n² − (n−1)² = 2n − 1 (always odd).

Solved Examples

Example 1: Example 1: Quick multiplication using identity

Problem: Find 53 × 47 without long multiplication.


Solution:

Observation: 53 = 50 + 3 and 47 = 50 − 3.

  • 53 × 47 = (50 + 3)(50 − 3)
  • = 50² − 3²
  • = 2500 − 9
  • = 2491

Answer: 53 × 47 = 2491.

Example 2: Example 2: Product of numbers equidistant from 100

Problem: Find 102 × 98.


Solution:

Observation: 102 = 100 + 2 and 98 = 100 − 2.

  • 102 × 98 = (100 + 2)(100 − 2)
  • = 100² − 2²
  • = 10000 − 4
  • = 9996

Answer: 102 × 98 = 9996.

Example 3: Example 3: Large number multiplication

Problem: Find 997 × 1003.


Solution:

Observation: 997 = 1000 − 3 and 1003 = 1000 + 3.

  • 997 × 1003 = (1000 − 3)(1000 + 3)
  • = 1000² − 3²
  • = 1000000 − 9
  • = 999991

Answer: 997 × 1003 = 999991.

Example 4: Example 4: Evaluating 78² − 22²

Problem: Evaluate 78² − 22².


Solution:

Using a² − b² = (a + b)(a − b):

  • 78² − 22² = (78 + 22)(78 − 22)
  • = 100 × 56
  • = 5600

Answer: 78² − 22² = 5600.

Example 5: Example 5: Factorising an algebraic expression

Problem: Factorise 9x² − 16y².


Solution:

  • 9x² = (3x)² and 16y² = (4y)²
  • 9x² − 16y² = (3x)² − (4y)²
  • = (3x + 4y)(3x − 4y)

Answer: 9x² − 16y² = (3x + 4y)(3x − 4y).

Example 6: Example 6: Simplifying a fraction

Problem: Simplify (x² − 49)/(x − 7).


Solution:

  • x² − 49 = x² − 7² = (x + 7)(x − 7)
  • (x² − 49)/(x − 7) = (x + 7)(x − 7)/(x − 7)
  • = x + 7 (for x ≠ 7)

Answer: (x² − 49)/(x − 7) = x + 7.

Example 7: Example 7: Finding a number

Problem: The difference of squares of two numbers is 80. If the larger number is 9, find the smaller.


Solution:

Given: a² − b² = 80, a = 9.

  • 81 − b² = 80
  • b² = 81 − 80 = 1
  • b = 1

Answer: The smaller number is 1.

Example 8: Example 8: Consecutive numbers

Problem: Prove that the difference of squares of two consecutive numbers is always odd.


Solution:

Let the consecutive numbers be n and n + 1.

  • (n + 1)² − n² = (n + 1 + n)(n + 1 − n)
  • = (2n + 1)(1)
  • = 2n + 1

Since 2n + 1 is always odd (one more than an even number), the difference is always odd.

Answer: Proved. The difference equals 2n + 1, which is always odd.

Example 9: Example 9: Multi-step calculation

Problem: Evaluate 105² − 95².


Solution:

  • 105² − 95² = (105 + 95)(105 − 95)
  • = 200 × 10
  • = 2000

Answer: 105² − 95² = 2000.

Example 10: Example 10: Application in geometry

Problem: A square garden has side 25 m. A path of width 5 m runs along two adjacent sides (outside). Find the area of the path using the identity.


Solution:

Given: Inner square side = 25 m, path width = 5 m.

  • The outer region along two sides can be computed as difference of areas.
  • Total outer area (one L-strip): 30 × 30 − 25 × 25 = (30 + 25)(30 − 25) = 55 × 5 = 275 m²

Wait — this gives the area of the border on ALL sides. For two sides only, a different approach is needed. Let us reconsider:

  • Area of full outer square = 30² = 900 m²
  • Area of inner square = 25² = 625 m²
  • Area of border (all 4 sides) = 900 − 625 = 275 m²
  • Using identity: 30² − 25² = (30+25)(30−25) = 55 × 5 = 275 m²

Answer: Area of the border = 275 m².

Real-World Applications

Real-world applications:

  • Mental arithmetic: Quickly multiply numbers that are equidistant from a round number (e.g., 48 × 52, 97 × 103).
  • Factorisation: Factorise algebraic expressions of the form a² − b².
  • Simplification: Cancel common factors in fractions involving differences of squares.
  • Geometry: Calculate areas of annular (ring-shaped) regions: π(R² − r²) = π(R+r)(R−r).
  • Number patterns: Prove properties of odd and even numbers.
  • Physics: Kinetic energy differences, lens equations, and other formulas involve a² − b².

Key Points to Remember

  • a² − b² = (a + b)(a − b) — learn this identity thoroughly.
  • Use it for quick multiplication of numbers equidistant from a round number.
  • The difference of squares of consecutive integers is always odd: (n+1)² − n² = 2n + 1.
  • To evaluate expressions like 78² − 22², factorise first — it is much faster than squaring both numbers.
  • The identity also works for algebraic expressions: 4x² − 9 = (2x+3)(2x−3).
  • The geometric interpretation: removing a square from a square gives an L-shape that can be reshaped into a rectangle.
  • Ring area = π(R² − r²) = π(R + r)(R − r).
  • Always check if an expression is a difference of perfect squares before attempting to factorise.

Practice Problems

  1. Evaluate 73 × 67 using the difference of squares identity.
  2. Evaluate 201 × 199.
  3. Find 85² − 15².
  4. Factorise: 25a² − 36b².
  5. Simplify: (4x² − 1)/(2x + 1).
  6. The product of two numbers is 2491 and their sum is 100. Find the numbers.
  7. Prove that the difference of squares of any two odd numbers is divisible by 8.
  8. Evaluate: 10.5² − 9.5².

Frequently Asked Questions

Q1. What is the difference of two squares identity?

a² − b² = (a + b)(a − b). The difference of two squares equals the product of their sum and their difference.

Q2. How is this useful for mental maths?

When multiplying two numbers equidistant from a round number (like 48 × 52 = 50² − 2² = 2496), you avoid long multiplication entirely.

Q3. Does this identity work for non-integers?

Yes. It works for all real numbers, including decimals and fractions. For example, (3.5)² − (1.5)² = (3.5 + 1.5)(3.5 − 1.5) = 5 × 2 = 10.

Q4. Can a sum of two squares be factorised similarly?

No. a² + b² cannot be factorised into real linear factors. Only the DIFFERENCE of two squares can be factorised as (a+b)(a−b).

Q5. What if b > a in a² − b²?

Then a² − b² is negative. The identity still holds: a² − b² = (a+b)(a−b), which will be negative since (a−b) < 0.

Q6. How is this related to factorisation?

When you see an expression like 16x² − 25, recognise it as (4x)² − 5² and factorise as (4x + 5)(4x − 5). This is a key factorisation technique.

Q7. What is the geometric meaning?

If you cut a b × b square from a corner of an a × a square, the remaining L-shaped area (a² − b²) can be rearranged into a rectangle of dimensions (a + b) by (a − b).

Q8. Why is the difference of consecutive squares always odd?

(n+1)² − n² = (n+1+n)(n+1−n) = (2n+1)(1) = 2n+1, which is always odd.

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