Chapter 14: Probability Notes for Class 10 gives you a clear, NCERT-aligned guide to the basic principles and calculations of probability commonly tested in CBSE exams. Learn definitions and notation for experiments, outcomes, sample space, and events, plus the formal definition of probability and methods to compute probabilities for simple, complementary, mutually exclusive, and independent events. It includes step-by-step worked examples, shortcut tips for quick computation, revision bullets, practice problems with answers, and common mistake alerts to build confidence and strong conceptual understanding for exam success.
Definition: The theoretical probability of an event E is:
P(E) = Number of outcomes favourable to E / Number of all possible outcomes
This formula assumes all outcomes are equally likely.
Experimental vs Theoretical Probability
As the number of trials increases, experimental probability gets closer and closer to theoretical probability.
Sum of Elementary Events
The sum of probabilities of all elementary events of an experiment always equals 1.
Example: For a die: P(1) + P(2) + P(3) + P(4) + P(5) + P(6) = 1/6 × 6 = 1
Impossible Event: P(E) = 0
e.g., rolling 8 on a die
Sure/Certain Event: P(E) = 1
e.g., rolling <7 on a die
For any event E: 0 ≤ P(E) ≤ 1
Complementary Event (Not E): P(Ē) = 1 − P(E)
If event E is ‘getting a head’, then Ē (complement, read as ‘E-bar’) is ‘not getting a head’ = ‘getting a tail’. They are complementary because together the events cover all possibilities.
Complementary Events Formula
P(E) + P(Ē) = 1 ⟹ P(Ē) = 1 − P(E)
For two coins, the possible outcomes are:
Total Outcomes = 4
Therefore, when two coins are tossed together, the sample space is:
S = {HH,HT,TH,TT}
Examples:
1. Probability of getting two heads
Favourable outcome = {HH}
P(Two Heads) = 1/4
2. Probability of getting two tails
Favourable outcome = {TT}
P(Two Tails) = 1/4
3. Probability of getting one head and one tail
Favourable outcomes = {HT, TH}
P(One Head and One Tail) = 2/4 = ½
where n = number of coins.
When two dice are thrown, the total number of outcomes = 6 × 6 = 36. Each ordered pair (a, b) represents a unique outcome where a ≠ b position-wise, so (1, 4) ≠ (4, 1).
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A standard deck has 52 cards.
♠ Spades
Black - 13 cards
♥ Hearts
Red - 13 cards
♦ Diamonds
Red - 13 cards
♣ Clubs
Black - 13 cards
Question 1: A bag contains 6 red, 4 white and 8 blue balls. A ball is drawn at random. Find the probability that the ball drawn is (i) blue, (ii) not red.
Solution: Total = 18
Blue balls = 8
Red balls = 6
White balls = 4
(i) P(blue) = 8/18 = 4/9
(ii) P(not red) = 12/18 = 2/3
Question 2: Cards marked 2 to 101 are placed in a box and one is drawn at random. Find the probability that the number on the card is (i) a perfect square, (ii) divisible by 7.
Solution: Total = 100
(i) Perfect squares: 4, 9, 16, 25, 36, 49, 64, 81 and 100
There are 9 perfect squares
P(a perfect square) = 9/100
(ii) Divisible by 7 (7, 14, ... 98)
There are 14 numbers divisible by 7
P(divisible by 7) = 14/100 = 7/50
Question 3: A die is thrown twice. What is the probability that (i) 5 will not come up either time? (ii) 5 will come up at least once?
Solution: Total = 36
Outcomes where 5 appears: (5,1), (5,2)...(5,6), (1,5)...(6,5) minus double-count Therefore 11 outcomes
(i) P(5 not at all) = 25/36
(ii) P(5 at least once) = 11/36
Question 4: A number x is selected at random from the numbers 1, 2, 3 and 4. Another number y is selected at random from 1, 2, 3 and 4. Find the probability that the product of x and y is less than 9.
Solution: Total pairs = 16
Products ≥ 9: (3,3)=9, (3,4)=12, (4,3)=12, (4,4)=16
Total 4 favourable outcomes
P(xy < 9) = 12/16 = 3/4
Click below to download your free Class 10 Maths Chapter 14: Probability PDF Notes perfect for last-minute CBSE board exam revision.
Two events E and Ē are complementary if they are the only two possible outcomes and exactly one of them must occur. The key property is P(E) + P(Ē) = 1, which gives P(Ē) = 1 − P(E).
When two dice are thrown simultaneously, the total number of equally likely outcomes is 6 × 6 = 36. Each outcome is an ordered pair (a, b) where a is the result of the first die and b of the second.
A standard deck has 12 face cards: King, Queen, and Jack of each of the 4 suits (spades, hearts, diamonds, and clubs). The 4 suits give 3 × 4 = 12 face cards total.
The probability of an impossible event is 0, for example, rolling a 7 on a standard 6-faced die. The probability of a sure (certain) event is 1, for example, rolling a number less than 7 on a standard die.
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