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Squares of Numbers

Class 8Squares and Square Roots

The square of a number is the result of multiplying a number by itself. If n is a number, then n × n = n² is called the square of n.


Squares are one of the most fundamental operations in mathematics. They appear in area calculations, the Pythagoras theorem, algebraic identities, and physics formulas.


A perfect square is a number that is the square of a whole number. For example, 1, 4, 9, 16, 25, 36, ... are perfect squares because they equal 1², 2², 3², 4², 5², 6², ... respectively.

What is Squares of Numbers?

Definition: The square of a number n is the product of the number multiplied by itself.


n² = n × n


Where:

  • n is any number (integer, fraction, or decimal)
  • is read as "n squared" or "n to the power 2"
  • The result is always non-negative (≥ 0)

Definition: A perfect square (or square number) is a natural number that can be expressed as the square of a natural number.

  • The first 20 perfect squares: 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, 289, 324, 361, 400

Methods

Methods for finding squares:


Method 1: Direct Multiplication

  • Simply multiply the number by itself.
  • Example: 13² = 13 × 13 = 169

Method 2: Using the identity (a + b)² = a² + 2ab + b²

  1. Split the number into two parts: a + b.
  2. Apply the identity.
  3. Example: 23² = (20 + 3)² = 400 + 120 + 9 = 529

Method 3: Using the pattern for numbers ending in 5

  1. For a number like n5 (e.g., 25, 35, 45):
  2. Multiply n by (n + 1). Write the result.
  3. Append 25 at the end.
  4. Example: 35² → 3 × 4 = 12, append 25 → 1225

Method 4: Using consecutive square difference

  • n² = (n − 1)² + (n − 1) + n
  • Or equivalently: n² − (n − 1)² = 2n − 1
  • This means the difference between consecutive perfect squares is always an odd number.

Solved Examples

Example 1: Example 1: Square of a two-digit number

Problem: Find 14².


Solution:

Using direct multiplication:

  • 14² = 14 × 14
  • = 14 × 10 + 14 × 4
  • = 140 + 56
  • = 196

Answer: 14² = 196

Example 2: Example 2: Using (a + b)² identity

Problem: Find 27² using the algebraic identity.


Solution:

Given:

  • 27 = 20 + 7, so a = 20, b = 7

Using (a + b)² = a² + 2ab + b²:

  • = 20² + 2(20)(7) + 7²
  • = 400 + 280 + 49
  • = 729

Answer: 27² = 729

Example 3: Example 3: Number ending in 5

Problem: Find 45² using the shortcut for numbers ending in 5.


Solution:

Steps:

  • Number = 45. The digit before 5 is 4.
  • Multiply 4 by (4 + 1) = 4 × 5 = 20
  • Append 25: 2025

Check: 45 × 45 = 2025. Correct.

Answer: 45² = 2025

Example 4: Example 4: Square of a negative number

Problem: Find (−8)².


Solution:

Steps:

  • (−8)² = (−8) × (−8)
  • Negative × Negative = Positive
  • = 64

Important: (−8)² = 64, but −8² = −(8²) = −64. The parentheses matter!

Answer: (−8)² = 64

Example 5: Example 5: Is 2025 a perfect square?

Problem: Check whether 2025 is a perfect square.


Solution:

Steps:

  • Find the prime factorisation: 2025 = 3 × 675 = 3 × 3 × 225 = 3² × 225
  • 225 = 15² = (3 × 5)² = 3² × 5²
  • So 2025 = 3² × 3² × 5² = 3⁴ × 5²
  • All prime factors have even powers
  • √2025 = 3² × 5 = 9 × 5 = 45

Answer: Yes, 2025 is a perfect square. 2025 = 45².

Example 6: Example 6: Sum of first n odd numbers

Problem: Find the sum: 1 + 3 + 5 + 7 + 9 + 11.


Solution:

Using the property: Sum of first n odd numbers = n²

  • Count the terms: there are 6 odd numbers
  • Sum = 6² = 36

Check: 1 + 3 + 5 + 7 + 9 + 11 = 36. Correct.

Answer: Sum = 36

Example 7: Example 7: Square of a fraction

Problem: Find (3/4)².


Solution:

Steps:

  • (3/4)² = 3²/4²
  • = 9/16

Answer: (3/4)² = 9/16

Example 8: Example 8: Square of a decimal

Problem: Find (0.6)².


Solution:

Steps:

  • (0.6)² = 0.6 × 0.6
  • = 0.36

Alternatively: 0.6 = 6/10, so (6/10)² = 36/100 = 0.36

Answer: (0.6)² = 0.36

Example 9: Example 9: Using difference of consecutive squares

Problem: Given that 30² = 900, find 31² without multiplying.


Solution:

Using the property: n² = (n − 1)² + 2n − 1

  • 31² = 30² + 2(31) − 1
  • = 900 + 62 − 1
  • = 900 + 61
  • = 961

Check: 31 × 31 = 961. Correct.

Answer: 31² = 961

Example 10: Example 10: Can a number ending in 7 be a perfect square?

Problem: Without calculating, determine whether 4587 can be a perfect square.


Solution:

Steps:

  • The number 4587 ends in 7.
  • A perfect square can only end in 0, 1, 4, 5, 6, or 9.
  • Since 4587 ends in 7, it cannot be a perfect square.

Answer: No, 4587 is not a perfect square.

Real-World Applications

Real-world applications of squares:

  • Area calculation: Area of a square with side a = a². A square room of side 5 m has area 25 m².
  • Pythagoras theorem: In a right triangle, c² = a² + b². Finding distances uses squares.
  • Physics: Kinetic energy = ½mv². The square of velocity determines energy.
  • Statistics: Standard deviation uses squares of deviations from the mean.
  • Computer science: Checking if a number is a perfect square is a common algorithmic problem.
  • Finance: Compound interest formulas involve squaring the growth factor for 2 years.

Key Points to Remember

  • The square of n is n² = n × n.
  • The square of any number is always non-negative (≥ 0).
  • (−n)² = n². Squaring a negative gives a positive.
  • Perfect squares end in 0, 1, 4, 5, 6, or 9 only. Never in 2, 3, 7, or 8.
  • Square of even number = even. Square of odd number = odd.
  • Difference of consecutive squares: n² − (n−1)² = 2n − 1.
  • Sum of first n odd numbers = .
  • For numbers ending in 5: (n5)² = n(n+1) followed by 25.
  • A perfect square has an odd number of factors.
  • In the prime factorisation of a perfect square, every prime factor appears an even number of times.

Practice Problems

  1. Find 18².
  2. Find 65² using the shortcut for numbers ending in 5.
  3. Using the identity (a + b)², find 32².
  4. Is 1764 a perfect square? If yes, find its square root.
  5. Without calculating, determine if 3378 can be a perfect square.
  6. Find the sum: 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15.
  7. Given 25² = 625, find 26² without multiplying.
  8. Find (−12)² and (−0.7)².

Frequently Asked Questions

Q1. What is the square of a number?

The square of a number n is the product n × n, written as n². For example, the square of 7 is 7² = 49.

Q2. What is a perfect square?

A perfect square is a natural number that equals the square of some natural number. Examples: 1, 4, 9, 16, 25, 36, 49, 64, 81, 100.

Q3. Can a negative number be a perfect square?

No. Since squaring any real number gives a non-negative result, perfect squares are always ≥ 0. A number like −4 is not a perfect square.

Q4. What is the difference between (−5)² and −5²?

(−5)² = (−5) × (−5) = 25 (the square of negative 5). But −5² = −(5²) = −25 (the negative of 5 squared). The parentheses make a crucial difference.

Q5. How can you tell if a number is NOT a perfect square without calculating?

Check the last digit. If a number ends in 2, 3, 7, or 8, it is NOT a perfect square. Perfect squares can only end in 0, 1, 4, 5, 6, or 9.

Q6. What is the shortcut for squaring numbers ending in 5?

For a number like n5: multiply n by (n + 1) and append 25. Example: 75² → 7 × 8 = 56, append 25 → 5625.

Q7. Why is the sum of first n odd numbers equal to n²?

This can be visualised with dots arranged in an L-shape pattern. Each successive odd number adds another L-shaped layer to a square arrangement, making the total a perfect square.

Q8. How do you square a fraction?

Square the numerator and denominator separately: (a/b)² = a²/b². For example, (2/3)² = 4/9.

Q9. What is the relationship between consecutive squares?

The difference between n² and (n−1)² is always 2n − 1 (an odd number). For example, 10² − 9² = 100 − 81 = 19 = 2(10) − 1.

Q10. How many perfect squares are there between 1 and 100?

There are 10 perfect squares between 1 and 100 (inclusive): 1, 4, 9, 16, 25, 36, 49, 64, 81, 100. These are 1² through 10².

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