Fractions in Disguise for Class 8: Important Questions and Answers are available in this Maths article. Fractions in Disguise for Class 8: Important Questions and Answers are very useful to solve problems easily. This article helps the students to know the key questions and answers about Fractions in Disguise. Our subject experts have provided detailed solutions for these problems based on the CBSE syllabus and the NCERT textbook. This material helps students revise the chapter easily and perform well in the final examination.
Fractions in Disguise means representing fractions in different forms while keeping the same value. The same fraction can be written as a common fraction, a decimal, a percentage, or a ratio. Students need to recognise that 1/2 is the same as 0.5, 50%, and 1:2. Understanding these conversions helps students work with fractions more flexibly and solve problems in different ways.
Question 1: Convert 4/5 into percentage.
Solution
45×100=80
Answer: 80%
Question 2: Convert 3/20 into percentage.
Solution
320×100=15
Answer: 15%
Question 3: Convert 45% into fraction.
Solution
45% = 45100=920
Answer: 9/20
Question 4: Convert 0.75 into percentage.
Solution
0.75×100=75
Answer: 75%
Question 5: Find 20% of 350.
Solution
20100×350=70
Answer: 70
Question 1: Convert 2/25 into decimal and percentage.
Solution
225=0.08=8
Answer: 0.08 and 8%
Question 2: Convert 125% into decimal.
Solution
125% = 125100=1.25
Answer: 1.25
Question 3: Convert 0.4 into fraction.
Solution
0.4=410=25
Answer: 2/5
Question 4: Find 35% of 480.
Solution
35100×480=168
Answer: 168
Question 5: A student scored 36 out of 45 marks. Find the percentage scored.
Solution
3645×100=80
Answer: 80%
Question 1: Out of 200 students, 150 students passed the exam. Find the percentage of students who passed.
Solution
150200×100=75
Answer: 75%
Question 2: Find 15% of 900.
Solution
15100×900=135
Answer: 135
Question 3: A shirt priced at ₹1200 is sold at a discount of 10%. Find the discount amount.
Solution
10100×1200=120
Answer: ₹120
Question 4: Find 60% of 250.
Solution
60100×250=150
Answer: 150
Question 5: The population of a village increased from 4000 to 5000. Find the percentage increase.
Solution
Increase = 1000
10004000×100=25
Answer: 25%
Question 1: A bag costing ₹800 is sold for ₹960. Find the profit percentage.
Solution
Profit = ₹160
160800×100=20
Answer: 20%
Question 2: A toy costing ₹500 is sold for ₹450. Find the loss percentage.
Solution
Loss = ₹50
50500×100=10
Answer: 10%
Question 3: An item marked at ₹2500 is sold for ₹2250. Find the discount percentage.
Solution
Discount = ₹250
2502500×100=10
Answer: 10%
Question 4: A pen costing ₹40 is sold for ₹50. Find the profit percentage.
Solution
Profit = ₹10
1040×100=25
Answer: 25%
Question 5: A bicycle costing ₹6000 is sold for ₹5400. Find the loss percentage.
Solution
Loss = ₹600
6006000×100=10
Answer: 10%
Question 1: 50% as a decimal is:
A) 0.05
B) 0.5
C) 5
D) 50
Solution
50% = 0.5
Answer: B) 0.5
Question 2: The fraction equivalent to 20% is:
A) 1/2
B) 1/4
C) 1/5
D) 2/5
Solution
20% = 20100=15
Answer: C) 1/5
Question 3: Find 25% of 200.
A) 25
B) 40
C) 50
D) 75
Solution
25100×200=50
Answer: C) 50
Question 4: 0.9 as a percentage is:
A) 9%
B) 90%
C) 0.9%
D) 900%
Solution
0.9×100=90
Answer: B) 90%
Question 5: A shopkeeper bought an item for ₹1000 and sold it for ₹1200. The profit percentage is:
A) 10%
B) 15%
C) 20%
D) 25%
Solution
Profit = ₹200
2001000×100=20
Answer: C) 20%
Question 1: Convert the following fractions into percentages:
(i) 3/4
(ii) 7/20
(iii) 9/25
Solution
(i) 34×100=75
(ii) 720×100=35
(iii) 925×100=36
Answers
(i) 75%
(ii) 35%
(iii) 36%
Question 2: Convert the following decimals into percentages:
(i) 0.35
(ii) 1.25
(iii) 0.08
Solution
(i) 0.35×100=35
(ii) 1.25×100=125
(iii) 0.08×100=8
Answers
(i) 35%
(ii) 125%
(iii) 8%
Question 3: Convert 45% into fraction in simplest form.
Solution: 45% = 45100=920
Answer: 9/20
Question 4: Find 25% of 480.
Solution
25100×480=120
Answer: 120
Question 5: A student scored 63 marks out of 84. Find the percentage obtained.
Solution
6384×100=75
Answer: 75%
Question 6: Out of 160 students, 120 students passed the examination. Find the percentage of students who passed.
Solution
120160×100=75
Answer: 75%
Question 7: A shopkeeper bought a table for ₹2400 and sold it for ₹3000. Find the profit percentage.
Solution
Profit = ₹600
6002400×100=25
Answer: 25%
Question 8: A bicycle costing ₹5000 was sold for ₹4500. Find the loss percentage.
Solution
Loss = ₹500
5005000×100=10
Answer: 10%
Question 9: An item marked at ₹4000 is sold at a discount of 15%. Find the discount amount.
Solution
15100×4000=600
Answer: ₹600
Question 10: Find the simple interest on ₹8000 at 5% per annum for 3 years.
Solution
SI=8000×5×3100=1200
Answer: ₹1200
Question 11: Calculate the amount on ₹5000 compounded annually at 10% for 2 years.
Solution
A=5000(1+10100)2
A=5000(1.1)2=6050
Answer: ₹6050
Question 12: Find 12.5% of 640.
Solution
12.5100×640=80
Answer: 80
Question 13: A shirt marked at ₹2500 is sold for ₹2250. Find the discount percentage.
Solution
Discount = ₹250
2502500×100=10
Answer: 10%
Question 14: The population of a city increased from 50,000 to 60,000. Find the percentage increase.
Solution
Increase = 10,000
1000050000×100=20
Answer: 20%
Question 15: A number is increased by 25% and then decreased by 25%. Find the final percentage change.
Solution
Assume the number is 100.
Increase by 25%:
100 + 25 = 125
Decrease 25% of 125:
125−25100×125=93.75
Answer: There is a 6.25% decrease overall.
“Fractions in Disguise” refers to algebraic fractions where variables and algebraic expressions are written in fraction form.
Factorise the numerator and denominator, then cancel common factors.
Example: 6x12=x2
Fractions are written in the form: pq
while decimals are written using decimal points.
Example: 12=0.5
Multiply the fraction by: 100%.
Percentage means “per hundred.”
Example: 25%=25100
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